The reason for not using an amide ion to form a carbanion from an alkane has to be given. Concept Introduction: In a reaction which strongly favours the formation of products, the base used to remove proton from the acid should be stronger than the base formed when the proton is removed. Order of electronegativity of carbon atoms: sp > sp 2 > sp 3 Most electronegative is the sp hybridized carbon atom. The most acidic compound will be the hydrogen which is attached to the most electronegative carbon.

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Chapter 7.10, Problem 22P

Interpretation Introduction

Interpretation:

The reason for not using an amide ion to form a carbanion from an alkane has to be given.

Concept Introduction:

In a reaction which strongly favours the formation of products, the base used to remove proton from the acid should be stronger than the base formed when the proton is removed.

Order of electronegativity of carbon atoms:

sp > sp2 > sp3

Most electronegative is the sp hybridized carbon atom.

The most acidic compound will be the hydrogen which is attached to the most electronegative carbon.

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