Figure P8.18 a shows a uniform beam subject to a linearly increasing distributed load. The equation for the resulting elastic curve is (see Fig. P8.18 b ) y = w 0 120 E I L ( − x 5 + 2 L 2 x 3 − L 4 x ) ( P8 .18 .1 ) Use bisection to determine the point of maximum deflection (that is, the value of x where d y / d x = 0 ). Then substitute this value into Eq. ( P8 .18 .1 ) to determine the value of the maximum deflection. Use the following parameter values in your computation: L = 450 cm, E = 50 , 000 kN / cm 2 , I = 30 , 000 cm 4 , and w 0 = 1.75 kN / cm . FIGURE P8.18
Figure P8.18 a shows a uniform beam subject to a linearly increasing distributed load. The equation for the resulting elastic curve is (see Fig. P8.18 b ) y = w 0 120 E I L ( − x 5 + 2 L 2 x 3 − L 4 x ) ( P8 .18 .1 ) Use bisection to determine the point of maximum deflection (that is, the value of x where d y / d x = 0 ). Then substitute this value into Eq. ( P8 .18 .1 ) to determine the value of the maximum deflection. Use the following parameter values in your computation: L = 450 cm, E = 50 , 000 kN / cm 2 , I = 30 , 000 cm 4 , and w 0 = 1.75 kN / cm . FIGURE P8.18
Figure P8.18a shows a uniform beam subject to a linearly increasing distributed load. The equation for the resulting elastic curve is (see Fig. P8.18b)
y
=
w
0
120
E
I
L
(
−
x
5
+
2
L
2
x
3
−
L
4
x
)
(
P8
.18
.1
)
Use bisection to determine the point of maximum deflection (that is, the value of
x
where
d
y
/
d
x
=
0
). Then substitute this value into Eq.
(
P8
.18
.1
)
to determine the value of the maximum deflection. Use the following parameter values in your computation:
L
=
450
cm,
E
=
50
,
000
kN
/
cm
2
,
I
=
30
,
000
cm
4
,
and
w
0
=
1.75
kN
/
cm
.
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