The first three vibrational levels for HCl has to be sketched.
The first three vibrational levels for HCl has to be sketched.
Solution Summary: The author illustrates how the energy needed to excite a HCl from ground state to excited state is calculated using the below mentioned formula.
Definition Definition Rate at which light travels, measured in a vacuum. The speed of light is a universal physical constant used in many areas of physics, most commonly denoted by the letter c . The value of the speed of light c = 299,792,458 m/s, but for most of the calculations, the value of the speed of light is approximated as c = 3 x 10 8 m/s.
Chapter 7, Problem 7.151QP
(a)
Interpretation Introduction
Interpretation:
The first three vibrational levels for HCl has to be sketched.
(b)
Interpretation Introduction
Interpretation:
The energy needed to excite a HCl from ground state to excited state has to be calculated.
Concept Introduction:
The energy of each photon is given as
E=hν
h is the Planck’s constant (6.63×10-34J.s ) which relates energy and frequency.
ν is the frequency.
E is the energy of light particle.
The mathematical equation of various characteristics of light wave is given as follows,
c = νλ
C is the speed of light (3.00 × 108 m/s).
ν is the frequency
λ is wavelength.
(c)
Interpretation Introduction
Interpretation:
The vibrational nature of HCl is not equal to zero at any temperature has to be justified using Heisenberg uncertainty principle.
Concept Introduction:
Heisenberg uncertainty principle:
It is not possible to identify both the particle’s momentum and position at same time with certainty. And it given as mathematical equation
1,4-Dimethyl-1,3-cyclohexadiene can undergo 1,2- or 1,4-addition with hydrogen halides. (a) 1,2-Addition i. Draw the carbocation intermediate(s) formed during the 1,2-addition of hydrobromic acid to 1,4-dimethyl-1,3-cyclohexadiene. ii. What is the major 1,2-addition product formed during the reaction in (i)? (b) 1,4-Addition i. Draw the carbocation intermediate(s) formed during the 1,4-addition of hydrobromic acid to 1,4-dimethyl-1,3-cyclohexadiene. ii. What is the major 1,4-addition product formed from the reaction in (i)? (c) What is the kinetic product from the reaction of one mole of hydrobromic acid with 1,4-dimethyl-1,3-cyclohexadiene? Explain your reasoning. (d) What is the thermodynamic product from the reaction of one mole of hydrobro-mic acid with 1,4-dimethyl-1,3-cyclohexadiene? Explain your reasoning. (e) What major product will result when 1,4-dimethyl-1,3-cyclohexadiene is treated with one mole of hydrobromic acid at - 78 deg * C ? Explain your reasoning.
Give the product of the bimolecular elimination from each of the isomeric halogenated compounds.
Reaction A
Reaction B.
КОВ
CH₂
HotBu
+B+
ко
HOIBU
+Br+
Templates More
QQQ
Select Cv Templates More
Cras
QQQ
One of these compounds undergoes elimination 50x faster than the other. Which one and why?
Reaction A because the conformation needed for elimination places the phenyl groups and to each other
Reaction A because the conformation needed for elimination places the phenyl groups gauche to each other.
◇ Reaction B because the conformation needed for elimination places the phenyl groups gach to each other.
Reaction B because the conformation needed for elimination places the phenyl groups anti to each other.
Five isomeric alkenes. A through each undergo catalytic hydrogenation to give 2-methylpentane
The IR spectra of these five alkenes have the key absorptions (in cm
Compound
Compound A
–912. (§), 994 (5), 1643 (%), 3077 (1)
Compound B 833 (3), 1667 (W), 3050 (weak shoulder on C-Habsorption)
Compound C
Compound D)
–714 (5), 1665 (w), 3010 (m)
885 (3), 1650 (m), 3086 (m)
967 (5), no aharption 1600 to 1700, 3040 (m)
Compound K
Match each compound to the data presented.
Compound A
Compound B
Compound C
Compound D
Compound
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