MECHANICS OF MATERIAL IN SI UNITS
10th Edition
ISBN: 9781292178202
Author: HIBBELER
Publisher: PEARSON
expand_more
expand_more
format_list_bulleted
Textbook Question
Chapter 7.3, Problem 7.46P
The member consists of two plastic channel strips 0.5 in. thick, glued together at A and B. If the glue can support an allowable shear stress of τallow = 600 psi, determine the maximum intensity W0 of the triangular distributed loading that can be applied to the member based on the strength of the glue.
Prob. 7–46
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
8. All of the members in the Warren truss of Figure 8 are of length 10 ft. Use the method of
sections to determine the forces in the members BD,CD,CE.
B
A
C
D
E
F
G
2000 lb
3000 lb
5000 lb
Figure 8
H
An acrobat is walking on a tightrope of length L
=20.1 m attached to supports A and B at a
distance of 20.0 m apart. The combined weight
of the acrobat and his balancing pole is 900 N,
and the friction between his shoes and the rope
is large enough to prevent him from slipping.
Neglecting the weight of the rope and any
elastic deformation, determine the deflection (y)
and the tension in portion AC and BC of the
rope for values of x from 0.5 m to 10 m using
0.5 m increments.
1. Determine the maximum deflection (y) in
the rope.
2. Plot tension of AC and BC vs. x (on the
same plot with x on the x-axis). Turn in the
plot and the table of x, TAC, and TBC (clearly
label each).
A
C
20.0 m
B
5. A 4000 lb block of concrete is attached by light inextensible cables to the truss in Figure 5.
Determine the force in each member. State whether each member is in tension or compression.
3
ΘΑ
D
E
cables
all dimensions in feet.
Chapter 7 Solutions
MECHANICS OF MATERIAL IN SI UNITS
Ch. 7.2 - In each case, calculate the value of Q and t that...Ch. 7.2 - If the beam is subjected to a shear force of V =...Ch. 7.2 - Determine the shear stress at points A and B if...Ch. 7.2 - Determine the absolute maximum shear stress in the...Ch. 7.2 - If the beam is subjected to a shear force of V =20...Ch. 7.2 - If the beam is made from four plates and subjected...Ch. 7.2 - If the wide-flange beam is subjected to a shear of...Ch. 7.2 - If the wide-flange beam is subjected to a shear of...Ch. 7.2 - If the wide-flange beam is subjected to a shear of...Ch. 7.2 - If the beam is subjected to a shear of V = 30 kN,...
Ch. 7.2 - If the wide-flange beam is subjected to a shear of...Ch. 7.2 - The wood beam has an allowable shear stress of...Ch. 7.2 - The shaft is supported by a thrust bearing at A...Ch. 7.2 - The shaft is supported by a thrust bearing at A...Ch. 7.2 - Determine the largest shear force V that the...Ch. 7.2 - If the applied shear force V = 18 kip, determine...Ch. 7.2 - The overhang beam is subjected to the uniform...Ch. 7.2 - The beam is made from a polymer and is subjected...Ch. 7.2 - Determine the maximum shear stress in the strut if...Ch. 7.2 - Determine the maximum shear force V that the strut...Ch. 7.2 - Sketch the intensity of the shear-stress...Ch. 7.2 - Plot the shear-stress distribution over the cross...Ch. 7.2 - If the beam is subjected to a shear of V=15 kN,...Ch. 7.2 - If the wide-flange beam is subjected to a shear of...Ch. 7.2 - If the wide-flange beam is subjected to a shear of...Ch. 7.2 - Determine the length of the cantilevered beam so...Ch. 7.2 - If the beam is made from wood having an allowable...Ch. 7.2 - Determine the largest intensity w of the...Ch. 7.2 - If w=800 lb/ft, determine the absolute maximum...Ch. 7.2 - Determine the shear stress at point B on the web...Ch. 7.2 - Determine the maximum shear stress acting at...Ch. 7.2 - Railroad ties must be designed to resist large...Ch. 7.2 - The beam is slit longitudinally along both sides....Ch. 7.2 - The beam is to be cut longitudinally along both...Ch. 7.2 - The composite beam is constructed from wood and...Ch. 7.2 - The beam has a rectangular cross section and is...Ch. 7.2 - The beam in Fig.6-48f is subjected to a fully...Ch. 7.3 - The two identical boards are bolted together to...Ch. 7.3 - Two identical 20-mm-thick plates are bolted to the...Ch. 7.3 - The boards are bolted together to form the...Ch. 7.3 - The boards are bolted together to form the...Ch. 7.3 - The beam is constructed from two boards fastened...Ch. 7.3 - The beam is constructed from two boards fastened...Ch. 7.3 - The beam is constructed from three boards. If it...Ch. 7.3 - The beam is constructed from three boards....Ch. 7.3 - The double T-beam is fabricated by welding the...Ch. 7.3 - The double T-beam is fabricated by welding the...Ch. 7.3 - The beam is constructed from three boards....Ch. 7.3 - A beam is constructed from three boards bolted...Ch. 7.3 - The simply supported beam is built up from three...Ch. 7.3 - The simply supported beam is built up from three...Ch. 7.3 - The T-beam is constructed as shown. If each nail...Ch. 7.3 - The box beam is constructed from four boards that...Ch. 7.3 - The box beam is constructed from four boards that...Ch. 7.3 - The member consists of two plastic channel strips...Ch. 7.3 - The member consists of two plastic channel strips...Ch. 7.3 - The beam is made from four boards nailed together...Ch. 7.3 - The beam is made from three polystyrene strips...Ch. 7.5 - A shear force of V=300 kN is applied to the box...Ch. 7.5 - A shear force of V=450 kN is applied to the box...Ch. 7.5 - A shear force of V = 18 kN is applied to the box...Ch. 7.5 - A shear force of V = 18 kN is applied to the box...Ch. 7.5 - The aluminum strut is 10 mm thick and has the...Ch. 7.5 - The aluminum strut is 10 mm thick and has the...Ch. 7.5 - The beam is subjected to a shear force of V=50...Ch. 7.5 - The beam is subjected to a shear force of V=50...Ch. 7.5 - The H-beam is subjected to a shear of V=80 kN...Ch. 7.5 - The H-beam is subjected to a shear of V=80 kN...Ch. 7.5 - The built-up beam is formed by welding together...Ch. 7.5 - The assembly is subjected to a vertical shear of V...Ch. 7.5 - The box girder is subjected to a shear of V=15 kN....Ch. 7.5 - Determine the location e of the shear center,...Ch. 7.5 - Determine the location e of the shear center,...Ch. 7.5 - The beam supports a vertical shear of V=7 kip....Ch. 7.5 - The stiffened beam is constructed from plates...Ch. 7.5 - The pipe is subjected to a shear force of V=8 kip....Ch. 7.5 - Determine the location e of the shear center,...Ch. 7.5 - A thin plate of thickness t is bent to form the...Ch. 7.5 - Determine the location e of the shear center,...Ch. 7 - The beam is fabricated from four boards nailed...Ch. 7 - The T-beam is subjected to a shear of V = 150 kN....Ch. 7 - The member is subject to a shear force of V = 2...Ch. 7 - Determine the shear stress at points B and C on...Ch. 7 - Determine the maximum shear stress acting at...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Similar questions
- A block hangs from the end of bar AB that is 5.80 meters long and connected to the wall in the xz plane. The bar is supported at end A by a ball joint such that it carries only a compressive force along its axis. The bar is supported in equilibrium at end B by cables BD and BC that connect to the xz plane at points C and D respectively with coordinates given in the figure. The z components of the moments exerted on the bar by these two cables sum to 0. The tension in cable BD is measured to be 210 Newtons. Input answers of zero as 0.00 to avoid an invalid answer due to significant figures. Determine the equivalent force and couple system acting at A that models only the forces exerted by both cables BD → and BC on the bar at B. Enter your results for Feq and Meg in Cartesian Components. Z D (c, 0, d) C (a, 0, b). X A f m B y cc 040 BY NC SA 2016 Eric Davishahl Values for dimensions on the figure are given in the following table. Note the figure may not be to scale. Variable Value a…arrow_forwardA bent tube is attached to a wall with brackets as shown. A force of F = 785 lb is applied to the end of the tube with direction indicated by the dimensions in the figure. a.) Determine the moment about point D due to the force F Enter your answer in Cartesian components with units of ft- lbs. b.) Determine the moment about a line (i.e. axis) running from D to C due to the force F. Enter your answer in Cartesian components with units of ft-lbs. 2013 Michael Swanbom x BY NC SA g Z h A с FK kaz Values for dimensions on the figure are given in the table below. Note the figure may not be to scale. Be sure to align your cartesian unit vectors with the coordinate axes shown in the figure. Variable Value α 4.84 in b 13.2 in с 12.5 in d 30.8 in h 18.7 in 22.0 in →> a. MD=( i+ k) ft- lb →> b. MDC = î + k) ft- lbarrow_forwardF1 3 4 5 P F2 F2 Ꮎ e b 200 3 4 5 F1 The electric pole is subject to the forces shown. Force F1 245 N and force F2 = 310 N with an angle 0 = 20.2°. Determine the moment about point P of all forces. Take counterclockwise moments to be positive. = Values for dimensions on the figure are given in the following table. Note the figure may not be to scale. Variable Value a 2.50 m b 11.3 m с 13.0 m The moment about point P is m. N- If the moment about point P sums up to be zero. Determine the distance c while all other values remained the same. m.arrow_forward
- F y b C 10 Z Determine the moment about O due to the force F shown, the magnitude of the force F = 76.0 lbs. Note: Pay attention to the axis. Values for dimensions on the figure are given in the following table. Note the figure may not be to scale. Variable Value a 1.90 ft b 2.80 ft с 2.60 ft d 2.30 ft Mo = lb + k) ft-arrow_forwardThe shelf bracket is subjected to the force F = 372 Newtons at an angle = 21.4°. Compute the moment (in N-m) that this force exerts about each of the two attachment points (screw locations in the figure). Take counterclockwise moments to be positive. a duk F -0 2013 cc Michael Swanbom BY NC O SA Values for dimensions on the figure are given in the following table. Note the figure may not be to scale. Variable Value a 43.0 cm b 32.3 cm с 2.58 cm The moment about the upper attachment point is N-m. The moment about the lower attachment point is N-m.arrow_forwardA man skis down a slope. His initial elevation was 150 m and his velocity at the bottom of the slope is 17 m/s. What percentage of his initial potential energy was consumed due to friction and air resistance? Use the accounting equation in your calculations.arrow_forward
- In direct calorimetry, a person is placed in a large, water-insulated chamber. The chamber is kept at a constant temperature. While in the chamber, the subject is asked to perform a number of normal activities, such as eating, sleeping, and exercising. The rate of heat released from the subject’s body can be measured by the rate of heat gain by the water bath. Would direct calorimetry be a practical way to measure metabolic rate? Why or why not?A person is placed inside a calorimetric chamber for 24 hours. During this time, the 660-gallon water bath heats up by 3.2°F. What is the subject’s metabolic rate during this period? Report your answer in kcal/day. Assume that there is no heat loss from the water to the surroundings.arrow_forwardUpon reentry into the Earth’s atmosphere, the bottom of a space shuttle heats up to dangerous levels as the craft slows for landing. If the velocity of the shuttle is 28,500 km/hr at the beginning of reentry and 370 km/hr just prior to landing, how much energy is lost as heat? The shuttle has a mass of 90,000 kg. Assume that the change in potential energy is negligible compared to the change in kinetic energy.arrow_forwardof the basket of the balloon at point A, and their other ends are staked to the ground. The hook is located in the geometric center of the basket. The balloon and the air inside it have a combined mass of 3000 kg. You want to determine the resultant of the tension forces in the four cables acting on the hook at point A. It is known that the magnitudes of the tension in the cables are as follows: TAB = 207 N; TAC = 355 N; TAD = 250 N; and TAE = 486 N. B E 2.5 m C E 5.5 m D 2.5 m 3.5 m 1.5 m Using the information provided in the problem, express the force on the hook at point A by cable AC in rectangular component form. The force on the hook at point A by cable AC in rectangular component form is given below. T AC N) i+ N) + N) Rarrow_forward
- Water in the glass tube is at a temperature of 40°C. Plot the height of the water as a function of the tube's inner diameter D for 0.5mm≤D≤3mm. Use increments of 0.5mm. Take sigma=69.6mN/m, and theta=0° for the contact angle.arrow_forwardDetermine the distance h that the column of mercury in the tube will be depressed when the tube is inserted into the mercury at a room temperature of 68 F. Plot this relationship of h (vertical axis) versus D for 0.5 in≤D≤0.150in. Give values for increments of ΔD=0.025in. Discuss this resultarrow_forwardWater is at a temperature of 30 C. Plot the height h of the water as a function of the gap w between the two glass plates for 0.4 mm ≤ w ≤ 2.4 mm. Use increments of 0.4mm. Take sigma=0.0718 N/m.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Elements Of ElectromagneticsMechanical EngineeringISBN:9780190698614Author:Sadiku, Matthew N. O.Publisher:Oxford University PressMechanics of Materials (10th Edition)Mechanical EngineeringISBN:9780134319650Author:Russell C. HibbelerPublisher:PEARSONThermodynamics: An Engineering ApproachMechanical EngineeringISBN:9781259822674Author:Yunus A. Cengel Dr., Michael A. BolesPublisher:McGraw-Hill Education
- Control Systems EngineeringMechanical EngineeringISBN:9781118170519Author:Norman S. NisePublisher:WILEYMechanics of Materials (MindTap Course List)Mechanical EngineeringISBN:9781337093347Author:Barry J. Goodno, James M. GerePublisher:Cengage LearningEngineering Mechanics: StaticsMechanical EngineeringISBN:9781118807330Author:James L. Meriam, L. G. Kraige, J. N. BoltonPublisher:WILEY
Elements Of Electromagnetics
Mechanical Engineering
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Oxford University Press
Mechanics of Materials (10th Edition)
Mechanical Engineering
ISBN:9780134319650
Author:Russell C. Hibbeler
Publisher:PEARSON
Thermodynamics: An Engineering Approach
Mechanical Engineering
ISBN:9781259822674
Author:Yunus A. Cengel Dr., Michael A. Boles
Publisher:McGraw-Hill Education
Control Systems Engineering
Mechanical Engineering
ISBN:9781118170519
Author:Norman S. Nise
Publisher:WILEY
Mechanics of Materials (MindTap Course List)
Mechanical Engineering
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Cengage Learning
Engineering Mechanics: Statics
Mechanical Engineering
ISBN:9781118807330
Author:James L. Meriam, L. G. Kraige, J. N. Bolton
Publisher:WILEY
Differences between Temporary Joining and Permanent Joining.; Author: Academic Gain Tutorials;https://www.youtube.com/watch?v=PTr8QZhgXyg;License: Standard Youtube License