Explanation The balanced chemical reaction between HCl and NaOH is: HCl + NaOH → NaCl + H 2 O ----(1) Molarity is defined as the number of moles of solute in 1L of the solution. Thus, number of millimoles of HCl and NaOH can be calculated as: Molarity = number of millimoles of solute Volume of solution (mL) n HCl = 1 .86 mol/L × 25 mL = 46 .5 mmol n NaOH = 1 .05 mol/L × 50 mL = 52 .5 mmol According to stoichiometry of reaction (1), 1 mmol of HCl reacts with 1 mmol of NaOH to produce 1 mmol of water. HCl is the limiting reagent. Thus, 46.5 mmol of HCl reacts with 46.5 mmol of NaOH to form 46.5 mmol of water. Thus, moles of water produced = 46.5 × 10-3 mol = 0.0465 mol Given that the heat of neutralization for HCl versus NaOH = -55.84 kJ/mol Thus, for 0.0465 mol of water produced = heat released by the reaction =-55 .84 kJ/mol × 0 .0465 mol =-2 .59 kJ Heat absorbed by the solution = 2.59 kJ Total volume of the solution formed = (50+25) mL = 75 mL Density of solution = 1.02 g/mL Thus, mass of solution Density = Mass Volume ⇒ Mass = Density × Volume =1

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ISBN: 9780134193601

Author: Petrucci

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Question

Chapter 7, Problem 26E

Interpretation Introduction

Interpretation:

The final solution temperature obtained when HCl and NaOH are neutralized in a particular amount.

Concept introduction:

Enthalpy of neutralization is defined as the amount of heat released when 1 equivalent of an acid neutralizes 1 equivalent of base to form 1 equivalent of salt and 1 equivalent water.

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Chapter 7, Problem 25E

Chapter 7, Problem 27E

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