
Concept explainers
(a)
Interpretation:
The reagent used for the synthesis of the given compound should be determined.
Concept Introduction:
Deprotonation: The reaction in which proton is removed from the compound using reagents is known as deprotonation.
Different reagents are used for the deprotonation and one of the common reagent is sodium amide.
Lindlar catalyst: The catalyst is used for the hydrogenation of alkynes in a syn manner. This means both hydrogen are added on the same side across the triple bond and the product obtained will be a cis product.
Sodium in liquid ammonia: The catalyst is used for the formation of trans
(b)
Interpretation:
The reagent used for the synthesis of the given compound should be determined.
Concept Introduction:
Deprotonation: The reaction in which proton is removed from the compound using reagents is known as deprotonation.
Different reagents are used for the deprotonation and one of the common reagent is sodium amide.
Lindlar catalyst: The catalyst is used for the hydrogenation of alkynes in a syn manner. This means both hydrogen are added on the same side across the triple bond and the product obtained will be a cis product.
Sodium in liquid ammonia: The catalyst is used for the formation of trans alkenes from alkynes. Because of its more reactivity towards triple bonds, the reaction will stop at the formation of alkenes.
(c)
Interpretation:
The reagent used for the synthesis of the given compound should be determined.
Concept Introduction:
Deprotonation: The reaction in which proton is removed from the compound using reagents is known as deprotonation.
Different reagents are used for the deprotonation and one of the common reagent is sodium amide.
Lindlar catalyst: The catalyst is used for the hydrogenation of alkynes in a syn manner. This means both hydrogen are added on the same side across the triple bond and the product obtained will be a cis product.
Sodium in liquid ammonia: The catalyst is used for the formation of trans alkenes from alkynes. Because of its more reactivity towards triple bonds, the reaction will stop at the formation of alkenes.

Want to see the full answer?
Check out a sample textbook solution
Chapter 7 Solutions
ORGANIC CHEMISTRY-W/S.G+SOLN.MANUAL
- So, the first image is what I'm trying to understand regarding my approach. The second image illustrates my teacher's method, and the third image includes my notes on the concepts behind these types of problems.arrow_forwardHAND DRAWarrow_forwardDraw a mental model for calcium chloride mixed with sodium phosphatearrow_forward
- here is my question (problem number 20) please explain to me thanks!arrow_forwardThe bromination of anisole is an extremely fast reaction. Complete the resonance structures of the intermediate arenium cation for the reaction (Part 1), and then answer the question that follows (Part 2).arrow_forwardDrawing of 3-fluro-2methylphenolarrow_forward
- Which compound(s) will be fully deprotonated (>99%) by reaction with one molar equivalent of sodium hydroxide? I, II, III I, || I, III I only II, III SH | H3C-C=C-H || III NH2arrow_forwardWill NBS (and heat or light) work for this reaction, or do we have to use Br2?arrow_forwardHAND DRAWarrow_forward
- Organic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage Learning
