Hex address of the relocated reference to “sum”: From the given Figure 7.12(a), the function “sum” in line 5 is 4004de: e8 05 00 00 00callq 4004e8 <sum>sum() From the given Figure 7.12(a), the value of “ADDR(s)”, “ADDR(r.symbol)” and “r.addend” is given below ADDR(s) = ADDR( .text) = 0x4004d0 r .offset = 0xf r .addend = -4 Now calculate the reference address for given line using the below formula. refaddr = ADDR(s) + r

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Answer 1

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Chapter 7.7, Problem 7.4PP

A.

Explanation of Solution

Hex address of the relocated reference to “sum”:

From the given Figure 7.12(a), the function “sum” in line 5 is

4004de: e8 05 00 00 00callq 4004e8 <sum>sum()

From the given Figure 7.12(a), the value of “ADDR(s)”, “ADDR(r.symbol)” and “r.addend” is given below

ADDR(s) = ADDR(.text) = 0x4004d0

r.offset = 0xf

r.addend = -4

Now calculate the reference address for given line using the below formula.

refaddr = ADDR(s) + r

B.

Explanation of Solution

Hex value of the relocated reference to “sum”:

From the given Figure 7.12(a), the function “sum” in line 5 is

4004de: e8 05 00 00 00callq 4004e8 <sum>sum()

From the given Figure 7.12(a), the value of “ADDR(s)”, “ADDR(r.symbol)” and “r.addend” is given below

ADDR(s) = ADDR(.text) = 0x4004d0

r.offset = 0xf

r.addend = -4

Now calculate the reference address for given line using the below formula.

refaddr = ADDR(s) + r.offset

Then,

refaddr = ADDR(s) + r

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