Glencoe Math Accelerated, Student Edition
1st Edition
ISBN: 9780076637980
Author: McGraw-Hill Glencoe
Publisher: MCG
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 7.5, Problem 22IP
To determine
Find the GCF of
Expert Solution & Answer
Answer to Problem 22IP
GCF of
Explanation of Solution
Given:
Pair of monomials:
Concept Used:
GCF is the greatest common factor of the pair of monomials.
Calculation:
Thus, GCF of
Chapter 7 Solutions
Glencoe Math Accelerated, Student Edition
Ch. 7.1 - Prob. 1GPCh. 7.1 - Prob. 2GPCh. 7.1 - Prob. 3GPCh. 7.1 - Prob. 4GPCh. 7.1 - Prob. 5GPCh. 7.1 - Prob. 6GPCh. 7.1 - Prob. 7GPCh. 7.1 - Prob. 8GPCh. 7.1 - Prob. 9GPCh. 7.1 - Prob. 10IP
Ch. 7.1 - Prob. 11IPCh. 7.1 - Prob. 12IPCh. 7.1 - Prob. 13IPCh. 7.1 - Prob. 14IPCh. 7.1 - Prob. 15IPCh. 7.1 - Prob. 16IPCh. 7.1 - Prob. 17IPCh. 7.1 - Prob. 18IPCh. 7.1 - Prob. 19IPCh. 7.1 - Prob. 20IPCh. 7.1 - Prob. 21IPCh. 7.1 - Prob. 22IPCh. 7.1 - Prob. 23IPCh. 7.1 - Prob. 24IPCh. 7.1 - Prob. 25IPCh. 7.1 - Prob. 26IPCh. 7.1 - Prob. 27IPCh. 7.1 - Prob. 28IPCh. 7.1 - Prob. 29IPCh. 7.1 - Prob. 30IPCh. 7.1 - Prob. 31IPCh. 7.1 - Prob. 32IPCh. 7.1 - Prob. 33IPCh. 7.1 - Prob. 34IPCh. 7.1 - Prob. 35IPCh. 7.1 - Prob. 36IPCh. 7.1 - Prob. 37HPCh. 7.1 - Prob. 38HPCh. 7.1 - Prob. 39HPCh. 7.1 - Prob. 40STPCh. 7.1 - Prob. 41STPCh. 7.1 - Prob. 42STPCh. 7.1 - Prob. 43STPCh. 7.1 - Prob. 44CCRCh. 7.1 - Prob. 45CCRCh. 7.1 - Prob. 46CCRCh. 7.1 - Prob. 47CCRCh. 7.1 - Prob. 48CCRCh. 7.1 - Prob. 49CCRCh. 7.1 - Prob. 50CCRCh. 7.1 - Prob. 51CCRCh. 7.1 - Prob. 52CCRCh. 7.1 - Prob. 53CCRCh. 7.2 - Prob. 1GPCh. 7.2 - Prob. 2GPCh. 7.2 - Prob. 3GPCh. 7.2 - Prob. 4GPCh. 7.2 - Prob. 5GPCh. 7.2 - Prob. 6GPCh. 7.2 - Prob. 7GPCh. 7.2 - Prob. 8GPCh. 7.2 - Prob. 9GPCh. 7.2 - Prob. 10GPCh. 7.2 - Prob. 11GPCh. 7.2 - Prob. 12GPCh. 7.2 - Prob. 13GPCh. 7.2 - Prob. 14GPCh. 7.2 - Prob. 15IPCh. 7.2 - Prob. 16IPCh. 7.2 - Prob. 17IPCh. 7.2 - Prob. 18IPCh. 7.2 - Prob. 19IPCh. 7.2 - Prob. 20IPCh. 7.2 - Prob. 21IPCh. 7.2 - Prob. 22IPCh. 7.2 - Prob. 23IPCh. 7.2 - Prob. 24IPCh. 7.2 - Prob. 25IPCh. 7.2 - Prob. 26IPCh. 7.2 - Prob. 27IPCh. 7.2 - Prob. 28IPCh. 7.2 - Prob. 29IPCh. 7.2 - Prob. 30IPCh. 7.2 - Prob. 31IPCh. 7.2 - Prob. 32IPCh. 7.2 - Prob. 33IPCh. 7.2 - Prob. 34IPCh. 7.2 - Prob. 35IPCh. 7.2 - Prob. 36IPCh. 7.2 - Prob. 37IPCh. 7.2 - Prob. 38IPCh. 7.2 - Prob. 39IPCh. 7.2 - Prob. 40IPCh. 7.2 - Prob. 41IPCh. 7.2 - Prob. 42IPCh. 7.2 - Prob. 43IPCh. 7.2 - Prob. 44IPCh. 7.2 - Prob. 45IPCh. 7.2 - Prob. 46IPCh. 7.2 - Prob. 47IPCh. 7.2 - Prob. 48IPCh. 7.2 - Prob. 49IPCh. 7.2 - Prob. 50IPCh. 7.2 - Prob. 51IPCh. 7.2 - Prob. 52IPCh. 7.2 - Prob. 53IPCh. 7.2 - Prob. 54HPCh. 7.2 - Prob. 55HPCh. 7.2 - Prob. 56HPCh. 7.2 - Prob. 57HPCh. 7.2 - Prob. 58HPCh. 7.2 - Prob. 59HPCh. 7.2 - Prob. 60STPCh. 7.2 - Prob. 61STPCh. 7.2 - Prob. 62STPCh. 7.2 - Prob. 63STPCh. 7.2 - Prob. 64CCRCh. 7.2 - Prob. 65CCRCh. 7.2 - Prob. 66CCRCh. 7.2 - Prob. 67CCRCh. 7.2 - Prob. 68CCRCh. 7.2 - Prob. 69CCRCh. 7.2 - Prob. 70CCRCh. 7.2 - Prob. 71CCRCh. 7.2 - Prob. 72CCRCh. 7.2 - Prob. 73CCRCh. 7.2 - Prob. 74CCRCh. 7.2 - Prob. 75CCRCh. 7.2 - Prob. 76CCRCh. 7.2 - Prob. 77CCRCh. 7.2 - Prob. 78CCRCh. 7.2 - Prob. 79CCRCh. 7.2 - Prob. 80CCRCh. 7.2 - Prob. 81CCRCh. 7.2 - Prob. 82CCRCh. 7.2 - Prob. 83CCRCh. 7.3 - Prob. 1GPCh. 7.3 - Prob. 2GPCh. 7.3 - Prob. 3GPCh. 7.3 - Prob. 4GPCh. 7.3 - Prob. 5GPCh. 7.3 - Prob. 6IPCh. 7.3 - Prob. 7IPCh. 7.3 - Prob. 8IPCh. 7.3 - Prob. 9IPCh. 7.3 - Prob. 10IPCh. 7.3 - Prob. 11IPCh. 7.3 - Prob. 12IPCh. 7.3 - Prob. 13IPCh. 7.3 - Prob. 14IPCh. 7.3 - Prob. 15IPCh. 7.3 - Prob. 16IPCh. 7.3 - Prob. 17IPCh. 7.3 - Prob. 18HPCh. 7.3 - Prob. 19HPCh. 7.3 - Prob. 20HPCh. 7.3 - Prob. 21HPCh. 7.3 - Prob. 22STPCh. 7.3 - Prob. 23STPCh. 7.3 - Prob. 24STPCh. 7.3 - Prob. 25STPCh. 7.3 - Prob. 26CCRCh. 7.3 - Prob. 27CCRCh. 7.3 - Prob. 28CCRCh. 7.3 - Prob. 29CCRCh. 7.3 - Prob. 30CCRCh. 7.3 - Prob. 31CCRCh. 7.3 - Prob. 32CCRCh. 7.3 - Prob. 33CCRCh. 7.3 - Prob. 34CCRCh. 7.3 - Prob. 35CCRCh. 7.3 - Prob. 36CCRCh. 7.3 - Prob. 37CCRCh. 7.3 - Prob. 38CCRCh. 7.3 - Prob. 39CCRCh. 7.3 - Prob. 40CCRCh. 7.3 - Prob. 41CCRCh. 7.3 - Prob. 42CCRCh. 7.3 - Prob. 43CCRCh. 7.3 - Prob. 44CCRCh. 7.3 - Prob. 45CCRCh. 7.3 - Prob. 46CCRCh. 7.3 - Prob. 47CCRCh. 7.4 - Prob. 1GPCh. 7.4 - Prob. 2GPCh. 7.4 - Prob. 3GPCh. 7.4 - Prob. 4GPCh. 7.4 - Prob. 5GPCh. 7.4 - Prob. 6IPCh. 7.4 - Prob. 7IPCh. 7.4 - Prob. 8IPCh. 7.4 - Prob. 9IPCh. 7.4 - Prob. 10IPCh. 7.4 - Prob. 11IPCh. 7.4 - Prob. 12IPCh. 7.4 - Prob. 13IPCh. 7.4 - Prob. 14IPCh. 7.4 - Prob. 15HPCh. 7.4 - Prob. 16HPCh. 7.4 - Prob. 17HPCh. 7.4 - Prob. 18STPCh. 7.4 - Prob. 19STPCh. 7.4 - Prob. 20STPCh. 7.4 - Prob. 21STPCh. 7.4 - Prob. 22CCRCh. 7.4 - Prob. 23CCRCh. 7.4 - Prob. 24CCRCh. 7.4 - Prob. 25CCRCh. 7.4 - Prob. 26CCRCh. 7.4 - Prob. 27CCRCh. 7.4 - Prob. 28CCRCh. 7.4 - Prob. 29CCRCh. 7.4 - Prob. 30CCRCh. 7.4 - Prob. 31CCRCh. 7.4 - Prob. 32CCRCh. 7.4 - Prob. 33CCRCh. 7.4 - Prob. 34CCRCh. 7.4 - Prob. 35CCRCh. 7.4 - Prob. 36CCRCh. 7.4 - Prob. 37CCRCh. 7.4 - Prob. 38CCRCh. 7.4 - Prob. 39CCRCh. 7.4 - Prob. 40CCRCh. 7.4 - Prob. 41CCRCh. 7.4 - Prob. 42CCRCh. 7.4 - Prob. 43CCRCh. 7.5 - Prob. 1GPCh. 7.5 - Prob. 2GPCh. 7.5 - Prob. 3GPCh. 7.5 - Prob. 4GPCh. 7.5 - Prob. 5GPCh. 7.5 - Prob. 6GPCh. 7.5 - Prob. 7GPCh. 7.5 - Prob. 8GPCh. 7.5 - Prob. 9GPCh. 7.5 - Prob. 10GPCh. 7.5 - Prob. 11GPCh. 7.5 - Prob. 12GPCh. 7.5 - Prob. 13GPCh. 7.5 - Prob. 14GPCh. 7.5 - Prob. 15GPCh. 7.5 - Prob. 16GPCh. 7.5 - Prob. 17GPCh. 7.5 - Prob. 18GPCh. 7.5 - Prob. 19GPCh. 7.5 - Prob. 20GPCh. 7.5 - Prob. 21IPCh. 7.5 - Prob. 22IPCh. 7.5 - Prob. 23IPCh. 7.5 - Prob. 24IPCh. 7.5 - Prob. 25IPCh. 7.5 - Prob. 26IPCh. 7.5 - Prob. 27IPCh. 7.5 - Prob. 28IPCh. 7.5 - Prob. 29IPCh. 7.5 - Prob. 30IPCh. 7.5 - Prob. 31IPCh. 7.5 - Prob. 32IPCh. 7.5 - Prob. 33IPCh. 7.5 - Prob. 34IPCh. 7.5 - Prob. 35IPCh. 7.5 - Prob. 36IPCh. 7.5 - Prob. 37IPCh. 7.5 - Prob. 38IPCh. 7.5 - Prob. 39IPCh. 7.5 - Prob. 40IPCh. 7.5 - Prob. 41IPCh. 7.5 - Prob. 42IPCh. 7.5 - Prob. 43IPCh. 7.5 - Prob. 44IPCh. 7.5 - Prob. 45IPCh. 7.5 - Prob. 46IPCh. 7.5 - Prob. 47IPCh. 7.5 - Prob. 48IPCh. 7.5 - Prob. 49IPCh. 7.5 - Prob. 50IPCh. 7.5 - Prob. 51HPCh. 7.5 - Prob. 52HPCh. 7.5 - Prob. 53HPCh. 7.5 - Prob. 54STPCh. 7.5 - Prob. 55STPCh. 7.5 - Prob. 56STPCh. 7.5 - Prob. 57CCRCh. 7.5 - Prob. 58CCRCh. 7.5 - Prob. 59CCRCh. 7.5 - Prob. 60CCRCh. 7.5 - Prob. 61CCRCh. 7.5 - Prob. 62CCRCh. 7.5 - Prob. 63CCRCh. 7.5 - Prob. 64CCRCh. 7.5 - Prob. 65CCRCh. 7.5 - Prob. 66CCRCh. 7.5 - Prob. 67CCRCh. 7.5 - Prob. 68CCRCh. 7 - Prob. 1CRCh. 7 - Prob. 2CRCh. 7 - Prob. 3CRCh. 7 - Prob. 4CRCh. 7 - Prob. 5CRCh. 7 - Prob. 6CRCh. 7 - Prob. 7CRCh. 7 - Prob. 8CRCh. 7 - Prob. 9CRCh. 7 - Prob. 10CRCh. 7 - Prob. 11CRCh. 7 - Prob. 12CRCh. 7 - Prob. 13CRCh. 7 - Prob. 14CRCh. 7 - Prob. 15CRCh. 7 - Prob. 16CRCh. 7 - Prob. 17CRCh. 7 - Prob. 18CRCh. 7 - Prob. 19CRCh. 7 - Prob. 20CRCh. 7 - Prob. 21CRCh. 7 - Prob. 22CRCh. 7 - Prob. 23CRCh. 7 - Prob. 24CRCh. 7 - Prob. 25CRCh. 7 - Prob. 26CRCh. 7 - Prob. 27CRCh. 7 - Prob. 28CRCh. 7 - Prob. 29CRCh. 7 - Prob. 30CRCh. 7 - Prob. 31CRCh. 7 - Prob. 32CRCh. 7 - Prob. 33CRCh. 7 - Prob. 34CRCh. 7 - Prob. 35CR
Additional Math Textbook Solutions
Find more solutions based on key concepts
A categorical variable has three categories, with the following frequencies of occurrence: a. Compute the perce...
Basic Business Statistics, Student Value Edition
In Exercises 9-20, use the data in the following table, which lists drive-thru order accuracy at popular fast f...
Elementary Statistics (13th Edition)
The fraction 630 in its simplest form.
Pre-Algebra Student Edition
A child has 12 blocks, of which 6 are black, 4 are red, 1 is white, and 1 is blue. If the child puts the blocks...
A First Course in Probability (10th Edition)
Females’ Pulse Rates before and after a Fright (Example 17) In a statistics class taught by one of the authors,...
Introductory Statistics
1. combination of numbers, variables, and operation symbols is called an algebraic______.
Algebra and Trigonometry (6th Edition)
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, calculus and related others by exploring similar questions and additional content below.Similar questions
- x4 -289 Consider the function f(x) = 2 X-17 Complete parts a and b below. a. Analyze lim f(x) and lim f(x), and then identify the horizontal asymptotes. x+x X--∞ lim 4 X-289 2 X∞ X-17 X - 289 lim = 2 ... X∞ X - 17 Identify the horizontal asymptotes. Select the correct choice and, if necessary, fill in the answer box(es) to complete your choice. A. The function has a horizontal asymptote at y = B. The function has two horizontal asymptotes. The top asymptote is y = and the bottom asymptote is y = ☐ . C. The function has no horizontal asymptotes. b. Find the vertical asymptotes. For each vertical asymptote x = a, evaluate lim f(x) and lim f(x). Select the correct choice and, if necessary, fill in the answer boxes to complete your choice. earrow_forwardExplain why lim x²-2x-35 X-7 X-7 lim (x+5), and then evaluate lim X-7 x² -2x-35 x-7 x-7 Choose the correct answer below. A. x²-2x-35 The limits lim X-7 X-7 and lim (x+5) equal the same number when evaluated using X-7 direct substitution. B. Since each limit approaches 7, it follows that the limits are equal. C. The numerator of the expression X-2x-35 X-7 simplifies to x + 5 for all x, so the limits are equal. D. Since x²-2x-35 X-7 = x + 5 whenever x 7, it follows that the two expressions evaluate to the same number as x approaches 7. Now evaluate the limit. x²-2x-35 lim X-7 X-7 = (Simplify your answer.)arrow_forwardA function f is even if f(x) = f(x) for all x in the domain of f. If f is even, with lim f(x) = 4 and x-6+ lim f(x)=-3, find the following limits. X-6 a. lim f(x) b. +9-←x lim f(x) X-6 a. lim f(x)= +9-←x (Simplify your answer.) b. lim f(x)= X→-6 (Simplify your answer.) ...arrow_forwardEvaluate the following limit. lim X-X (10+19) Select the correct answer below and, if necessary, fill in the answer box within your choice. 10 A. lim 10+ = 2 ☐ (Type an integer or a simplified fraction.) X-∞ B. The limit does not exist.arrow_forwardFind the following limit or state that it does not exist. x² +x-20 lim x-4 x-4 Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. lim x²+x-20 x-4 (Type an exact answer.) x→4 B. The limit does not exist.arrow_forwardDetermine the intervals on which the following function is continuous. f(x) = x - 5x + 6 2 X-9 On what interval(s) is f continuous? (Simplify your answer. Type your answer in interval notation. Use a comma to separate answers as needed.)arrow_forwardFind the following limit or state that it does not exist. 2 3x² +7x+2 lim X-2 6x-8 Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. lim 3x²+7x+2 6x-8 (Simplify your answer.) X-2 B. The limit does not exist.arrow_forwardFind the following limit or state that it does not exist. X-2 lim x-2 5x+6 - 4 Select the correct choice below and, if necessary, fill in the answer box to complete your choice. O A. lim X-2 X-2 15x+6 = (Type an exact answer.) - 4 B. The limit does not exist.arrow_forward(a) Sketch the graph of a function that is not continuous at 1, but is defined at 1. (b) Sketch the graph of a function that is not continuous at 1, but has a limit at 1. (a) Which of the following graphs shows a function that is not continuous at 1, but is defined at 1. ○ A. Ay ✓ B. 5 X ✓ (b) Which of the following graphs shows a function that is not continuous at 1, but has a limit at 1. ○ A. B. X y 5- -5 5 ✓ ✓ 5 ☑ 5 X y ☑ LVarrow_forwardIf lim f(x)=L and lim f(x) = M, where L and M are finite real numbers, then what must be true about L x-a x-a+ and M in order for lim f(x) to exist? x-a Choose the correct answer below. A. L = M B. LMarrow_forwardDetermine the following limit, using ∞ or - ∞ when appropriate, or state that it does not exist. lim csc 0 Select the correct choice below, and fill in the answer box if necessary. lim csc 0 = ○ A. 0→⭑ B. The limit does not exist and is neither ∞ nor - ∞.arrow_forwardIs the function f(x) continuous at x = 1? (x) 7 6 5 4 3 2 1 0 -10 -9 -8 -7 -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 7 8 9 10 -1 -2 -3 -4 -5 -6 -71 Select the correct answer below: The function f(x) is continuous at x = 1. The right limit does not equal the left limit. Therefore, the function is not continuous. The function f(x) is discontinuous at x = 1. We cannot tell if the function is continuous or discontinuous.arrow_forwardarrow_back_iosSEE MORE QUESTIONSarrow_forward_ios
Recommended textbooks for you
- Calculus: Early TranscendentalsCalculusISBN:9781285741550Author:James StewartPublisher:Cengage LearningThomas' Calculus (14th Edition)CalculusISBN:9780134438986Author:Joel R. Hass, Christopher E. Heil, Maurice D. WeirPublisher:PEARSONCalculus: Early Transcendentals (3rd Edition)CalculusISBN:9780134763644Author:William L. Briggs, Lyle Cochran, Bernard Gillett, Eric SchulzPublisher:PEARSON
- Calculus: Early TranscendentalsCalculusISBN:9781319050740Author:Jon Rogawski, Colin Adams, Robert FranzosaPublisher:W. H. FreemanCalculus: Early Transcendental FunctionsCalculusISBN:9781337552516Author:Ron Larson, Bruce H. EdwardsPublisher:Cengage Learning
Calculus: Early Transcendentals
Calculus
ISBN:9781285741550
Author:James Stewart
Publisher:Cengage Learning
Thomas' Calculus (14th Edition)
Calculus
ISBN:9780134438986
Author:Joel R. Hass, Christopher E. Heil, Maurice D. Weir
Publisher:PEARSON
Calculus: Early Transcendentals (3rd Edition)
Calculus
ISBN:9780134763644
Author:William L. Briggs, Lyle Cochran, Bernard Gillett, Eric Schulz
Publisher:PEARSON
Calculus: Early Transcendentals
Calculus
ISBN:9781319050740
Author:Jon Rogawski, Colin Adams, Robert Franzosa
Publisher:W. H. Freeman
Calculus: Early Transcendental Functions
Calculus
ISBN:9781337552516
Author:Ron Larson, Bruce H. Edwards
Publisher:Cengage Learning
Polynomials with Trigonometric Solutions (2 of 3: Substitute & solve); Author: Eddie Woo;https://www.youtube.com/watch?v=EnfhYp4o20w;License: Standard YouTube License, CC-BY
Quick Revision of Polynomials | Tricks to Solve Polynomials in Algebra | Maths Tricks | Letstute; Author: Let'stute;https://www.youtube.com/watch?v=YmDnGcol-gs;License: Standard YouTube License, CC-BY
Introduction to Polynomials; Author: Professor Dave Explains;https://www.youtube.com/watch?v=nPPNgin7W7Y;License: Standard Youtube License