A simply supported beam is loaded as shown in Fig. P8.24. Using singularity functions, the shear along the beam can be expressed by the equation: V ( x ) = 20 [ 〈 x − 0 〉 1 − 〈 x − 5 〉 1 ] − 15 〈 x − 8 〉 0 − 57 By definition, the singularity function can be expressed as follows: 〈 x − a 〉 n = { ( x − a ) n when x > a 0 when x ≤ a } Use a numerical method to find the point(s) where the shear equals zero. FIGURE P8.24
A simply supported beam is loaded as shown in Fig. P8.24. Using singularity functions, the shear along the beam can be expressed by the equation: V ( x ) = 20 [ 〈 x − 0 〉 1 − 〈 x − 5 〉 1 ] − 15 〈 x − 8 〉 0 − 57 By definition, the singularity function can be expressed as follows: 〈 x − a 〉 n = { ( x − a ) n when x > a 0 when x ≤ a } Use a numerical method to find the point(s) where the shear equals zero. FIGURE P8.24
The entire graph of the function g is shown in the figure below.
Write the domain and range of g as intervals or unions of intervals.
5
4
-3.
2
3
omain =
range ☐
=
Can you prove this integral equation?Note: It also has an application to prove that 22/7 > π.
1.
The number of claims is modelled by a NB2(n, p) (the number of fail-
ures before the nth success with probability p of success). The sample x =
(x1, x2,,XN) with N = 100 returns
N
N
xj =
754,
Σε = 70425.
j=1
Estimate the parameters n and p using the point estimates.
[5 Marks]
Elementary Statistics Using The Ti-83/84 Plus Calculator, Books A La Carte Edition (5th Edition)
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