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Single Variable Calculus: Early Transcendentals (2nd Edition) - Standalone book
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- By expanding (xh)2+(yk)2=r2, we obtain x22hx+h22ky+k2r2=0. When we compare this result to the form x2+y2+Dx+Ey+F=0, we see that D=2h,E=2k, and F=h2+k2r2. Therefore, the center and the length of a radius of a circle can be found by using h=D2,k=E2 and r=h2+k2F. Use these relationship to find the center and the length of the radius of each of the following circles. x2+y2+4x14y+49=0arrow_forwardUse integration by parts to evaluate 2x cos (x) dx (A -x?cos (x) +c (B В - 2x cos (x) + 2sin (x) +c x²sin (x) +2xcos (x) +c (D) 2x sin (x) + 2cos (x) +c E None of the other answers F 2x sin (x) – 2 cos (x) +carrow_forwardEvaluate the following: Integration by substitution i need solutionarrow_forward
- 3: Please help me answer the followingarrow_forwardFind Hence evaluate d -1 dx /1+x² 1 I Lo (1+2273/2 da. 0arrow_forwardUse integration by parts to evaluate cos (x) dx A -x?cos (x) +c В - 2x cos (x) + 2sin (x) + c c) x²sin (x) + 2xcos (x) + c D 2x sin (x) + 2cos (x) +c E None of the other answers F 2x sin (x) – 2 cos (x) +carrow_forward
- Intermediate AlgebraAlgebraISBN:9781285195728Author:Jerome E. Kaufmann, Karen L. SchwittersPublisher:Cengage LearningCollege Algebra (MindTap Course List)AlgebraISBN:9781305652231Author:R. David Gustafson, Jeff HughesPublisher:Cengage Learning
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