Big Java Late Objects
2nd Edition
ISBN: 9781119330455
Author: Horstmann
Publisher: WILEY
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Question
Chapter 7, Problem 6PE
Program Plan Intro
Calculate the average of 2 columns
Program plan:
Filename: “AverageColumns.java”
- Include the required header files.
- Define the “AverageColumns” class
- Define the main method.
- Create an object for “Scanner” class.
- Get the input file name from the user.
- In “try” block, declare an object for “Scanner” class and pass the file name.
- Declare the required variables with the values.
- Check the file has any content
- Calculate the “sum1” and “sum2”
- Increment the value
- Display the average of column 1 and column 2.
- In “catch” block, throw a “FileNotFoundException”.
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Students have asked these similar questions
Exercise 1 Function and Structure [30 pts]
Please debug the following program and answer the following questions. There is a cycle in a linked
list if some node in the list can be reached again by continuously following the next pointer.
#include
typedef struct node {
int value;
struct node *next;
} node;
int 11_has_cycle (node *first)
if (first
==
node *head =
{
NULL) return 0;
first;
while (head->next != NULL) {
}
if (head
first) {
return 1; }
head = head->next;
return 0;
void test ll_has_cycle () {
int i;
node nodes [6];
for (i = 0; i < 6; i++) {
nodes [i] .next = NULL;
nodes [i].value = i;
}
nodes [0] .next
=
&nodes [1];
nodes [1] .next
=
&nodes [2];
nodes [2] .next
=
&nodes [3];
nodes [3] .next
nodes [4] .next
&nodes [4];
NULL;
nodes [5] .next = &nodes [0];
printf("1. Checking first list for cycles. \n Function 11_has_cycle says it
has s cycle\n\n", 11_has_cycle (&nodes [0])?"a":"no");
printf("2. Checking length-zero list for cycles. \n Function 11_has_cycle
says it has %s…
how to read log logs
Discrete Mathematics for Computer Engineering
Chapter 7 Solutions
Big Java Late Objects
Ch. 7.1 - Prob. 1SCCh. 7.1 - Prob. 2SCCh. 7.1 - Prob. 3SCCh. 7.1 - Prob. 4SCCh. 7.1 - Prob. 5SCCh. 7.2 - Prob. 6SCCh. 7.2 - Prob. 7SCCh. 7.2 - Prob. 8SCCh. 7.2 - Prob. 9SCCh. 7.2 - Prob. 10SC
Ch. 7.3 - Prob. 11SCCh. 7.3 - Prob. 12SCCh. 7.3 - Prob. 13SCCh. 7.3 - Prob. 14SCCh. 7.3 - Prob. 15SCCh. 7.4 - Prob. 16SCCh. 7.4 - Prob. 17SCCh. 7.4 - Prob. 18SCCh. 7.4 - Prob. 19SCCh. 7.4 - Prob. 20SCCh. 7.4 - Prob. 21SCCh. 7.5 - Prob. 22SCCh. 7.5 - Prob. 23SCCh. 7.5 - Prob. 24SCCh. 7.5 - Prob. 25SCCh. 7.5 - Prob. 26SCCh. 7 - Prob. 1RECh. 7 - Prob. 2RECh. 7 - Prob. 3RECh. 7 - Prob. 4RECh. 7 - Prob. 5RECh. 7 - Prob. 6RECh. 7 - Prob. 7RECh. 7 - Prob. 8RECh. 7 - Prob. 9RECh. 7 - Prob. 10RECh. 7 - Prob. 11RECh. 7 - Prob. 12RECh. 7 - Prob. 13RECh. 7 - Prob. 14RECh. 7 - Prob. 15RECh. 7 - Prob. 16RECh. 7 - Prob. 17RECh. 7 - Prob. 18RECh. 7 - Prob. 1PECh. 7 - Prob. 2PECh. 7 - Prob. 3PECh. 7 - Prob. 4PECh. 7 - Prob. 5PECh. 7 - Prob. 6PECh. 7 - Prob. 7PECh. 7 - Prob. 8PECh. 7 - Prob. 9PECh. 7 - Prob. 10PECh. 7 - Prob. 11PECh. 7 - Prob. 12PECh. 7 - Prob. 1PPCh. 7 - Prob. 2PPCh. 7 - Prob. 3PPCh. 7 - Prob. 4PPCh. 7 - Prob. 5PPCh. 7 - Prob. 6PPCh. 7 - Prob. 7PPCh. 7 - Prob. 8PPCh. 7 - Prob. 9PPCh. 7 - Prob. 10PPCh. 7 - Prob. 11PPCh. 7 - Prob. 12PPCh. 7 - Prob. 13PP
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