Glencoe Math Accelerated, Student Edition
1st Edition
ISBN: 9780076637980
Author: McGraw-Hill Glencoe
Publisher: MCG
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Question
Chapter 7.3, Problem 28CCR
To determine
Write the ratio in simplest form.
Expert Solution & Answer
Answer to Problem 28CCR
Simplest form:
Explanation of Solution
Given: 14 out of 30 whales
Concept Used:
In mathematics, a ratio indicates how many times one number contains another. For example, if there are eight oranges and six lemons in a bowl of fruit, then the ratio of oranges to lemons is eight to six (that is, 8:6, which is equivalent to the ratio 4:3). ... Equal quotients correspond to equal ratios.
Calculation:
To find the simplest form, just cancel out the GCF or common factor from both the number.
14 out of 30 whales
Simplest form:
Thus, Simplest form:
Chapter 7 Solutions
Glencoe Math Accelerated, Student Edition
Ch. 7.1 - Prob. 1GPCh. 7.1 - Prob. 2GPCh. 7.1 - Prob. 3GPCh. 7.1 - Prob. 4GPCh. 7.1 - Prob. 5GPCh. 7.1 - Prob. 6GPCh. 7.1 - Prob. 7GPCh. 7.1 - Prob. 8GPCh. 7.1 - Prob. 9GPCh. 7.1 - Prob. 10IP
Ch. 7.1 - Prob. 11IPCh. 7.1 - Prob. 12IPCh. 7.1 - Prob. 13IPCh. 7.1 - Prob. 14IPCh. 7.1 - Prob. 15IPCh. 7.1 - Prob. 16IPCh. 7.1 - Prob. 17IPCh. 7.1 - Prob. 18IPCh. 7.1 - Prob. 19IPCh. 7.1 - Prob. 20IPCh. 7.1 - Prob. 21IPCh. 7.1 - Prob. 22IPCh. 7.1 - Prob. 23IPCh. 7.1 - Prob. 24IPCh. 7.1 - Prob. 25IPCh. 7.1 - Prob. 26IPCh. 7.1 - Prob. 27IPCh. 7.1 - Prob. 28IPCh. 7.1 - Prob. 29IPCh. 7.1 - Prob. 30IPCh. 7.1 - Prob. 31IPCh. 7.1 - Prob. 32IPCh. 7.1 - Prob. 33IPCh. 7.1 - Prob. 34IPCh. 7.1 - Prob. 35IPCh. 7.1 - Prob. 36IPCh. 7.1 - Prob. 37HPCh. 7.1 - Prob. 38HPCh. 7.1 - Prob. 39HPCh. 7.1 - Prob. 40STPCh. 7.1 - Prob. 41STPCh. 7.1 - Prob. 42STPCh. 7.1 - Prob. 43STPCh. 7.1 - Prob. 44CCRCh. 7.1 - Prob. 45CCRCh. 7.1 - Prob. 46CCRCh. 7.1 - Prob. 47CCRCh. 7.1 - Prob. 48CCRCh. 7.1 - Prob. 49CCRCh. 7.1 - Prob. 50CCRCh. 7.1 - Prob. 51CCRCh. 7.1 - Prob. 52CCRCh. 7.1 - Prob. 53CCRCh. 7.2 - Prob. 1GPCh. 7.2 - Prob. 2GPCh. 7.2 - Prob. 3GPCh. 7.2 - Prob. 4GPCh. 7.2 - Prob. 5GPCh. 7.2 - Prob. 6GPCh. 7.2 - Prob. 7GPCh. 7.2 - Prob. 8GPCh. 7.2 - Prob. 9GPCh. 7.2 - Prob. 10GPCh. 7.2 - Prob. 11GPCh. 7.2 - Prob. 12GPCh. 7.2 - Prob. 13GPCh. 7.2 - Prob. 14GPCh. 7.2 - Prob. 15IPCh. 7.2 - Prob. 16IPCh. 7.2 - Prob. 17IPCh. 7.2 - Prob. 18IPCh. 7.2 - Prob. 19IPCh. 7.2 - Prob. 20IPCh. 7.2 - Prob. 21IPCh. 7.2 - Prob. 22IPCh. 7.2 - Prob. 23IPCh. 7.2 - Prob. 24IPCh. 7.2 - Prob. 25IPCh. 7.2 - Prob. 26IPCh. 7.2 - Prob. 27IPCh. 7.2 - Prob. 28IPCh. 7.2 - Prob. 29IPCh. 7.2 - Prob. 30IPCh. 7.2 - Prob. 31IPCh. 7.2 - Prob. 32IPCh. 7.2 - Prob. 33IPCh. 7.2 - Prob. 34IPCh. 7.2 - Prob. 35IPCh. 7.2 - Prob. 36IPCh. 7.2 - Prob. 37IPCh. 7.2 - Prob. 38IPCh. 7.2 - Prob. 39IPCh. 7.2 - Prob. 40IPCh. 7.2 - Prob. 41IPCh. 7.2 - Prob. 42IPCh. 7.2 - Prob. 43IPCh. 7.2 - Prob. 44IPCh. 7.2 - Prob. 45IPCh. 7.2 - Prob. 46IPCh. 7.2 - Prob. 47IPCh. 7.2 - Prob. 48IPCh. 7.2 - Prob. 49IPCh. 7.2 - Prob. 50IPCh. 7.2 - Prob. 51IPCh. 7.2 - Prob. 52IPCh. 7.2 - Prob. 53IPCh. 7.2 - Prob. 54HPCh. 7.2 - Prob. 55HPCh. 7.2 - Prob. 56HPCh. 7.2 - Prob. 57HPCh. 7.2 - Prob. 58HPCh. 7.2 - Prob. 59HPCh. 7.2 - Prob. 60STPCh. 7.2 - Prob. 61STPCh. 7.2 - Prob. 62STPCh. 7.2 - Prob. 63STPCh. 7.2 - Prob. 64CCRCh. 7.2 - Prob. 65CCRCh. 7.2 - Prob. 66CCRCh. 7.2 - Prob. 67CCRCh. 7.2 - Prob. 68CCRCh. 7.2 - Prob. 69CCRCh. 7.2 - Prob. 70CCRCh. 7.2 - Prob. 71CCRCh. 7.2 - Prob. 72CCRCh. 7.2 - Prob. 73CCRCh. 7.2 - Prob. 74CCRCh. 7.2 - Prob. 75CCRCh. 7.2 - Prob. 76CCRCh. 7.2 - Prob. 77CCRCh. 7.2 - Prob. 78CCRCh. 7.2 - Prob. 79CCRCh. 7.2 - Prob. 80CCRCh. 7.2 - Prob. 81CCRCh. 7.2 - Prob. 82CCRCh. 7.2 - Prob. 83CCRCh. 7.3 - Prob. 1GPCh. 7.3 - Prob. 2GPCh. 7.3 - Prob. 3GPCh. 7.3 - Prob. 4GPCh. 7.3 - Prob. 5GPCh. 7.3 - Prob. 6IPCh. 7.3 - Prob. 7IPCh. 7.3 - Prob. 8IPCh. 7.3 - Prob. 9IPCh. 7.3 - Prob. 10IPCh. 7.3 - Prob. 11IPCh. 7.3 - Prob. 12IPCh. 7.3 - Prob. 13IPCh. 7.3 - Prob. 14IPCh. 7.3 - Prob. 15IPCh. 7.3 - Prob. 16IPCh. 7.3 - Prob. 17IPCh. 7.3 - Prob. 18HPCh. 7.3 - Prob. 19HPCh. 7.3 - Prob. 20HPCh. 7.3 - Prob. 21HPCh. 7.3 - Prob. 22STPCh. 7.3 - Prob. 23STPCh. 7.3 - Prob. 24STPCh. 7.3 - Prob. 25STPCh. 7.3 - Prob. 26CCRCh. 7.3 - Prob. 27CCRCh. 7.3 - Prob. 28CCRCh. 7.3 - Prob. 29CCRCh. 7.3 - Prob. 30CCRCh. 7.3 - Prob. 31CCRCh. 7.3 - Prob. 32CCRCh. 7.3 - Prob. 33CCRCh. 7.3 - Prob. 34CCRCh. 7.3 - Prob. 35CCRCh. 7.3 - Prob. 36CCRCh. 7.3 - Prob. 37CCRCh. 7.3 - Prob. 38CCRCh. 7.3 - Prob. 39CCRCh. 7.3 - Prob. 40CCRCh. 7.3 - Prob. 41CCRCh. 7.3 - Prob. 42CCRCh. 7.3 - Prob. 43CCRCh. 7.3 - Prob. 44CCRCh. 7.3 - Prob. 45CCRCh. 7.3 - Prob. 46CCRCh. 7.3 - Prob. 47CCRCh. 7.4 - Prob. 1GPCh. 7.4 - Prob. 2GPCh. 7.4 - Prob. 3GPCh. 7.4 - Prob. 4GPCh. 7.4 - Prob. 5GPCh. 7.4 - Prob. 6IPCh. 7.4 - Prob. 7IPCh. 7.4 - Prob. 8IPCh. 7.4 - Prob. 9IPCh. 7.4 - Prob. 10IPCh. 7.4 - Prob. 11IPCh. 7.4 - Prob. 12IPCh. 7.4 - Prob. 13IPCh. 7.4 - Prob. 14IPCh. 7.4 - Prob. 15HPCh. 7.4 - Prob. 16HPCh. 7.4 - Prob. 17HPCh. 7.4 - Prob. 18STPCh. 7.4 - Prob. 19STPCh. 7.4 - Prob. 20STPCh. 7.4 - Prob. 21STPCh. 7.4 - Prob. 22CCRCh. 7.4 - Prob. 23CCRCh. 7.4 - Prob. 24CCRCh. 7.4 - Prob. 25CCRCh. 7.4 - Prob. 26CCRCh. 7.4 - Prob. 27CCRCh. 7.4 - Prob. 28CCRCh. 7.4 - Prob. 29CCRCh. 7.4 - Prob. 30CCRCh. 7.4 - Prob. 31CCRCh. 7.4 - Prob. 32CCRCh. 7.4 - Prob. 33CCRCh. 7.4 - Prob. 34CCRCh. 7.4 - Prob. 35CCRCh. 7.4 - Prob. 36CCRCh. 7.4 - Prob. 37CCRCh. 7.4 - Prob. 38CCRCh. 7.4 - Prob. 39CCRCh. 7.4 - Prob. 40CCRCh. 7.4 - Prob. 41CCRCh. 7.4 - Prob. 42CCRCh. 7.4 - Prob. 43CCRCh. 7.5 - Prob. 1GPCh. 7.5 - Prob. 2GPCh. 7.5 - Prob. 3GPCh. 7.5 - Prob. 4GPCh. 7.5 - Prob. 5GPCh. 7.5 - Prob. 6GPCh. 7.5 - Prob. 7GPCh. 7.5 - Prob. 8GPCh. 7.5 - Prob. 9GPCh. 7.5 - Prob. 10GPCh. 7.5 - Prob. 11GPCh. 7.5 - Prob. 12GPCh. 7.5 - Prob. 13GPCh. 7.5 - Prob. 14GPCh. 7.5 - Prob. 15GPCh. 7.5 - Prob. 16GPCh. 7.5 - Prob. 17GPCh. 7.5 - Prob. 18GPCh. 7.5 - Prob. 19GPCh. 7.5 - Prob. 20GPCh. 7.5 - Prob. 21IPCh. 7.5 - Prob. 22IPCh. 7.5 - Prob. 23IPCh. 7.5 - Prob. 24IPCh. 7.5 - Prob. 25IPCh. 7.5 - Prob. 26IPCh. 7.5 - Prob. 27IPCh. 7.5 - Prob. 28IPCh. 7.5 - Prob. 29IPCh. 7.5 - Prob. 30IPCh. 7.5 - Prob. 31IPCh. 7.5 - Prob. 32IPCh. 7.5 - Prob. 33IPCh. 7.5 - Prob. 34IPCh. 7.5 - Prob. 35IPCh. 7.5 - Prob. 36IPCh. 7.5 - Prob. 37IPCh. 7.5 - Prob. 38IPCh. 7.5 - Prob. 39IPCh. 7.5 - Prob. 40IPCh. 7.5 - Prob. 41IPCh. 7.5 - Prob. 42IPCh. 7.5 - Prob. 43IPCh. 7.5 - Prob. 44IPCh. 7.5 - Prob. 45IPCh. 7.5 - Prob. 46IPCh. 7.5 - Prob. 47IPCh. 7.5 - Prob. 48IPCh. 7.5 - Prob. 49IPCh. 7.5 - Prob. 50IPCh. 7.5 - Prob. 51HPCh. 7.5 - Prob. 52HPCh. 7.5 - Prob. 53HPCh. 7.5 - Prob. 54STPCh. 7.5 - Prob. 55STPCh. 7.5 - Prob. 56STPCh. 7.5 - Prob. 57CCRCh. 7.5 - Prob. 58CCRCh. 7.5 - Prob. 59CCRCh. 7.5 - Prob. 60CCRCh. 7.5 - Prob. 61CCRCh. 7.5 - Prob. 62CCRCh. 7.5 - Prob. 63CCRCh. 7.5 - Prob. 64CCRCh. 7.5 - Prob. 65CCRCh. 7.5 - Prob. 66CCRCh. 7.5 - Prob. 67CCRCh. 7.5 - Prob. 68CCRCh. 7 - Prob. 1CRCh. 7 - Prob. 2CRCh. 7 - Prob. 3CRCh. 7 - Prob. 4CRCh. 7 - Prob. 5CRCh. 7 - Prob. 6CRCh. 7 - Prob. 7CRCh. 7 - Prob. 8CRCh. 7 - Prob. 9CRCh. 7 - Prob. 10CRCh. 7 - Prob. 11CRCh. 7 - Prob. 12CRCh. 7 - Prob. 13CRCh. 7 - Prob. 14CRCh. 7 - Prob. 15CRCh. 7 - Prob. 16CRCh. 7 - Prob. 17CRCh. 7 - Prob. 18CRCh. 7 - Prob. 19CRCh. 7 - Prob. 20CRCh. 7 - Prob. 21CRCh. 7 - Prob. 22CRCh. 7 - Prob. 23CRCh. 7 - Prob. 24CRCh. 7 - Prob. 25CRCh. 7 - Prob. 26CRCh. 7 - Prob. 27CRCh. 7 - Prob. 28CRCh. 7 - Prob. 29CRCh. 7 - Prob. 30CRCh. 7 - Prob. 31CRCh. 7 - Prob. 32CRCh. 7 - Prob. 33CRCh. 7 - Prob. 34CRCh. 7 - Prob. 35CR
Additional Math Textbook Solutions
Find more solutions based on key concepts
Two dice are thrown. Let E be the event that the sum of the dice is odd, let F be the event that at least one o...
A First Course in Probability (10th Edition)
CHECK POINT 1 Find a counterexample to show that the statement The product of two two-digit numbers is a three-...
Thinking Mathematically (6th Edition)
For a population containing N=902 individual, what code number would you assign for a. the first person on the ...
Basic Business Statistics, Student Value Edition
Coke versus Pepsi (Example 5) Suppose you are testing someone to see whether she or he can tell Coke from Pepsi...
Introductory Statistics
Version 2 of the Chain Rule Use Version 2 of the Chain Rule to calculate the derivatives of the following funct...
Calculus: Early Transcendentals (2nd Edition)
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, calculus and related others by exploring similar questions and additional content below.Similar questions
- Solve this question and show steps.arrow_forwardu, v and w are three coplanar vectors: ⚫ w has a magnitude of 10 and points along the positive x-axis ⚫ v has a magnitude of 3 and makes an angle of 58 degrees to the positive x- axis ⚫ u has a magnitude of 5 and makes an angle of 119 degrees to the positive x- axis ⚫ vector v is located in between u and w a) Draw a diagram of the three vectors placed tail-to-tail at the origin of an x-y plane. b) If possible, find w × (ū+v) Support your answer mathematically or a with a written explanation. c) If possible, find v. (ū⋅w) Support your answer mathematically or a with a written explanation. d) If possible, find u. (vxw) Support your answer mathematically or a with a written explanation. Note: in this question you can work with the vectors in geometric form or convert them to algebraic vectors.arrow_forwardQuestion 3 (6 points) u, v and w are three coplanar vectors: ⚫ w has a magnitude of 10 and points along the positive x-axis ⚫ v has a magnitude of 3 and makes an angle of 58 degrees to the positive x- axis ⚫ u has a magnitude of 5 and makes an angle of 119 degrees to the positive x- axis ⚫ vector v is located in between u and w a) Draw a diagram of the three vectors placed tail-to-tail at the origin of an x-y plane. b) If possible, find w × (u + v) Support your answer mathematically or a with a written explanation. c) If possible, find v. (ū⋅ w) Support your answer mathematically or a with a written explanation. d) If possible, find u (v × w) Support your answer mathematically or a with a written explanation. Note: in this question you can work with the vectors in geometric form or convert them to algebraic vectors.arrow_forward
- K Find all values x = a where the function is discontinuous. For each value of x, give the limit of the function as x approaches a. Be sure to note when the limit doesn't exist. x-7 p(x) = X-7 Select the correct choice below and, if necessary, fill in the answer box(es) within your choice. (Use a comma to separate answers as needed.) OA. f is discontinuous at the single value x = OB. f is discontinuous at the single value x= OC. f is discontinuous at the two values x = OD. f is discontinuous at the two values x = The limit is The limit does not exist and is not co or - ∞. The limit for the smaller value is The limit for the larger value is The limit for the smaller value is The limit for the larger value does not exist and is not c∞ or -arrow_forwardK x3 +216 complete the table and use the results to find lim k(x). If k(x) = X+6 X-6 X -6.1 -6.01 - 6.001 - 5.999 - 5.99 -5.9 k(x) Complete the table. X -6.1 -6.01 - 6.001 - 5.999 - 5.99 - 5.9 k(x) (Round to three decimal places as needed.) Find the limit. Select the correct choice below and, if necessary, fill in the answer box within your choice.arrow_forwardSketch the slope field that represents the differential equation. × Clear Undo Redo y ४|० || 33 dy dxarrow_forward
- Sketch the slope field that represents the differential equation. × Clear Undo Redo dy 33 dx = -y "arrow_forwardMath Test 3 3 x³+y³ = Ꭹ = 9 2 2 x²+y² = 5 x+y=?arrow_forwardFor each of the following series, determine whether the absolute convergence series test determines absolute convergence or fails. For the ¿th series, if the test is inconclusive then let Mi = 4, while if the test determines absolute convergence let Mi 1 : 2: ∞ Σ(−1)"+¹ sin(2n); n=1 Σ n=1 Σ ((−1)”. COS n² 3+2n4 3: (+ 4: 5 : n=1 ∞ n 2+5n3 ПП n² 2 5+2n3 пп n² Σ(+)+ n=1 ∞ n=1 COS 4 2 3+8n3 П ηπ n- (−1)+1 sin (+727) 5 + 2m³ 4 = 8. Then the value of cos(M₁) + cos(2M2) + cos(3M3) + sin(2M) + sin(M5) is -0.027 -0.621 -1.794 -1.132 -1.498 -4.355 -2.000 2.716arrow_forward
- i need help with this question i tried by myself and so i am uploadding the question to be quided with step by step solution and please do not use chat gpt i am trying to learn thank you.arrow_forwardi need help with this question i tried by myself and so i am uploadding the question to be quided with step by step solution and please do not use chat gpt i am trying to learn thank you.arrow_forward1. 3 2 fx=14x²-15x²-9x- 2arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Calculus: Early TranscendentalsCalculusISBN:9781285741550Author:James StewartPublisher:Cengage Learning
Thomas' Calculus (14th Edition)CalculusISBN:9780134438986Author:Joel R. Hass, Christopher E. Heil, Maurice D. WeirPublisher:PEARSON
Calculus: Early Transcendentals (3rd Edition)CalculusISBN:9780134763644Author:William L. Briggs, Lyle Cochran, Bernard Gillett, Eric SchulzPublisher:PEARSON
Calculus: Early TranscendentalsCalculusISBN:9781319050740Author:Jon Rogawski, Colin Adams, Robert FranzosaPublisher:W. H. Freeman
Calculus: Early Transcendental FunctionsCalculusISBN:9781337552516Author:Ron Larson, Bruce H. EdwardsPublisher:Cengage Learning
Calculus: Early Transcendentals
Calculus
ISBN:9781285741550
Author:James Stewart
Publisher:Cengage Learning
Thomas' Calculus (14th Edition)
Calculus
ISBN:9780134438986
Author:Joel R. Hass, Christopher E. Heil, Maurice D. Weir
Publisher:PEARSON
Calculus: Early Transcendentals (3rd Edition)
Calculus
ISBN:9780134763644
Author:William L. Briggs, Lyle Cochran, Bernard Gillett, Eric Schulz
Publisher:PEARSON
Calculus: Early Transcendentals
Calculus
ISBN:9781319050740
Author:Jon Rogawski, Colin Adams, Robert Franzosa
Publisher:W. H. Freeman
Calculus: Early Transcendental Functions
Calculus
ISBN:9781337552516
Author:Ron Larson, Bruce H. Edwards
Publisher:Cengage Learning
Find number of persons in a part with 66 handshakes Combinations; Author: Anil Kumar;https://www.youtube.com/watch?v=33TgLi-wp3E;License: Standard YouTube License, CC-BY
Discrete Math 6.3.1 Permutations and Combinations; Author: Kimberly Brehm;https://www.youtube.com/watch?v=J1m9sB5XZQc;License: Standard YouTube License, CC-BY
How to use permutations and combinations; Author: Mario's Math Tutoring;https://www.youtube.com/watch?v=NEGxh_D7yKU;License: Standard YouTube License, CC-BY
Permutations and Combinations | Counting | Don't Memorise; Author: Don't Memorise;https://www.youtube.com/watch?v=0NAASclUm4k;License: Standard Youtube License
Permutations and Combinations Tutorial; Author: The Organic Chemistry Tutor;https://www.youtube.com/watch?v=XJnIdRXUi7A;License: Standard YouTube License, CC-BY