(a)
Interpretation:
For each step of the given unimolecular nucleophilic substitution
Concept introduction:
An atom with partial or full negative charge is called an electron-rich site whereas an atom with partial or full positive charge is called an electron-poor site. An electron-rich atom has a lone pair of electrons whereas an electron-poor atom lacks an octet. In an elementary step, electrons tend to flow from an electron-rich site to an electron-poor site.
(b)
Interpretation:
Appropriate curved arrows are to be drawn to show the bond formation and bond breaking that occur in each step of the given unimolecular nucleophilic substitution
Concept introduction:
In an elementary step, electrons tend to flow from an electron-rich site to an electron-poor site. One curved arrow is drawn from the lone pair of an electron-rich atom to the H attached to the electron-poor site to show the formation of a bond. A second curved arrow is drawn starting from the middle of the broken bond to the atom on which the lone pair ends up, to indicate the breaking of the bond.
(c)
Interpretation:
Each step of the given unimolecular nucleophilic substitution
Concept introduction:
An elementary step in which a proton is transferred from an electron-poor site to an electron-rich site and one bond is broken and another is formed simultaneously is called the proton transfer step. An elementary step in which only single bond is broken and both electrons from that bond end up on one of the atoms initially involved in the bond is called the heterolysis step. An elementary step in which a single covalent bond is formed between the electron-rich site and the electron-poor site is called the coordination step.
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Chapter 7 Solutions
EBK GET READY FOR ORGANIC CHEMISTRY
- Nonearrow_forwardNonearrow_forwardman Campus Depa (a) Draw the three products (constitutional isomers) obtained when 2-methyl-3-hexene reacts with water and a trace of H2SO4. Hint: one product forms as the result of a 1,2-hydride shift. (1.5 pts) This is the acid-catalyzed alkene hydration reaction.arrow_forward
- (6 pts - 2 pts each part) Although we focused our discussion on hydrogen light emission, all elements have distinctive emission spectra. Sodium (Na) is famous for its spectrum being dominated by two yellow emission lines at 589.0 and 589.6 nm, respectively. These lines result from electrons relaxing to the 3s subshell. a. What is the photon energy (in J) for one of these emission lines? Show your work. b. To what electronic transition in hydrogen is this photon energy closest to? Justify your answer-you shouldn't need to do numerical calculations. c. Consider the 3s subshell energy for Na - use 0 eV as the reference point for n=∞. What is the energy of the subshell that the electron relaxes from? Choose the same emission line that you did for part (a) and show your work.arrow_forwardNonearrow_forward(9 Pts) In one of the two Rare Earth element rows of the periodic table, identify an exception to the general ionization energy (IE) trend. For the two elements involved, answer the following questions. Be sure to cite sources for all physical data that you use. a. (2 pts) Identify the two elements and write their electronic configurations. b. (2 pts) Based on their configurations, propose a reason for the IE trend exception. c. (5 pts) Calculate effective nuclear charges for the last electron in each element and the Allred-Rochow electronegativity values for the two elements. Can any of these values explain the IE trend exception? Explain how (not) - include a description of how IE relates to electronegativity.arrow_forward
- Organic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage Learning
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