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(a)
Interpretation:
Between
Concept Introduction:
Boiling point:
Boiling is a form of evaporation where the conversion from the liquid state to vapor state occurs within the body of the liquid through bubble formation.
A normal boiling point is the temperature at which the liquid boils under a pressure of
London force:
London force is a type of weak intermolecular force that has an effect on boiling point. This weak temporary force occurs between two atoms or molecules (polar or non-polar)
The cause of London force is the temporary uneven distribution of electrons causing induced polarity. The strength of the London force depends on how easily a molecule can be distorted or polarized by the polarity present in another molecule. For the large molecules the outermost electrons are far from nucleus and as the result the attractive forces of nucleus acting on them are very weak and hence the outermost electrons can be easily polarized. Hence the induced polar molecule and the polar molecule will attract each other more.
Thus the molecules having higher mass have higher boiling point.
(b)
Interpretation:
Between
Concept Introduction:
Boiling point:
Boiling is a form of evaporation where the conversion from the liquid state to vapor state occurs within the body of the liquid through bubble formation.
A normal boiling point is the temperature at which the liquid boils under a pressure of
Hydrogen bonding:
Hydrogen bonding is an intermolecular force. This is an extra strong dipole-dipole interaction between a hydrogen atom covalently bonded to a small electronegative atom mainly
The vapor pressure of liquids having significant hydrogen bonding are much lower than those liquids having no hydrogen bonding. Because of presence of extensive hydrogen bonding the liquid molecules face difficulty to escape from the condensed state and additional energy is required to break the hydrogen bonds and go to the vapor state and as a result the liquids having extensive hydrogen bonding have higher boiling points.
Dipole-dipole interaction:
Dipole- dipole interactions are the strong intermolecular interaction that causes between two polar molecules.
In polar molecules there will be a force of attraction between the positive end and the negative end. Hence the molecules having higher electronegativity difference i.e. having more polarity will have higher dipole-dipole intermolecular attraction acting between them and as a result the boiling point will increase.
(c)
Interpretation:
Between
Concept Introduction:
Dipole-dipole interaction:
Dipole- dipole interactions are the strong intermolecular interaction that causes between two polar molecules.
In polar molecules there will be a force of attraction between the positive end and the negative end. Hence the molecules having higher electronegativity difference i.e. having more polarity will have higher dipole-dipole intermolecular attraction acting between them and as a result the boiling point will increase.
(d)
Interpretation:
Between
Concept Introduction:
Hydrogen bonding:
Hydrogen bonding is an intermolecular force. This is an extra strong dipole-dipole interaction between a hydrogen atom covalently bonded to a small electronegative atom mainly
The vapor pressure of liquids having significant hydrogen bonding are much lower than those liquids having no hydrogen bonding. Because of presence of extensive hydrogen bonding the liquid molecules face difficulty to escape from the condensed state and additional energy is required to break the hydrogen bonds and go to the vapor state and as a result the liquids having extensive hydrogen bonding have higher boiling points.
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Chapter 7 Solutions
Study Guide with Selected Solutions for Stoker's General, Organic, and Biological Chemistry, 7th
- Transmitance 3. Which one of the following compounds corresponds to this IR spectrum? Point out the absorption band(s) that helped you decide. OH H3C OH H₂C CH3 H3C CH3 H3C INFRARED SPECTRUM 0.8- 0.6 0.4- 0.2 3000 2000 1000 Wavenumber (cm-1) 4. Consider this compound: H3C On the structure above, label the different types of H's as A, B, C, etc. In table form, list the labeled signals, and for each one state the number of hydrogens, their shifts, and the splitting you would observe for these hydrogens in the ¹H NMR spectrum. Label # of hydrogens splitting Shift (2)arrow_forwardNonearrow_forwardDraw the Lewis structure of C2H4Oarrow_forward
- a) 5. Circle all acidic (and anticoplanar to the Leaving group) protons in the following molecules, Solve these elimination reactions, and identify the major and minor products where appropriate: 20 points + NaOCH3 Br (2 productarrow_forwardNonearrow_forwardDr. Mendel asked his BIOL 260 class what their height was and what their parent's heights were. He plotted that data in the graph below to determine if height was a heritable trait. A. Is height a heritable trait? If yes, what is the heritability value? (2 pts) B. If the phenotypic variation is 30, what is the variation due to additive alleles? (2 pts) Offspring Height (Inches) 75 67.5 60 52.5 y = 0.9264x + 4.8519 55 60 65 MidParent Height (Inches) 70 75 12pt v V Paragraph B IUA > AT2 v Varrow_forward
- Experiment: Each team will be provided with 5g of a mixture of acetanilide and salicylic acid. You will divide it into three 1.5 g portions in separate 125 mL Erlenmeyer flasks savıng some for melting point analysis. Dissolve the mixture in each flask in ~60mL of DI water by heating to boiling on a hotplate. Take the flasks off the hotplate once you have a clear solution and let them stand on the bench top for 5 mins and then allow them to cool as described below. Sample A-Let the first sample cool slowly to room temperature by letting it stand on your lab bench, with occasional stirring to promote crystallization. Sample B-Cool the second sample 1n a tap-water bath to 10-15 °C Sample C-Cool the third sample in an ice-bath to 0-2 °C Results: weight after recrystalization and melting point temp. A=0.624g,102-115° B=0.765g, 80-105° C=1.135g, 77-108 What is the percent yield of A,B, and C.arrow_forwardRel. Intensity Q 1. Which one of the following is true of the compound whose mass spectrum is shown here? Explain how you decided. 100 a) It contains chlorine. b) It contains bromine. c) It contains neither chlorine nor bromine. 80- 60- 40- 20- 0.0 0.0 TT 40 80 120 160 m/z 2. Using the Table of IR Absorptions how could you distinguish between these two compounds in the IR? What absorbance would one compound have that the other compound does not? HO CIarrow_forwardIllustrate reaction mechanisms of alkenes with water in the presence of H2SO4, detailing each step of the process. Please show steps of processing. Please do both, I will thumb up for sure #1 #3arrow_forward
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