(a)
Interpretation:
The time taken by
Concept Introduction:
According to the integrated rate law for the first order reaction, the concentration of reactant is the exponential function of time. The equation that represents the integrated rate law for the first order kinetics is shown below.
The half-life of the particular
(b)
Interpretation:
The time taken by
Concept Introduction:
Same as part (a).
Want to see the full answer?
Check out a sample textbook solutionChapter 7 Solutions
Chemical Principles: The Quest for Insight
- Explain why half-lives are not normally used to describe reactions other than first order.arrow_forwardThe rate law for the reaction A + 3B → 2C + D was found to be v = k[A]2[B]2. (a) What are the units of k? (b) Express the rate law in terms of the rates of formation and consumption of A and C, respectively.arrow_forwardThe activation energy for the isomerization reaction CH3NC(g) → CH3CN(g) is 161 kJ mol−¹, and the reaction rate constant at 600 K is 0.41 s¯¹. (a) What is the value of the pre-exponential factor A for this reaction? (b) What is the value of the rate constant of the reaction at 1000 K?arrow_forward
- (d) The first-order rate constants for the fluorescence and phosphorescence of molecule X are 4.5 × 10" s' and 0.50 s', respectively. Briefly explain the large order of magnitude difference in the rate constant values. (e) Explain how long (in s) it takes for 1.0% of fluorescence and phosphorescence to occur following termination of excitation.arrow_forwardA second-order reaction of the type A + 2 B → P was carried out in a solution that was initially 0.050 mol dm−3 in A and 0.030 mol dm−3 in B. After 1.0 h the concentration of A had fallen to 0.040 mol dm−3. (a) Calculate the rate constant. (b) What is the half-life of each reactant?arrow_forward(iv) The activation energy, Ea, and pre-exponential factor, A, for the decomposition of N2O5: N2O5→ 2 NO2 + ½ O2 are: E = 102.2 kJ mol-1 and A = 2.81 x 1013 s-1. (a) Using these data calculate the rate constant of the reaction at 300 K. (b) Assuming the reaction is first order calculate the rate of the reaction, at 300 K, when the concentration of N2O5 is 0.015 mol L-1.arrow_forward
- (a) Define the following terms:(i) Collision frequency(ii) Rate constant (k)(b) The rate constant of a first order reaction increases from 4 X 10-2 to 24 X 10-2 when the temperature changes from 300 K to 350 K. Calculate the energy of activation (JEa). (log 2 = 0.301, log 3 = 0.4771, log 4 = 0.6021, log 6 = 0.7782)arrow_forwardChlorine atoms react with methane, forming HCl and CH3. The rate constant for the reaction is 6.00 × 107 M–1 s–1 at 298 K. The experiment was repeated at three other temperatures, resulting in the following data: Calculate the the activation energy for the reaction in kJ/molarrow_forwardAcetone is one of the most important solvents in organicchemistry, used to dissolve everything from fats and waxes toairplane glue and nail polish. At high temperatures, it decom-poses in a first-order process to methane and ketene(CH2=C=O). At 600C, the rate constant is 8.7x10^-3s⁻¹.(a) What is the half-life of the reaction?(b) How long does it take for 40.% of a sample of acetone todecompose?(c) How long does it take for 90.% of a sample of acetone todecompose?arrow_forward
- The reaction A + B → P is found to be first order in both A and B. The reaction was carried out in a solution that was initially 0.080 mol dm−3 in A and 0.060 mol dm−3 in B. After 1.0 h the concentration of B had fallen to 0.030 mol dm−3. (i) Calculate the rate constant. (ii) What are the half-lives of the reactants?arrow_forwardThe enzyme urease catalyzes the reaction of urea, 1NH2CONH22, with water to produce carbon dioxide and ammonia. In water, without the enzyme, the reaction proceeds with a first-order rate constant of 4.15 * 10-5 s-1 at 100 °C. In the presence of the enzyme in water, the reaction proceeds with a rate constant of 3.4 * 104 s-1 at 21 °C. (a) Write out the balanced equation for the reaction catalyzed by urease.arrow_forward1 Rate constants for the first-order decomposition of acetonedicarboxylic acid CO(CH2COOH)2(aq) → CO(CH3)2(aq) + 2 CO2(g) acetonedicarboxylic acidacetone are k = 4.75 ×10–4 s–1 at 293 K and k = 1.63 ×10–3 at 303 K. What is the activation energy, Ea, for this reaction? Select one: a. 71KJ/mol b. 81KJ/mol c. 51KJ/mol d. 91kJ/molarrow_forward
- Principles of Modern ChemistryChemistryISBN:9781305079113Author:David W. Oxtoby, H. Pat Gillis, Laurie J. ButlerPublisher:Cengage LearningChemistry for Engineering StudentsChemistryISBN:9781337398909Author:Lawrence S. Brown, Tom HolmePublisher:Cengage LearningChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage Learning
- Chemistry: Principles and PracticeChemistryISBN:9780534420123Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward MercerPublisher:Cengage LearningChemistry: An Atoms First ApproachChemistryISBN:9781305079243Author:Steven S. Zumdahl, Susan A. ZumdahlPublisher:Cengage Learning