BIO Mantis Shrimp Smasher A peacock mantis shrimp smashes its prey with a hammer-like appendage by storing energy in a spring-like section of exoskeleton on its appendage. The spring has a force constant of 5.9 × 10 4 N/m. (a) If the spring stores 0.0103 J of energy, over what distance must the shrimp compress it? (b) What power does the shrimp generate if it unleashes the energy in 0.0018 s? (The power per mass of the shrimp appendage is more than 20 times greater than that generated by muscle alone, showcasing the shrimp’s ability to harness the potential energy of its spring.)
BIO Mantis Shrimp Smasher A peacock mantis shrimp smashes its prey with a hammer-like appendage by storing energy in a spring-like section of exoskeleton on its appendage. The spring has a force constant of 5.9 × 10 4 N/m. (a) If the spring stores 0.0103 J of energy, over what distance must the shrimp compress it? (b) What power does the shrimp generate if it unleashes the energy in 0.0018 s? (The power per mass of the shrimp appendage is more than 20 times greater than that generated by muscle alone, showcasing the shrimp’s ability to harness the potential energy of its spring.)
BIO Mantis Shrimp Smasher A peacock mantis shrimp smashes its prey with a hammer-like appendage by storing energy in a spring-like section of exoskeleton on its appendage. The spring has a force constant of 5.9 × 104N/m. (a) If the spring stores 0.0103 J of energy, over what distance must the shrimp compress it? (b) What power does the shrimp generate if it unleashes the energy in 0.0018 s? (The power per mass of the shrimp appendage is more than 20 times greater than that generated by muscle alone, showcasing the shrimp’s ability to harness the potential energy of its spring.)
SARET CRKS AUTOWAY
12. A stone is dropped from the top of a cliff. It is seen to hit the ground below
after 3.55 s. How high is the cliff?
13. A ball is dropped from rest at the top of a building that is 320 m tall. Assuming
no air resistance, what is the speed of the ball just before it strikes the ground?
14. Estimate (a) how long it took King Kong to fall straight down from the top
of the Empire State Building (280m high), and (b) his velocity just before
"landing".
Useful equations
For Constant Velocity:
V =>
D
X = V₁t + Xo
For Constant Acceleration:
Vr = V + at
X = Xo+Vot +
v=V+2a(X-Xo)
\prom = V +V
V velocity
t = time
D Distance
X = Final Position
Xo Initial Position
V = Final Velocity
Vo Initial Velocity
a = acceleration
For free fall
Yf
= Final Position
Yo Initial Position
g = 9.80
m
$2
For free fall:
V = V + gt
Y=Yo+Vo t +
+gt
V,² = V₁²+2g (Y-Yo)
V+Vo
Vprom=
2
6
Biology: Life on Earth with Physiology (11th Edition)
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Work and Energy - Physics 101 / AP Physics 1 Review with Dianna Cowern; Author: Physics Girl;https://www.youtube.com/watch?v=rKwK06stPS8;License: Standard YouTube License, CC-BY