The electron configuration of C is 1 s 2 2 s 2 2 P 2 . (a) If each core electron (i.e., the 1 s electrons) were totally effective in shielding the valence electrons (i.e., the 2s and 2 p electrons) from the nucleus and the valence electrons did not shield one another, what would be the shielding constant ( σ ) and the effective nuclear charge ( Z eff ) for the 2s and 2 p electrons? (b) In reality, the shielding constants for the 2 s and 2 p electrons in C are slightly different. They are 2.78 and 2.86. respectively. Calculate Z eff for these electrons, and explain the differences from the values you determined in part (a).
The electron configuration of C is 1 s 2 2 s 2 2 P 2 . (a) If each core electron (i.e., the 1 s electrons) were totally effective in shielding the valence electrons (i.e., the 2s and 2 p electrons) from the nucleus and the valence electrons did not shield one another, what would be the shielding constant ( σ ) and the effective nuclear charge ( Z eff ) for the 2s and 2 p electrons? (b) In reality, the shielding constants for the 2 s and 2 p electrons in C are slightly different. They are 2.78 and 2.86. respectively. Calculate Z eff for these electrons, and explain the differences from the values you determined in part (a).
Solution Summary: The author explains how the shielding constant and the effective nuclear charge are calculated for 2s& 2p electrons.
The electron configuration of C is
1
s
2
2
s
2
2
P
2
. (a) If each core electron (i.e., the 1s electrons) were totally effective in shielding the valence electrons (i.e., the 2s and 2p electrons) from the nucleus and the valence electrons did not shield one another, what would be the shielding constant
(
σ
)
and the effective nuclear charge (
Z
eff
) for the 2s and 2p electrons? (b) In reality, the shielding constants for the 2s and 2p electrons in C are slightly different. They are 2.78 and 2.86. respectively. Calculate
Z
eff
for these electrons, and explain the differences from the values you determined in part (a).
€
+
Suppose the molecule in the drawing area below were reacted with H₂ over a platinum catalyst. Edit the molecule to show what would happen to it. That is, turn
it into the product of the reaction.
Also, write the name of the product molecule under the drawing area.
Name: ☐
H
C=0
X
H-
OH
HO-
H
HO-
-H
CH₂OH
×
Draw the Haworth projection of the disaccharide made by joining D-glucose and D-mannose with a ẞ(1-4) glycosidic bond. If the disaccharide has more than
one anomer, you can draw any of them.
Click and drag to start drawing a
structure.
X
Epoxides can be opened in aqueous acid or aqueous base to produce diols (molecules with two OH groups). In this question, you'll explore the
mechanism of epoxide opening in aqueous acid.
2nd attempt
Be sure to show all four bonds at stereocenters using hash and wedge lines.
0
0
Draw curved arrows to show how the epoxide reacts with hydronium ion.
100 +1:
1st attempt
Feedback
Be sure to show all four bonds at stereocenters using hash and wedge lines.
See Periodic Table
See Hint
H
A
5
F
F
Hr
See Periodic Table See Hint
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Quantum Numbers, Atomic Orbitals, and Electron Configurations; Author: Professor Dave Explains;https://www.youtube.com/watch?v=Aoi4j8es4gQ;License: Standard YouTube License, CC-BY