Chapter 8, Problem 1P

To determine

The total number of peak hour trips.

Answer to Problem 1P

The total number of peak hour trips by shopping activity and social or recreational activity are $544\text{trips}$ and $921.6\text{trips}$ respectively.

Explanation of Solution

Given:

The total retail employment is $120$ .

The number total households in the village is $1600$ .

The number of non-working family members in each household is $2$ .

The household income is $\$20,000$ .

Formula Used:

Write the expression for total number of peak hour trip by shopping trip generation.

  $\left\{\begin{array}{l}\text{Number}\text{of}\\ \text{peak}\text{hour}\\ \text{vehicle}\text{trip}\end{array}\right\}=\left[\begin{array}{l}0.12+0.09\left(\text{household}\text{size}\right)\\ +0.011\left(\begin{array}{l}\text{annual}\text{household}\\ \text{income}\text{in}\text{thousand}\text{of}\text{dollars}\end{array}\right)\\ -0.15\left(\begin{array}{l}\text{employment}\text{in}\text{the}\\ \text{household's}\text{neighborhood}\\ \text{,}\text{in}\text{hundreds}\end{array}\right)\end{array}\right]\times \left(\begin{array}{l}\text{total}\\ \text{households}\end{array}\right)$ ...............(I)

Write the expression for total number of peak hour trip by social and recreational activity.

  $\left\{\begin{array}{l}\text{Number}\text{of}\\ \text{peak}\text{hour}\\ \text{vehicle}\text{trip}\end{array}\right\}=\left[\begin{array}{l}0.04+0.018\left(\text{household}\text{size}\right)\\ +0.009\left(\begin{array}{l}\text{annual}\text{household}\\ \text{income}\text{in}\text{thousand}\text{of}\text{dollars}\end{array}\right)\\ +0.16\left(\begin{array}{l}\text{number}\text{of}\text{nonworking}\\ \text{household}\text{members}\end{array}\right)\end{array}\right]\times \left(\begin{array}{l}\text{total}\\ \text{households}\end{array}\right)$ ...............(II)

Calculation:

Substitute $2$ for $\text{household}\text{size}$ , $20$ for $\text{annual}\text{household}\text{income}\text{in}\text{thousand}\text{of}\text{dollars}$ , $1.20$ for $\text{employment}\text{in}\text{the}\text{household's}\text{neighborhood,}\text{in}\text{hundreds}$ and $1600$ for $\text{total}\text{households}$ in equation (I).

  $\begin{array}{c}\left\{\begin{array}{l}\text{Number}\text{of}\\ \text{peak}\text{hour}\\ \text{vehicle}\text{trip}\end{array}\right\}=\left[0.12+0.09\left(\text{2}\right)+0.011\left(20\right)-0.15\left(\text{1}\text{.20}\right)\right]\times \left(1600\right)\\ =\left(0.34\right)\left(1600\right)\\ =544\text{trips}\end{array}$

Substitute $2$ for $\text{house}\text{hold}\text{size}$ , $20$ for $\text{annual}\text{household}\text{income}\text{in}\text{thousand}\text{of}\text{dollars}$ , $2$ for $\text{number}\text{of}\text{nonworking}\text{household}\text{members}$ and $1600$ for $\text{total}\text{households}$ in equation (II).

  $\begin{array}{c}\left\{\begin{array}{l}\text{Number}\text{of}\\ \text{peak}\text{hour}\\ \text{vehicle}\text{trip}\end{array}\right\}=\left[0.04+0.018\left(\text{2}\right)+0.009\left(20\right)+0.16\left(\text{2}\right)\right]\times \left(1600\right)\\ =\left(0.576\right)\left(1600\right)\\ =921.6\text{trips}\end{array}$

Conclusion:

Thus, the total number of peak hour trips by shopping activity and social or recreational activity are $544\text{trips}$ and $921.6\text{trips}$ respectively.