Connect 1-Semester Access Card for General, Organic, and Biochemistry
9th Edition
ISBN: 9781259815096
Author: Katherine J Denniston, Joseph J Topping, Dr Danae Quirk Dorr
Publisher: McGraw-Hill Education
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Chapter 7, Problem 8CP
Interpretation Introduction
Interpretation:
A person spent the entire morning in a
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When an unknown amine reacts with an unknown acid chloride, an amide with a molecular mass of 163 g/mol (M* = 163 m/z)
is formed. In the infrared spectrum, important absorptions appear at 1661, 750 and 690 cm. The 13C NMR and DEPT spectra
are provided. Draw the structure of the product as the resonance contributor lacking any formal charges.
13C NMR
DEPT 90
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160
120
80
40
0
200
160
120
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0
DEPT 135
T
200
160
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Draw the unknown amide.
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Chapter 7 Solutions
Connect 1-Semester Access Card for General, Organic, and Biochemistry
Ch. 7.1 - Prob. 7.1PPCh. 7.1 - Are the following processes exothermic or...Ch. 7.1 - Prob. 7.2QCh. 7.1 - Prob. 7.3QCh. 7.1 - Prob. 7.4QCh. 7.1 - Prob. 7.2PPCh. 7.1 - Predict whether a reaction with positive ΔH and...Ch. 7.1 - Prob. 7.6QCh. 7.2 - Prob. 7.3PPCh. 7.2 - Prob. 7.4PP
Ch. 7.2 - Prob. 7.7QCh. 7.2 - Prob. 7.8QCh. 7.2 - Prob. 7.5PPCh. 7.3 - Prob. 7.9QCh. 7.3 - Prob. 7.10QCh. 7.3 - Prob. 7.11QCh. 7.3 - Prob. 7.12QCh. 7.3 - Prob. 7.6PPCh. 7.4 - Prob. 7.13QCh. 7.4 - Prob. 7.14QCh. 7.4 - Prob. 7.15QCh. 7.4 - Prob. 7.16QCh. 7.4 - Prob. 7.7PPCh. 7.4 - Prob. 7.8PPCh. 7.4 - Prob. 7.17QCh. 7.4 - Prob. 7.18QCh. 7.4 - Prob. 7.9PPCh. 7.4 - Prob. 7.10PPCh. 7.4 - Prob. 7.11PPCh. 7 - Prob. 7.19QPCh. 7 - State the second law of thermodynamics.
Ch. 7 - Describe what is meant by an exothermic reaction.
Ch. 7 - Describe what is meant by an endothermic...Ch. 7 - Prob. 7.23QPCh. 7 - Prob. 7.24QPCh. 7 - Explain what is meant by the term free energy....Ch. 7 - Prob. 7.26QPCh. 7 - Prob. 7.27QPCh. 7 - Prob. 7.28QPCh. 7 - Predict whether each of the following processes...Ch. 7 - Predict whether each of the following processes...Ch. 7 - Prob. 7.31QPCh. 7 - Energy is required to break chemical bonds during...Ch. 7 - Prob. 7.33QPCh. 7 - Prob. 7.34QPCh. 7 - Prob. 7.35QPCh. 7 - Prob. 7.36QPCh. 7 - Prob. 7.37QPCh. 7 - Prob. 7.38QPCh. 7 - What are the energy units most commonly employed...Ch. 7 - What energy unit is commonly employed in nutrition...Ch. 7 - Prob. 7.41QPCh. 7 - Prob. 7.42QPCh. 7 - A 5.00-g sample of octane is burned in a bomb...Ch. 7 - Prob. 7.44QPCh. 7 - A 30-g sample of chips is burned in a bomb...Ch. 7 - Prob. 7.46QPCh. 7 - Prob. 7.47QPCh. 7 - Prob. 7.48QPCh. 7 - Prob. 7.49QPCh. 7 - Prob. 7.50QPCh. 7 - Prob. 7.51QPCh. 7 - Prob. 7.52QPCh. 7 - Prob. 7.53QPCh. 7 - Lactase is an enzyme featured in Chapter 16,...Ch. 7 - Prob. 7.55QPCh. 7 - Prob. 7.56QPCh. 7 - Prob. 7.57QPCh. 7 - Prob. 7.58QPCh. 7 - Prob. 7.59QPCh. 7 - Prob. 7.60QPCh. 7 - Prob. 7.61QPCh. 7 - Prob. 7.62QPCh. 7 - Prob. 7.63QPCh. 7 - Prob. 7.64QPCh. 7 - For the equilibrium
the rate law is:
at 23°C, k...Ch. 7 - Prob. 7.66QPCh. 7 - Prob. 7.67QPCh. 7 - Prob. 7.68QPCh. 7 - Prob. 7.69QPCh. 7 - Prob. 7.70QPCh. 7 - Prob. 7.71QPCh. 7 - Prob. 7.72QPCh. 7 - Prob. 7.73QPCh. 7 - Label each of the following statements as true or...Ch. 7 - Prob. 7.75QPCh. 7 - Prob. 7.76QPCh. 7 - Prob. 7.77QPCh. 7 - Prob. 7.78QPCh. 7 - Prob. 7.79QPCh. 7 - Prob. 7.80QPCh. 7 - Prob. 7.81QPCh. 7 - Prob. 7.82QPCh. 7 - Prob. 7.83QPCh. 7 - Prob. 7.84QPCh. 7 - Prob. 7.85QPCh. 7 - Prob. 7.86QPCh. 7 - Prob. 7.87QPCh. 7 - Prob. 7.88QPCh. 7 - Prob. 7.89QPCh. 7 - Prob. 7.90QPCh. 7 - Prob. 7.91QPCh. 7 - Prob. 7.92QPCh. 7 - Prob. 7.93QPCh. 7 - Prob. 7.94QPCh. 7 - Prob. 7.95QPCh. 7 - Prob. 7.96QPCh. 7 - Prob. 7.97QPCh. 7 - Prob. 7.98QPCh. 7 - Prob. 7.99QPCh. 7 - Prob. 7.100QPCh. 7 - Prob. 7.101QPCh. 7 - Prob. 7.102QPCh. 7 - Prob. 7.103QPCh. 7 - Prob. 7.104QPCh. 7 - Prob. 7.105QPCh. 7 - Prob. 7.106QPCh. 7 - Predict the sign of G for perspiration...Ch. 7 - Prob. 2CPCh. 7 - Prob. 5CPCh. 7 - Prob. 6CPCh. 7 - Prob. 7CPCh. 7 - Prob. 8CP
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- Identify the unknown compound from its IR and proton NMR spectra. C4H6O: 'H NMR: 82.43 (1H, t, J = 2 Hz); 8 3.41 (3H, s); 8 4.10 (2H, d, J = 2 Hz) IR: 2125, 3300 cm¹ The C4H6O compound liberates a gas when treated with C2H5 MgBr. Draw the unknown compound. Select Draw с H Templates Morearrow_forwardPlease help with number 6 I got a negative number could that be right?arrow_forward1,4-Dimethyl-1,3-cyclohexadiene can undergo 1,2- or 1,4-addition with hydrogen halides. (a) 1,2-Addition i. Draw the carbocation intermediate(s) formed during the 1,2-addition of hydrobromic acid to 1,4-dimethyl-1,3-cyclohexadiene. ii. What is the major 1,2-addition product formed during the reaction in (i)? (b) 1,4-Addition i. Draw the carbocation intermediate(s) formed during the 1,4-addition of hydrobromic acid to 1,4-dimethyl-1,3-cyclohexadiene. ii. What is the major 1,4-addition product formed from the reaction in (i)? (c) What is the kinetic product from the reaction of one mole of hydrobromic acid with 1,4-dimethyl-1,3-cyclohexadiene? Explain your reasoning. (d) What is the thermodynamic product from the reaction of one mole of hydrobro-mic acid with 1,4-dimethyl-1,3-cyclohexadiene? Explain your reasoning. (e) What major product will result when 1,4-dimethyl-1,3-cyclohexadiene is treated with one mole of hydrobromic acid at - 78 deg * C ? Explain your reasoning.arrow_forward
- Give the product of the bimolecular elimination from each of the isomeric halogenated compounds. Reaction A Reaction B. КОВ CH₂ HotBu +B+ ко HOIBU +Br+ Templates More QQQ Select Cv Templates More Cras QQQ One of these compounds undergoes elimination 50x faster than the other. Which one and why? Reaction A because the conformation needed for elimination places the phenyl groups and to each other Reaction A because the conformation needed for elimination places the phenyl groups gauche to each other. ◇ Reaction B because the conformation needed for elimination places the phenyl groups gach to each other. Reaction B because the conformation needed for elimination places the phenyl groups anti to each other.arrow_forwardFive isomeric alkenes. A through each undergo catalytic hydrogenation to give 2-methylpentane The IR spectra of these five alkenes have the key absorptions (in cm Compound Compound A –912. (§), 994 (5), 1643 (%), 3077 (1) Compound B 833 (3), 1667 (W), 3050 (weak shoulder on C-Habsorption) Compound C Compound D) –714 (5), 1665 (w), 3010 (m) 885 (3), 1650 (m), 3086 (m) 967 (5), no aharption 1600 to 1700, 3040 (m) Compound K Match each compound to the data presented. Compound A Compound B Compound C Compound D Compoundarrow_forward7. The three sets of replicate results below were accumulated for the analysis of the same sample. Pool these data to obtain the most efficient estimate of the mean analyte content and the standard deviation. Lead content/ppm: Set 1 Set 2 Set 3 1. 9.76 9.87 9.85 2. 9.42 9.64 9.91 3. 9.53 9.71 9.42 9.81 9.49arrow_forward
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- A student proposes the transformation below in one step of an organic synthesis. There may be one or more reactants missing from the left-hand side, but there are no products missing from the right-hand side. There may also be catalysts, small inorganic reagents, and other important reaction conditions missing from the arrow. • Is the student's transformation possible? If not, check the box under the drawing area. • If the student's transformation is possible, then complete the reaction by adding any missing reactants to the left-hand side, and adding required catalysts, inorganic reagents, or other important reaction conditions above and below the arrow. • You do not need to balance the reaction, but be sure every important organic reactant or product is shown. + T G OH де OH This transformation can't be done in one step.arrow_forwardMacmillan Leaming Draw the major organic product of the reaction. 1. CH3CH2MgBr 2. H+ - G Select Draw Templates More H о QQarrow_forwardDraw the condensed structure of 3-hydroxy-2-butanone. Click anywhere to draw the first atom of your structure.arrow_forward
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