Chemistry In Focus
Chemistry In Focus
6th Edition
ISBN: 9781305084476
Author: Tro, Nivaldo J., Neu, Don.
Publisher: Cengage Learning
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Chapter 7, Problem 7.1YT
Interpretation Introduction

Interpretation:

The wavelength of electromagnetic radiation used to produce a modulation in amplitude is to be calculated.

Concept Introduction:

The distance between the two consecutive crests of a wave is called its wavelength.

Electromagnetic radiation is the type of energy that surrounds us and may lie in the visible region.

Modification or variation in amplitude is called amplitude modulation.

The wavelength of a radiation is given as follows:

λ=cν

Here, λ is the wavelength of the radiation, c is the speed of light and ν is the frequency of the radiation.

Expert Solution & Answer
Check Mark

Answer to Problem 7.1YT

Solution: 3.5×102 m

Explanation of Solution

Given information: The frequency of the radio signal is 840KHz.

First, the relationship between kilohertz and hertz is as follows:

1 KHz=1×103Hz840 KHz=(840KHz×1×103Hz1KHz)=840×103Hz

Also, the relationship between hertz and cycle per second is as follows:

1Hz=1cyclepersecond840×103Hz=(840×103Hz×1cyclepersecond1Hz)=840×103cyclespersecondor840×103s1

The wavelength of the radiation is calculated as follows:

λ=cν

Substitute 3×108 ms1 for c and 840×103 s1 for the value of ν in the above expression as follows:

λ=(3×108ms-1840×103 s-1)=3.5×102m

Conclusion

The wavelength of the electromagnetic radiation is 3.5×102m.

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Chapter 7 Solutions

Chemistry In Focus

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