Chapter 7.3, Problem 12SC

Explanation of Solution

Tracing the Self Check 11:

key	inFile	outFile	i	arg
3	null	null	0	-d
-3	file1.txt		1	file1.txt
			2

Iteration 1:

• Initially, the “key” value contains 3 because the “key” variable is assigned with the “DEFAULT_KEY” value which means 3.
• The “inFile” and “outFile” contains “null” value.
• In first iteration, the “i” value contains 0.
• The “arg” is assigned with the “args[i]” which means “-d” to the “arg” variable.

Iteration 2:

• The “key” value contains -3 because the “key” variable is assigned with the “-key” value which means -3...