(a) Interpretation: The number of molecules present in 3.45 g of C 6 H 12 O 6 should be calculated. Concept Introduction: According to Avogadro’s number , one mole of a compound contains 6.023 × 10 23 molecules. Number of moles of a compound is calculated by dividing the given mass of the compound by its molar mass. Moles = M a s s M o l a r M a s s .

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Answer 1

Question

Chapter 8, Problem 116AP

Interpretation Introduction

(a)

Interpretation:

The number of molecules present in 3.45 g of C6H12O6 should be calculated.

Concept Introduction:

According to Avogadro’s number, one mole of a compound contains 6.023×1023 molecules.

Number of moles of a compound is calculated by dividing the given mass of the compound by its molar mass.

Moles=MassMolarMass.

Interpretation Introduction

(b)

Interpretation:

The number of molecules present in 3.45 moles of C6H12O6 should be calculated.

Concept Introduction:

According to Avogadro’s number, one mole of a compound contains 6.023×1023 molecules.

Interpretation Introduction

(c)

Interpretation:

The number of molecules present in 25 g of ICl5 should be calculated.

Concept Introduction:

According to Avogadro’s number, one mole of a compound contains 6.023×1023 molecules.

Number of moles of a compound is calculated by dividing the given mass of the compound by its molar mass.

Moles=MassMolarMass.

Interpretation Introduction

(d)

Interpretation:

The number of molecules present in 1g of B2H6 should be calculated.

Concept Introduction:

According to Avogadro’s number, one mole of a compound contains 6.023×1023 molecules.

Number of moles of a compound is calculated by dividing the given mass of the compound by its molar mass.

Moles=MassMolarMass.

Interpretation Introduction

(e)

Interpretation:

The number of molecules present in 1.05 mmol of Al(NO3)3 should be calculated.

Concept Introduction:

According to Avogadro’s number, one mole of a compound contains 6.023×1023 molecules.

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Answer 2

Question

Chapter 8, Problem 116AP

Interpretation Introduction

(a)

Interpretation:

The number of molecules present in 3.45 g of C6H12O6 should be calculated.

Concept Introduction:

According to Avogadro’s number, one mole of a compound contains 6.023×1023 molecules.

Number of moles of a compound is calculated by dividing the given mass of the compound by its molar mass.

Moles=MassMolarMass.

Interpretation Introduction

(b)

Interpretation:

The number of molecules present in 3.45 moles of C6H12O6 should be calculated.

Concept Introduction:

According to Avogadro’s number, one mole of a compound contains 6.023×1023 molecules.

Interpretation Introduction

(c)

Interpretation:

The number of molecules present in 25 g of ICl5 should be calculated.

Concept Introduction:

According to Avogadro’s number, one mole of a compound contains 6.023×1023 molecules.

Number of moles of a compound is calculated by dividing the given mass of the compound by its molar mass.

Moles=MassMolarMass.

Interpretation Introduction

(d)

Interpretation:

The number of molecules present in 1g of B2H6 should be calculated.

Concept Introduction:

According to Avogadro’s number, one mole of a compound contains 6.023×1023 molecules.

Number of moles of a compound is calculated by dividing the given mass of the compound by its molar mass.

Moles=MassMolarMass.

Interpretation Introduction

(e)

Interpretation:

The number of molecules present in 1.05 mmol of Al(NO3)3 should be calculated.

Concept Introduction:

According to Avogadro’s number, one mole of a compound contains 6.023×1023 molecules.

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Answer 3

Question

Chapter 8, Problem 116AP

Interpretation Introduction

(a)

Interpretation:

The number of molecules present in 3.45 g of C6H12O6 should be calculated.

Concept Introduction:

According to Avogadro’s number, one mole of a compound contains 6.023×1023 molecules.

Number of moles of a compound is calculated by dividing the given mass of the compound by its molar mass.

Moles=MassMolarMass.

Interpretation Introduction

(b)

Interpretation:

The number of molecules present in 3.45 moles of C6H12O6 should be calculated.

Concept Introduction:

According to Avogadro’s number, one mole of a compound contains 6.023×1023 molecules.

Interpretation Introduction

(c)

Interpretation:

The number of molecules present in 25 g of ICl5 should be calculated.

Concept Introduction:

According to Avogadro’s number, one mole of a compound contains 6.023×1023 molecules.

Number of moles of a compound is calculated by dividing the given mass of the compound by its molar mass.

Moles=MassMolarMass.

Interpretation Introduction

(d)

Interpretation:

The number of molecules present in 1g of B2H6 should be calculated.

Concept Introduction:

According to Avogadro’s number, one mole of a compound contains 6.023×1023 molecules.

Number of moles of a compound is calculated by dividing the given mass of the compound by its molar mass.

Moles=MassMolarMass.

Interpretation Introduction

(e)

Interpretation:

The number of molecules present in 1.05 mmol of Al(NO3)3 should be calculated.

Concept Introduction:

According to Avogadro’s number, one mole of a compound contains 6.023×1023 molecules.

Expert Solution & Answer

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Answer 4

Question

Chapter 8, Problem 116AP

Interpretation Introduction

(a)

Interpretation:

The number of molecules present in 3.45 g of C6H12O6 should be calculated.

Concept Introduction:

According to Avogadro’s number, one mole of a compound contains 6.023×1023 molecules.

Number of moles of a compound is calculated by dividing the given mass of the compound by its molar mass.

Moles=MassMolarMass.

Interpretation Introduction

(b)

Interpretation:

The number of molecules present in 3.45 moles of C6H12O6 should be calculated.

Concept Introduction:

According to Avogadro’s number, one mole of a compound contains 6.023×1023 molecules.

Interpretation Introduction

(c)

Interpretation:

The number of molecules present in 25 g of ICl5 should be calculated.

Concept Introduction:

According to Avogadro’s number, one mole of a compound contains 6.023×1023 molecules.

Number of moles of a compound is calculated by dividing the given mass of the compound by its molar mass.

Moles=MassMolarMass.

Interpretation Introduction

(d)

Interpretation:

The number of molecules present in 1g of B2H6 should be calculated.

Concept Introduction:

According to Avogadro’s number, one mole of a compound contains 6.023×1023 molecules.

Number of moles of a compound is calculated by dividing the given mass of the compound by its molar mass.

Moles=MassMolarMass.

Interpretation Introduction

(e)

Interpretation:

The number of molecules present in 1.05 mmol of Al(NO3)3 should be calculated.

Concept Introduction:

According to Avogadro’s number, one mole of a compound contains 6.023×1023 molecules.

Expert Solution & Answer

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See solution

Answer 5

Chapter 8, Problem 116AP

Interpretation Introduction

(a)

Interpretation:

The number of molecules present in 3.45 g of C6H12O6 should be calculated.

Concept Introduction:

According to Avogadro’s number, one mole of a compound contains 6.023×1023 molecules.

Number of moles of a compound is calculated by dividing the given mass of the compound by its molar mass.

Moles=MassMolarMass.

Interpretation Introduction

(b)

Interpretation:

The number of molecules present in 3.45 moles of C6H12O6 should be calculated.

Concept Introduction:

According to Avogadro’s number, one mole of a compound contains 6.023×1023 molecules.

Interpretation Introduction

(c)

Interpretation:

The number of molecules present in 25 g of ICl5 should be calculated.

Concept Introduction:

According to Avogadro’s number, one mole of a compound contains 6.023×1023 molecules.

Number of moles of a compound is calculated by dividing the given mass of the compound by its molar mass.

Moles=MassMolarMass.

Interpretation Introduction

(d)

Interpretation:

The number of molecules present in 1g of B2H6 should be calculated.

Concept Introduction:

According to Avogadro’s number, one mole of a compound contains 6.023×1023 molecules.

Number of moles of a compound is calculated by dividing the given mass of the compound by its molar mass.

Moles=MassMolarMass.

Interpretation Introduction

(e)

Interpretation:

The number of molecules present in 1.05 mmol of Al(NO3)3 should be calculated.

Concept Introduction:

According to Avogadro’s number, one mole of a compound contains 6.023×1023 molecules.

Answer 6

Chapter 8, Problem 116AP

Interpretation Introduction

(a)

Interpretation:

The number of molecules present in 3.45 g of C6H12O6 should be calculated.

Concept Introduction:

According to Avogadro’s number, one mole of a compound contains 6.023×1023 molecules.

Number of moles of a compound is calculated by dividing the given mass of the compound by its molar mass.

Moles=MassMolarMass.

Answer 7

Chapter 8, Problem 116AP

Interpretation Introduction

(a)

Interpretation:

The number of molecules present in 3.45 g of C6H12O6 should be calculated.

Concept Introduction:

According to Avogadro’s number, one mole of a compound contains 6.023×1023 molecules.

Number of moles of a compound is calculated by dividing the given mass of the compound by its molar mass.

Moles=MassMolarMass.

Answer 8

Interpretation Introduction

(b)

Interpretation:

The number of molecules present in 3.45 moles of C6H12O6 should be calculated.

Concept Introduction:

According to Avogadro’s number, one mole of a compound contains 6.023×1023 molecules.

Answer 9

Interpretation Introduction

(b)

Interpretation:

The number of molecules present in 3.45 moles of C6H12O6 should be calculated.

Concept Introduction:

According to Avogadro’s number, one mole of a compound contains 6.023×1023 molecules.

Answer 10

Interpretation Introduction

(c)

Interpretation:

The number of molecules present in 25 g of ICl5 should be calculated.

Concept Introduction:

According to Avogadro’s number, one mole of a compound contains 6.023×1023 molecules.

Number of moles of a compound is calculated by dividing the given mass of the compound by its molar mass.

Moles=MassMolarMass.

Answer 11

Interpretation Introduction

(c)

Interpretation:

The number of molecules present in 25 g of ICl5 should be calculated.

Concept Introduction:

According to Avogadro’s number, one mole of a compound contains 6.023×1023 molecules.

Number of moles of a compound is calculated by dividing the given mass of the compound by its molar mass.

Moles=MassMolarMass.

Answer 12

Interpretation Introduction

(d)

Interpretation:

The number of molecules present in 1g of B2H6 should be calculated.

Concept Introduction:

According to Avogadro’s number, one mole of a compound contains 6.023×1023 molecules.

Number of moles of a compound is calculated by dividing the given mass of the compound by its molar mass.

Moles=MassMolarMass.

Answer 13

Interpretation Introduction

(d)

Interpretation:

The number of molecules present in 1g of B2H6 should be calculated.

Concept Introduction:

According to Avogadro’s number, one mole of a compound contains 6.023×1023 molecules.

Number of moles of a compound is calculated by dividing the given mass of the compound by its molar mass.

Moles=MassMolarMass.

Answer 14

Interpretation Introduction

(e)

Interpretation:

The number of molecules present in 1.05 mmol of Al(NO3)3 should be calculated.

Concept Introduction:

According to Avogadro’s number, one mole of a compound contains 6.023×1023 molecules.

Answer 15

Interpretation Introduction

(e)

Interpretation:

The number of molecules present in 1.05 mmol of Al(NO3)3 should be calculated.

Concept Introduction:

According to Avogadro’s number, one mole of a compound contains 6.023×1023 molecules.

Answer 16

Expert Solution & Answer

Answer 17

Expert Solution & Answer

Answer 18

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Answer 19

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Solution Summary: The author explains how the number of molecules in a compound is calculated by dividing the given mass of the compound by its molar mass.

Concept explainers

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(b)

Interpretation:

The number of molecules present in 3.45 moles of C6H12O6 should be calculated.

Concept Introduction:

According to Avogadro’s number, one mole of a compound contains 6.023×1023 molecules.

(e)

Interpretation:

The number of molecules present in 1.05 mmol of Al(NO3)3 should be calculated.

Concept Introduction:

According to Avogadro’s number, one mole of a compound contains 6.023×1023 molecules.

Want to see the full answer?

Chapter 8 Solutions

Solution Summary: The author explains how the number of molecules in a compound is calculated by dividing the given mass of the compound by its molar mass.

Concept explainers

Videos

(b) Interpretation: The number of molecules present in 3.45 moles of C6H12O6 should be calculated. Concept Introduction: According to Avogadro’s number, one mole of a compound contains 6.023×1023 molecules.

(e) Interpretation: The number of molecules present in 1.05 mmol of Al(NO3)3 should be calculated. Concept Introduction: According to Avogadro’s number, one mole of a compound contains 6.023×1023 molecules.

Want to see the full answer?

Chapter 8 Solutions

(b)

Interpretation:

The number of molecules present in 3.45 moles of C6H12O6 should be calculated.

Concept Introduction:

According to Avogadro’s number, one mole of a compound contains 6.023×1023 molecules.

(e)

Interpretation:

The number of molecules present in 1.05 mmol of Al(NO3)3 should be calculated.

Concept Introduction:

According to Avogadro’s number, one mole of a compound contains 6.023×1023 molecules.