Interpretation Introduction To find: The velocity of an emitted electron. Explanation Given: The threshold frequency is ν = 2 .25 × 10 14 s − 1 . The wavelength used is 5.00 × 10 − 7 m . Explanation: The threshold frequency ν is related to the binding energy ϕ as follows: ϕ = h ν Here, h is Planck’s constant. Calculate the binding energy by substituting the values as follows: ϕ = h ν = 6.626 × 10 − 34 J .s × 2 .25 × 10 14 s − 1 = 14 .908 × 10 − 20 J The energy of a photon is related to the wavelength as follows: E = h c λ Here, E ( 1 photon ) is the energy of one photon, h is Planck’s constant, λ is the wavelength, and c is the speed of light. Calculate the energy of used photon by substituting the values as follows: E = h c λ = ( 6.626 × 10 − 34 J .s ) × ( 3.0 × 10 8 ms − 1 ) 5.00 × 10 − 7 m = 39

Chemistry: A Molecular Approach (4th Edition)

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ISBN: 9780134112831

Author: Nivaldo J. Tro

Publisher: PEARSON

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Chapter 7, Problem 99E

Interpretation Introduction

To find: The velocity of an emitted electron.

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Chapter 7, Problem 98E

Chapter 7, Problem 100E

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Chemistry: A Molecular Approach (4th Edition)

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