
(a)
Interpretation:
The intermolecular forces presented in the given molecules
Concept introduction:
- Polarity of a bond is due to the difference in electro-negativities of atoms presented in it. The polarities of bonds are represented by using vectors.
- If the result of all bond polarities or vector sum is non-zero in a molecule, then the molecule is called as polar molecule.
- If the result of all bond polarities or vector sum is zero in a molecule, then the molecule is called as nonpolar molecule.
- Intermolecular force is the set of repulsive and attractive forces between molecules that result from the polarity between neighboring molecules. There are four types of intermolecular forces.
- Dipole – Dipole interaction: This force takes place between polar compounds.
- Hydrogen bonding is a type of dipole-dipole interaction of molecules when the hydrogen is bonded to strong electronegative atom (F, O, N, etc) in the molecules.
- Dispersion force is a weak force and this force is present in all compounds force.
To determine: intermolecular forces presented in
(b)
Interpretation:
The intermolecular forces presented in the given molecules
Concept introduction:
- Polarity of a bond is due to the difference in electro-negativities of atoms presented in it. The polarities of bonds are represented by using vectors.
- If the result of all bond polarities or vector sum is non-zero in a molecule, then the molecule is called as polar molecule.
- If the result of all bond polarities or vector sum is zero in a molecule, then the molecule is called as nonpolar molecule.
- Intermolecular force is the set of repulsive and attractive forces between molecules that result from the polarity between neighboring molecules. There are four types of intermolecular forces.
- Dipole – Dipole interaction: This force takes place between polar compounds.
- Hydrogen bonding is a type of dipole-dipole interaction of molecules when the hydrogen is bonded to strong electronegative atom (F, O, N, etc) in the molecules.
- Dispersion force is a weak force and this force is present in all compounds force.
To determine: intermolecular forces presented in
(c)
Interpretation:
The intermolecular forces presented in the given molecules
Concept introduction:
- Polarity of a bond is due to the difference in electro-negativities of atoms presented in it. The polarities of bonds are represented by using vectors.
- If the result of all bond polarities or vector sum is non-zero in a molecule, then the molecule is called as polar molecule.
- If the result of all bond polarities or vector sum is zero in a molecule, then the molecule is called as nonpolar molecule.
- Intermolecular force is the set of repulsive and attractive forces between molecules that result from the polarity between neighboring molecules. There are four types of intermolecular forces.
- Dipole – Dipole interaction: This force takes place between polar compounds.
- Hydrogen bonding is a type of dipole-dipole interaction of molecules when the hydrogen is bonded to strong electronegative atom (F, O, N, etc) in the molecules.
- Dispersion force is a weak force and this force is present in all compounds force.
To determine: intermolecular forces presented in
(d)
Interpretation:
The intermolecular forces presented in the given molecules
Concept introduction:
- Polarity of a bond is due to the difference in electro-negativities of atoms presented in it. The polarities of bonds are represented by using vectors.
- If the result of all bond polarities or vector sum is non-zero in a molecule, then the molecule is called as polar molecule.
- If the result of all bond polarities or vector sum is zero in a molecule, then the molecule is called as nonpolar molecule.
- Intermolecular force is the set of repulsive and attractive forces between molecules that result from the polarity between neighboring molecules. There are four types of intermolecular forces.
- Dipole – Dipole interaction: This force takes place between polar compounds.
- Hydrogen bonding is a type of dipole-dipole interaction of molecules when the hydrogen is bonded to strong electronegative atom (F, O, N, etc) in the molecules.
- Dispersion force is a weak force and this force is present in all compounds force.
To determine: intermolecular forces presented in

Want to see the full answer?
Check out a sample textbook solution
Chapter 7 Solutions
GEN COMBO CHEMISTRY: ATOMS FIRST; ALEKS 360 2S ACCESS CARD CHEMISTRY:ATOMS FIRST
- What alkene or alkyne yields the following products after oxidative cleavage with ozone? Click the "draw structure" button to launch the drawing utility. and two equivalents of CH2=O draw structure ...arrow_forwardH-Br Energy 1) Draw the step-by-step mechanism by which 3-methylbut-1-ene is converted into 2-bromo-2-methylbutane. 2) Sketch a reaction coordinate diagram that shows how the internal energy (Y- axis) of the reacting species change from reactants to intermediate(s) to product. Brarrow_forward2. Draw the missing structure(s) in each of the following reactions. The missing structure(s) can be a starting material or the major reaction product(s). C5H10 H-CI CH2Cl2 CIarrow_forward
- Draw the products of the stronger acid protonating the other reactant. དའི་སྐད”“ H3C OH H3C CH CH3 KEq Product acid Product basearrow_forwardDraw the products of the stronger acid protonating the other reactant. H3C NH2 NH2 KEq H3C-CH₂ 1. Product acid Product basearrow_forwardWhat alkene or alkyne yields the following products after oxidative cleavage with ozone? Click the "draw structure" button to launch the drawing utility. draw structure ... andarrow_forward
- Draw the products of the stronger acid protonating the other reactant. H3C-C=C-4 NH2 KEq CH H3C `CH3 Product acid Product basearrow_forward2. Draw the missing structure(s) in each of the following reactions. The missing structure(s) can be a starting material or the major reaction product(s). C5H10 Br H-Br CH2Cl2 + enant.arrow_forwardDraw the products of the stronger acid protonating the other reactant. KEq H₂C-O-H H3C OH Product acid Product basearrow_forward
- Draw the products of the stronger acid protonating the other reactant. OH KEq CH H3C H3C `CH3 Product acid Product basearrow_forward2. Draw the missing structure(s) in each of the following reactions. The missing structure(s) can be a starting material or the major reaction product(s). Ph H-I CH2Cl2arrow_forward3 attempts left Check my work Draw the products formed in the following oxidative cleavage. [1] 03 [2] H₂O draw structure ... lower mass product draw structure ... higher mass productarrow_forward
- Chemistry for Today: General, Organic, and Bioche...ChemistryISBN:9781305960060Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. HansenPublisher:Cengage LearningChemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage Learning
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistry: An Atoms First ApproachChemistryISBN:9781305079243Author:Steven S. Zumdahl, Susan A. ZumdahlPublisher:Cengage Learning




