Concept explainers
Answers to all problems are at the end of this book. Detailed solutions are available in the Student Solutions Manual, Study Guide, and Problems Book.
Drawing Haworth Structures of Sugars Draw Haworth structures for the two possible isomers of D-altrose (Figure 7.2) and D-psicose (Figure 7.3).
Interpretation: The Haworth structures for two possible isomers of
Concept introduction: The simplest hydrolyzed form that is obtained from the carbohydrates is known as a monosaccharide.
Haworth projection is a method that is used to provide the three-dimensional cyclic form of a monosaccharide. This method shows the monosaccharide in the form of a hemiacetal ring or hemiketal ring.
Carbon atom which behaves as a stereocenter or a chiral center in the cyclic ring form of the hemiacetal or hemiketal compound is known as anomeric carbon.
Answer to Problem 1P
The Haworth structures for two possible isomers of
Explanation of Solution
The anomeric carbon of a monosaccharide unit always possesses two types of isomers. One is
The molecular formula of
Figure 1
In the Haworth projection of
The molecular formula of
Figure 2
In the Haworth projection of
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Chapter 7 Solutions
Study Guide With Student Solutions Manual And Problems Book For Garrett/grisham's Biochemistry, 6th
- Draw and explain your answer thoroughly: a. What is the molar mass of aspirin (C9H8O4)?b. What is the mass of 0.00225mol of aspirin?c. How many moles of aspirin are present in 500mg of aspirin?arrow_forwardGeranylgeranyl pyrophosphate 5 is converted by general acid-base catalysis to 6, and then to the natural product 7. For clarity only limited atom numbers are shown, but the main chain carbons are numbered 1 to 16, and the off-chain methyl substituents are numbered 17-20. A. Based on what you specified in A, use curly arrows on the drawing above to convert 5 to 6, and 6 to 7. Invoke general acids and general bases as needed, and draw in hydrogens as necessary . B. On the structure of 7, write in the atom numbers for the carbons marked with an asteriskarrow_forwardα-Pinene (4) is synthesized enzymatically from nerol pyrophosphate 1. Drawn an arrow-pushing mechanism from 1 to 2 to 3 to 4; add explicit hydrogens to clarify, if needed.arrow_forward
- A reverse phase column chromatography separates proteins according to their polarity. Which pentapeptide will be eluted FIRST when chromatographed at pH 7 using a reverse phase column such as a C-18 column? Peptide Sequence (from N-terminal to C-terminal) AKGED GAAVF ALLLI MCYAG GAAVF MCYAG ALLLI AKGEDarrow_forwardMelting of three DNA samples with varying lengths was monitored by increase of ultraviolet light absorbance at 260 nm. Which is the shortest DNA? A B Carrow_forwardSelect the CORRECT description of the peptide bond. The peptide bond can freely rotate around the peptide bond. The peptide bond is non-polar, hydrophobic and does not have a dipole. The peptide bond is most stable in the cis configuration. The peptide bond is rigid and planar. The peptide bond has a mix of single and double bond characters. The peptide bond is most stable in the trans configuration.arrow_forward
- Below is a fractional saturation curve for O2 binding to adult hemoglobin. Assume that curve Y represents a system at pH 7.4 and with a normal physiological level of 2,3-BPG. Curve Z represents a system that ___________________ Curve Z: is at pH 7.4 with a higher than normal physiological level of 2,3-BPG. is at pH 7.4 with a normal physiological level of 2,3-BPG but with a decreased level of CO2. has a higher pH with a normal physiological level of 2,3-BPG. has a higher pH with a lower than physiological level of 2,3-BPG.arrow_forwardWhich is a homotropic positive effector of aspartate transcarbamoylase (ATCase)? oxygen CTP aspartate ATParrow_forwardThe reaction scheme shows the mechanism of chymotrypsin-catalyzed peptide hydrolysis. Select ALL CORRECT statements regarding the chymotrypsin mechanism. Serine is the nucleophile in the step 3. Histidine is a general base in the step 2. Carbonyl carbon is the electrophile in the step 3. Histidine is a general acid in the step 4. Carbonyl carbon is the nucleophile in the step 3. This is an example of covalent catalysis. Aspartate is the electrophile in the step 3. Histidine is the nucleophile in the step 3.arrow_forward
- The following shows a protein with mostly beta sheet secondary structures. Which force stabilizes the beta sheet secondary structure of proteins? hydrophobic interactions between nonpolar amino acid side chains within the protein. electrostatic interactions between lysine and aspartic acid residues within the protein. hydrogen bonding between hydrogen bond donors and hydrogen bond acceptors of the peptide backbone. covalent disulfide linkages between cysteine residues within the protein.arrow_forwardThe Lineweaver-Burk plot was obtained when enzyme inhibition study was done in the absence and presence of 0.50 mM inhibitor. Answer the following questions using correct units and significant figures: (a) What is the mode of inhibition, competitive, uncompetitive, mixed, or noncompetitive? Explain your answer. (b) What can you say about the finding site for the inhibitor in relation to the active site of the enzyme? Explain your answer. (c) Calculate the Km and Vmax in the absence of inhibitor. (d) Calculate the Km and Vmax in the presence of 0.50 mM inhibitor. (e) Calculate the KI of the inhibitor using the given equations for reversible inhibition. Which has a higher affinity, the substrate or the inhibitor? How can you tell?arrow_forwardWhich peptide sequence is most likely to be found in the interior portion of a water-soluble globular protein? GGDGEMG DSKSTEG GAIVLWL IVAKSLIarrow_forward
- BiochemistryBiochemistryISBN:9781305577206Author:Reginald H. Garrett, Charles M. GrishamPublisher:Cengage Learning