MYLAB MATH FOR EXCURSIONS IN MATHEMATIC
9th Edition
ISBN: 9780136415893
Author: Tannenbaum
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Chapter 7, Problem 53E
To determine
To check:
The given relation.
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موضوع الدرس
Prove that
Determine the following groups
Homz(QZ) Hom = (Q13,Z)
Homz(Q), Hom/z/nZ, Qt
for neN-
(2) Every factor group of
adivisible group is divisble.
• If R is a Skew ficald (aring with
identity and each non Zero element is
invertible then every R-module is free.
A: Tan Latitude / Tan P
A = Tan 04° 30'/ Tan 77° 50.3'
A= 0.016960 803 S CA named opposite to latitude,
except when hour angle between 090° and 270°)
B: Tan Declination | Sin P
B Tan 052° 42.1'/ Sin 77° 50.3'
B = 1.34 2905601 SCB is alway named same as
declination)
C = A + B = 1.35 9866404 S CC correction, A+/- B:
if A and B have same name - add, If
different name- subtract)
=
Tan Azimuth 1/Ccx cos Latitude)
Tan Azimuth = 0.737640253
Azimuth
=
S 36.4° E CAzimuth takes combined
name of C correction and Hour Angle - If LHA
is between 0° and 180°, it is named "west", if
LHA is between 180° and 360° it is named "east"
True Azimuth= 143.6°
Compass Azimuth = 145.0°
Compass Error = 1.4° West
Variation 4.0 East
Deviation: 5.4 West
A: Tan Latitude / Tan P
A = Tan 04° 30'/ Tan 77° 50.3'
A= 0.016960 803 S CA named opposite to latitude,
except when hour angle between 090° and 270°)
B: Tan Declination | Sin P
B Tan 052° 42.1'/ Sin 77° 50.3'
B = 1.34 2905601 SCB is alway named same as
declination)
C = A + B = 1.35 9866404 S CC correction, A+/- B:
if A and B have same name - add, If
different name- subtract)
=
Tan Azimuth 1/Ccx cos Latitude)
Tan Azimuth = 0.737640253
Azimuth
=
S 36.4° E CAzimuth takes combined
name of C correction and Hour Angle - If LHA
is between 0° and 180°, it is named "west", if
LHA is between 180° and 360° it is named "east"
True Azimuth= 143.6°
Compass Azimuth = 145.0°
Compass Error = 1.4° West
Variation 4.0 East
Deviation: 5.4 West
Chapter 7 Solutions
MYLAB MATH FOR EXCURSIONS IN MATHEMATIC
Ch. 7 - A computer lab has seven computers labeled A...Ch. 7 - The following is a list of the electrical power...Ch. 7 - Consider the network shown in Fig.720_. a. How...Ch. 7 - Consider the network shown in Fig.721_. a. How...Ch. 7 - Consider once again the network shown in. Fig720_....Ch. 7 - Consider once again the network shown in. Fig721_....Ch. 7 - Consider the network shown in. Fig722. This is the...Ch. 7 - Consider the network shown in. Fig723_. This is...Ch. 7 - Consider the tree shown in. Fig724_. a. How many...Ch. 7 - Consider the tree shown in. Fig725. a. How many...
Ch. 7 - In Exercises 11 through 24 you are given...Ch. 7 - Prob. 12ECh. 7 - Prob. 13ECh. 7 - Prob. 14ECh. 7 - In Exercises 11 through 24 you are given...Ch. 7 - Prob. 16ECh. 7 - Prob. 17ECh. 7 - Prob. 18ECh. 7 - Prob. 19ECh. 7 - In Exercises 11 through 24 you are given...Ch. 7 - Prob. 21ECh. 7 - Prob. 22ECh. 7 - Prob. 23ECh. 7 - Prob. 24ECh. 7 - Prob. 25ECh. 7 - Consider the network shown in Fig.727_. a. Find a...Ch. 7 - Prob. 27ECh. 7 - Consider the network shown in Fig.729_. a. Find a...Ch. 7 - Prob. 29ECh. 7 - Prob. 30ECh. 7 - Prob. 31ECh. 7 - Prob. 32ECh. 7 - Prob. 33ECh. 7 - Prob. 34ECh. 7 - Prob. 35ECh. 7 - The 4 by 5 grid shown in Fig. 7-37 represents a...Ch. 7 - Prob. 37ECh. 7 - Find the MST of the network shown in Fig. 7-39...Ch. 7 - Find the MST of the network shown in Fig. 7-40...Ch. 7 - Find the MST of the network shown in Fig. 7-41...Ch. 7 - Prob. 41ECh. 7 - Find the MaxST of the network shown in Fig. 7-39...Ch. 7 - Find the MaxST of the network shown in Fig. 7-40...Ch. 7 - Prob. 44ECh. 7 - The mileage chart in Fig. 742 shows the distances...Ch. 7 - Figure 7-43a shows a network of roads connecting...Ch. 7 - Prob. 47ECh. 7 - Prob. 48ECh. 7 - Prob. 49ECh. 7 - This exercise refers to weighted networks where...Ch. 7 - Prob. 51ECh. 7 - Prob. 52ECh. 7 - Prob. 53ECh. 7 - Prob. 54ECh. 7 - Prob. 55ECh. 7 - Prob. 56ECh. 7 - A bipartite graph is a graph with the property...Ch. 7 - Prob. 58ECh. 7 - Prob. 59E
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- Direction: Strictly write in 4 bond paper, because my activity sheet is have 4 spaces. This is actually for maritime. industry course, but I think geometry can do this. use nautical almanac. Sample Calculation (Amplitude- Sun): On 07th May 2006 at Sunset, a vesel in position 10°00'N 0 10°00' W observed the sun bearing 288° by compass. Find the compass error. LMT Sunset 07d 18h 13m (+)00d 00h 40 м LIT: UTC Sunset: 07d 18h 53 m added - since longitude is westerly Declination Co7d 18h): N016° 55.5' d(0.7): (+) 00-6 N016 56.1' Declination Sun: Sin Amplitude Sin Declination (Los Latitude - Sin 016° 56.1'/Cos 10°00' = 0.295780189 Amplitude = WI. 2N (The prefix of amplitude is named easterly if body is rising. and westerly of body is setting. The suffix is named came as declination.) True Bearing: 287.20 Compass Bearing 288.0° Compass Error: 0.8' Westarrow_forwardOnly 100% sure experts solve it correct complete solutions need to get full marks it's my quiz okkkk.take your time but solve full accurate okkk maths expert solve itarrow_forwardI have ai answers but incorrectarrow_forward
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