(a) Interpretation: The value of heat capacity C v at constant volume for 1 mol of gas needs to be determined. Concept introduction: The average translation kinetic energy of gas molecules is defined by the equation: e k ¯ = 3 2 ( R T N A ) Here, R is gas constant, T is temperature, and N A is Avogadro’s constant. Also, the internal energy for heating of N molecules of an ideal gas is proportional to the average translation kinetic energy of gas molecules: U = N e k ¯
(a) Interpretation: The value of heat capacity C v at constant volume for 1 mol of gas needs to be determined. Concept introduction: The average translation kinetic energy of gas molecules is defined by the equation: e k ¯ = 3 2 ( R T N A ) Here, R is gas constant, T is temperature, and N A is Avogadro’s constant. Also, the internal energy for heating of N molecules of an ideal gas is proportional to the average translation kinetic energy of gas molecules: U = N e k ¯
Solution Summary: The author explains that the value of heat capacity C_v at constant volume for 1 mol of gas needs to be determined. The internal energy for heating of N molecules of an ideal gas is proportional
Science that deals with the amount of energy transferred from one equilibrium state to another equilibrium state.
Chapter 7, Problem 127FP
Interpretation Introduction
(a)
Interpretation:
The value of heat capacity Cv at constant volume for 1 mol of gas needs to be determined.
Concept introduction:
The average translation kinetic energy of gas molecules is defined by the equation:
ek¯=32(RTNA)
Here, R is gas constant, T is temperature, and NA is Avogadro’s constant.
Also, the internal energy for heating of N molecules of an ideal gas is proportional to the average translation kinetic energy of gas molecules:
U=Nek¯
Interpretation Introduction
(b)
Interpretation:
The value of heat capacity Cp at constant pressure for 1 mol of gas needs to be determined.
Concept introduction:
In a constant pressure heating of an ideal gas, change in enthalpy is defined as:
ΔH=ΔU+nRΔT
Also, the heat of a process at constant pressure is equal to change in enthalpy. Then from first law of thermodynamics, change in enthalpy is defined as:
Draw the titration curve of (i) weak acid vs. strong base; (ii) weak acid vs. weakbase; (iii) diprotic acid with strong base (iii) triprotic acid with strong base.
Complete the reaction in the drawing area below by adding the major products to the right-hand side.
If there won't be any products, because nothing will happen under these reaction conditions, check the box under the drawing area instead.
Note: if the products contain one or more pairs of enantiomers, don't worry about drawing each enantiomer with dash and wedge bonds. Just draw one molecule
to represent each pair of enantiomers, using line bonds at the chiral center.
More...
No reaction.
my
ㄖˋ
+
1. Na O Me
Click and drag to start
drawing a structure.
2. H
+
Predict the intermediate 1 and final product 2 of this organic reaction:
NaOMe
H+
+
1
2
H
H
work up
You can draw 1 and 2 in any arrangement you like.
Note: if either 1 or 2 consists of a pair of enantiomers, just draw one structure using line bonds instead of 3D (dash and wedge) bonds at the chiral center.
Click and drag to start drawing a structure.
X
$
dm