The Oregon Bar Exam (Example 7) According to the Oregon Bar Association, approximately 65 % of the people who take the bar exam to practice law in Oregon pass the exam. Find the approximate probability that at least 67 % of 200 randomly sampled people taking the Oregon bar exam will pass. (In other words, find the probability that at least 134 out of 200 will pass.) See page 355 for guidance.
The Oregon Bar Exam (Example 7) According to the Oregon Bar Association, approximately 65 % of the people who take the bar exam to practice law in Oregon pass the exam. Find the approximate probability that at least 67 % of 200 randomly sampled people taking the Oregon bar exam will pass. (In other words, find the probability that at least 134 out of 200 will pass.) See page 355 for guidance.
Solution Summary: The author calculates the probability that at least 67% of 200 randomly selected people who took Oregon bar exam will pass.
The Oregon Bar Exam (Example 7) According to the Oregon Bar Association, approximately
65
%
of the people who take the bar exam to practice law in Oregon pass the exam. Find the approximate probability that at least
67
%
of 200 randomly sampled people taking the Oregon bar exam will pass. (In other words, find the probability that at least 134 out of 200 will pass.) See page 355 for guidance.
Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.
I need help with this problem and an explanation of the solution for the image described below. (Statistics: Engineering Probabilities)
I need help with this problem and an explanation of the solution for the image described below. (Statistics: Engineering Probabilities)
This exercise is based on the following data on four bodybuilding supplements. (Figures shown correspond to a single serving.)
Creatine(grams)
L-Glutamine(grams)
BCAAs(grams)
Cost($)
Xtend(SciVation)
0
2.5
7
1.00
Gainz(MP Hardcore)
2
3
6
1.10
Strongevity(Bill Phillips)
2.5
1
0
1.20
Muscle Physique(EAS)
2
2
0
1.00
Your personal trainer suggests that you supplement with at least 10 grams of creatine, 39 grams of L-glutamine, and 90 grams of BCAAs each week. You are thinking of combining Xtend and Gainz to provide you with the required nutrients. How many servings of each should you combine to obtain a week's supply that meets your trainer's specifications at the least cost? (If an answer does not exist, enter DNE.)
servings of xtend servings of gainz
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, statistics and related others by exploring similar questions and additional content below.
Bayes' Theorem 1: Introduction and conditional probability; Author: Dr Nic's Maths and Stats;https://www.youtube.com/watch?v=lQVkXfJ-rpU;License: Standard YouTube License, CC-BY
What is Conditional Probability | Bayes Theorem | Conditional Probability Examples & Problems; Author: ACADGILD;https://www.youtube.com/watch?v=MxOny_1y2Q4;License: Standard YouTube License, CC-BY
Bayes' Theorem of Probability With Tree Diagrams & Venn Diagrams; Author: The Organic Chemistry Tutor;https://www.youtube.com/watch?v=OByl4RJxnKA;License: Standard YouTube License, CC-BY