ELEMENTARY SURVEYING (LOOSELEAF)
15th Edition
ISBN: 9780134604701
Author: GHILANI
Publisher: PEARSON
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Chapter 7, Problem 7.6P
In Problems 7.6 through 7.? I9, convert the azimuths from north to bearings, and compute the angles, smaller than 180° between successive azimuths.
?.6
65°26’37”,12T°25’46”?254°23’07”, and 295°14’08”
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Surveying
An instrument is set-up at point A and vertical angles are observed at B -21º15' and C +33º45'. The height of instrument from point A = 1.5865m. The horizontal distance of BA and BC are 350.2552m and 904.5565m respectively. If point C is at elevation 620.6453m;
a. Determine the elevation of B neglecting the effects of the curvature and refraction.
b. Determine the elevation of the B making due allowance for the curvature and refraction,
7) the azimuth from north of traverse line AB is 225°00'. If the succeeding line BC has a bearing of S 30°00'E, what is the deflection angle of atation B?
Chapter 7 Solutions
ELEMENTARY SURVEYING (LOOSELEAF)
Ch. 7 - Define the different reference meridians that can...Ch. 7 - Prob. 7.2PCh. 7 - Why is it important to adopt a standard angle...Ch. 7 - Prob. 7.4PCh. 7 - Prob. 7.5PCh. 7 - In Problems 7.6 through 7.? I9, convert the...Ch. 7 - Prob. 7.7PCh. 7 - Prob. 7.8PCh. 7 - Prob. 7.9PCh. 7 - Prob. 7.10P
Ch. 7 - Prob. 7.11PCh. 7 - Prob. 7.12PCh. 7 - For a bearing DE = NUS 5 53’56 ”WT and angles to...Ch. 7 - ?.14 Similar to Problem ?.13 El, except the...Ch. 7 - Prob. 7.15PCh. 7 - Course AB of a ?ve-sided traverse runs due north....Ch. 7 - Prob. 7.17PCh. 7 - Prob. 7.18PCh. 7 - Prob. 7.19PCh. 7 - Prob. 7.20PCh. 7 - Prob. 7.21PCh. 7 - Prob. 7.22PCh. 7 - Prob. 7.23PCh. 7 - Prob. 7.24PCh. 7 - Prob. 7.25PCh. 7 - Prob. 7.26PCh. 7 - Prob. 7.27PCh. 7 - Prob. 7.28PCh. 7 - Prob. 7.29PCh. 7 - For Problems 7.30 through 7.32 the observed...Ch. 7 - Prob. 7.31PCh. 7 - Prob. 7.32PCh. 7 - Prob. 7.33PCh. 7 - Prob. 7.34PCh. 7 - Prob. 7.35PCh. 7 - Prob. 7.36PCh. 7 - Prob. 7.37PCh. 7 - Prob. 7.38P
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- 6. From a two inaccessible but intervisible points A and B, the angles to two triangulation stations C and D were observed as follows: Line CD has a distance of 500m. Iong. Compute the distance of the line AB. Angle CAB = 79°30' Angle DAB = 28°30' Angle DBC = 31°30' Angle DBA = 84°30' a) 536.48m. b) 563.84m. c) 535.68m. d) 538.46m.arrow_forwardThe azimuth from north of traverse line AB is 225 degrees and 00". If the succeeding line BC has a bearing of S 30 degrees and 00" E. Compute the following: a. Bearing line AB b. Deflection of station Barrow_forwardUsing the table 1. Compute the distance of the line DA. a. 79.733 b. 87.243 c. 97.634 d. 89.921 2. Compute the area of the traverse. a. 5188.245 b. 5238.245 c. 5028.245 d. 5788.245 3. Compute the bearing of the line DA. a. N74°14’34’’E b. N54°34’14’’E c. N84°24’54’’E d. N64°44’24’’Earrow_forward
- 11. In a triangulation, an eccentric station is occupied instead of the true station A. Observations then are made to true station A and to station B. The observation are as follows: LINE AZIMUTH DISTANCE Ec. A- True A 158°30'50" 4.50 m Есс. А-B 216°43'20.5" 18642.00 m Find the azimuth of line thru A to B.arrow_forwardConvert the following azimuths to equivalent bearings. Show necessary illustrations. (2 a.) AZIM, of line EF = 138°32' b.) AZIM, of line FG = 321°24' c.) AZIM, of line GH = 214°51' d.) AZIM, of line HI = 98°43'arrow_forwardThe magnetic bearing of line AB was observed to be S 30° E, when the declination was 2° west. Point C was sighted from B and the deflection angle 10° (L) was observed. What is the true azimuth of line CB?arrow_forward
- A is a point having an elevation of 125.64 m., B and C are points of unknown elevation, B is in between A andC. By means of an instrument set 1.45 m above B, vertical angles are observed, that to A being an angle of-14º45' and that to C being an angle of +8º32'. The horizontal distance AB is 547.20 and the horizontaldistance BC is 923.43 m. Making due allowance for earth’s curvature and atmospheric refraction, computethe difference in elevation between A and B.arrow_forward1. Convert the given bearings to azimuths from north and compute the angle, smaller than 180°, between successive bearings. N27°50'05"E, S38°12'44"E, S23°16'22"W, and N73°14'30"Warrow_forward1. Convert the following Azimuths to Bearings: a. 10° 20' b. 108° 46' c. 218° 07' d. 334° 35' e. 267° 15' 2. Convert the following Bearings to Azimuths: a. N 27° 30' E b. S 63° 50 E c. N 83° 12' W d. N 10° 15' W e. S 46° 46' Warrow_forward
- 11. Convert from azimuth to bearing. a. 120° Az b. 315° Az c. 245° Azarrow_forwardWith solutionsarrow_forwardCompute the azimuth from north of line CD. Azimuth AB = 101°26'32"; angles to the right ABC = 49°54'26", BCD = 40°36'38". (Azimuth of AB is also from north.) 191°57'36" 191°25'34" 192° 37'46" 191°37'46"arrow_forward
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