Chapter 8, Problem 27P

Using the simply supported beam from Prob. 8.24, the displacement along the beam is given by:

$\begin{array}{l}{u}_y\left(x\right)=\frac{-5}{6}\left[{\langle x-0\rangle }^4-{\langle x-5\rangle }^4\right]+\frac{15}{6}{\langle x-8\rangle }^3\\ +75{\langle x-7\rangle }^2+\frac{57}{6}{x}^3-238.25x\end{array}$

(a) Find the point(s) where the displacement equals zero.

(b) How would you use a root location technique to determine the location of the minimum displacement?