(a) Interpretation: The number of molecules present in 3.45 g of C 6 H 12 O 6 should be calculated. Concept Introduction: According to Avogadro’s number , one mole of a compound contains 6.023 × 10 23 molecules. Number of moles of a compound is calculated by dividing the given mass of the compound by its molar mass. Moles = M a s s M o l a r M a s s .
(a) Interpretation: The number of molecules present in 3.45 g of C 6 H 12 O 6 should be calculated. Concept Introduction: According to Avogadro’s number , one mole of a compound contains 6.023 × 10 23 molecules. Number of moles of a compound is calculated by dividing the given mass of the compound by its molar mass. Moles = M a s s M o l a r M a s s .
Solution Summary: The author explains how the number of molecules in a compound is calculated by dividing the given mass of the compound by its molar mass.
Definition Definition Number of atoms/molecules present in one mole of any substance. Avogadro's number is a constant. Its value is 6.02214076 × 10 23 per mole.
Chapter 8, Problem 116AP
Interpretation Introduction
(a)
Interpretation:
The number of molecules present in 3.45 g of C6H12O6 should be calculated.
Concept Introduction:
According to Avogadro’s number, one mole of a compound contains 6.023×1023 molecules.
Number of moles of a compound is calculated by dividing the given mass of the compound by its molar mass.
Moles=MassMolarMass.
Interpretation Introduction
(b)
Interpretation:
The number of molecules present in 3.45 moles of C6H12O6 should be calculated.
Concept Introduction:
According to Avogadro’s number, one mole of a compound contains 6.023×1023 molecules.
Interpretation Introduction
(c)
Interpretation:
The number of molecules present in 25 g of ICl5 should be calculated.
Concept Introduction:
According to Avogadro’s number, one mole of a compound contains 6.023×1023 molecules.
Number of moles of a compound is calculated by dividing the given mass of the compound by its molar mass.
Moles=MassMolarMass.
Interpretation Introduction
(d)
Interpretation:
The number of molecules present in 1g of B2H6 should be calculated.
Concept Introduction:
According to Avogadro’s number, one mole of a compound contains 6.023×1023 molecules.
Number of moles of a compound is calculated by dividing the given mass of the compound by its molar mass.
Moles=MassMolarMass.
Interpretation Introduction
(e)
Interpretation:
The number of molecules present in 1.05 mmol of Al(NO3)3 should be calculated.
Concept Introduction:
According to Avogadro’s number, one mole of a compound contains 6.023×1023 molecules.
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Vid4Q2
Unanswered
☑
Provide IUPAC name of product in the reaction
below
A 3,4-dimethylcyclohexene
B 1,2-dimethylcyclohexane
C 1,2-dimethylcyclohexene
D 3,4-dimethylcyclohexane
H₂
Pd
5.
Use the MS data to answer the questions on the next page.
14.0
1.4
15.0
8.1
100-
MS-IW-5644
26.0
2.8
27.0
6.7
28.0
1.8
29.0
80
4.4
38.0
1.0
39.0
1.5
41.0
1.2
42.0
11.2
43.0
100.0
44.0
4.3
79.0
1.9
80.0
2.6
Relative Intensity
40
81.0
1.9
82.0
2.5
93.0
8.7
20-
95.0
8.2
121.0
2.0
123.0
2.0
136.0
11.8
0
138.0
11.5
20
40
8.
60
a.
Br
- 0
80
100
120
140
160
180
200
220
m/z
Identify the m/z of the base peak and molecular ion.
2
b.
Draw structures for each of the following fragments (include electrons and charges): 43.0, 93.0,
95.0, 136.0, and 138.0 m/z.
C.
Draw a reasonable a-fragmentation mechanism for the fragmentation of the molecular ion to
fragment 43.0 m/z. Be sure to include all electrons and formal charges.
6. Using the values provided in Appendix E of your lab manual, calculate the monoisotopic mass for the pyridinium
ion (CsH6N) and show your work.
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Step by Step Stoichiometry Practice Problems | How to Pass ChemistryMole Conversions Made Easy: How to Convert Between Grams and Moles; Author: Ketzbook;https://www.youtube.com/watch?v=b2raanVWU6c;License: Standard YouTube License, CC-BY