(a)
Interpretation:
The empirical and the molecular formulas of the given compound are to be stated.
Concept introduction:
The
In a chemical compound, the proportion of atoms present in a compound is given by the empirical formula. On the other hand, molecular formula represents the exact number of atoms present in a compound.
(b)
Interpretation:
The empirical and the molecular formulas of the given compound are to be stated.
Concept introduction:
The atomic mass of an atom is defined as the average mass of the atoms in an element. Similarly, in case of molecules, the average mass of molecules is known as molecular mass. Formula mass is the mass of the atoms present in a molecular formula.
In a chemical compound, the proportion of atoms present in a compound is given by the empirical formula. On the other hand, molecular formula represents the exact number of atoms present in a compound.
(c)
Interpretation:
The empirical and the molecular formulas of the given compound are to be stated.
Concept introduction:
The atomic mass of an atom is defined as the average mass of the atoms in an element. Similarly, in case of molecules, the average mass of molecules is known as molecular mass. Formula mass is the mass of the atoms present in a molecular formula.
In a chemical compound, the proportion of atoms present in a compound is given by the empirical formula. On the other hand, molecular formula represents the exact number of atoms present in a compound.
(d)
Interpretation:
The empirical and the molecular formulas of the given compound are to be stated.
Concept introduction:
The atomic mass of an atom is defined as the average mass of the atoms in an element. Similarly, in case of molecules, the average mass of molecules is known as molecular mass. Formula mass is the mass of the atoms present in a molecular formula.
In a chemical compound, the proportion of atoms present in a compound is given by the empirical formula. On the other hand, molecular formula represents the exact number of atoms present in a compound.
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Chapter 7 Solutions
EBK INTRODUCTORY CHEMISTRY: AN ACTIVE L
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