Chapter 7.1, Problem 41STP

To determine

The total area of the rectangles.

Answer to Problem 41STP

  $2x+14$

Explanation of Solution

Given information:

   X 7

2

Concept Used:

Distributive property:

• Left Distributive property: $a\left(b\pm c\right)=a\cdot b\pm a\cdot c$
• Right Distributive property: $\left(a\pm b\right)c=a\cdot c\pm b\cdot c$

Rules of Addition/ Subtraction:

• Two numbers with similar sign always get added and the resulting number will carry the similar sign.
• Two numbers with opposite signs always get subtracted and the resulting number will carry the sign of larger number.

Rules of Multiplication/ Division:

• The product/quotient of two similar sign numbers is always positive.
• The product/quotient of two numbers with opposite signs is always negative.

Calculation:

In order to find the total area of the rectangle, first the area of rectangle is $l\times b$ ,l is length of rectangle and b is breadth of rectangle so the area of first rectangle is :

  $\begin{array}{l}2\times x\\ =2x\end{array}$

And the area of second rectangle is:

  $\begin{array}{l}2\times 7\\ =14\end{array}$

Then the total area of the rectangle is $2x+14$ .