Chapter 7, Problem 7.44QE

Interpretation Introduction

Interpretation:

The wavelength of the electron with velocity $1.096\times {10}^6\text{ m/s}$ has to be determined. Also, the wavelength of the electron has to be compared with circumference of orbit with $n$ equals to 2.

Concept Introduction:

de Broglie established a relation for particles of matter that they also can behave as a wave and has a wavelength. The wavelength of the particle is inversely related to its mass. The smaller the mass, the larger will be wavelength.

The expression given by the de Broglie is as follows:

  $\text{λ}=\frac{h}{mv}$        (1)

Here,

$\text{λ}$ is a wavelength of particle.

$h$ is a Plank’s constant.

$m$ is a mass of particle.

$v$ is a velocity of mass.