a)
Interpretation:
Electrostatic potential maps of formaldehyde is given.The nature of the formldehyde carbon atom whether electrophilic or nucleophilic is to be stated and explained.
Concept introduction:
Electrostatic potential maps are used to identify at a glance the electron rich or electron poor atoms in molecule. In them the electron rich regions are shown in red and electron poor region are shown in blue.
To state and explain:
From the electrostatic potential map of formaldehyde the nature of the formldehyde carbon atom, whether it is electrophilic or nucleophilic.
b)
Interpretation:
Electrostatic potential map of methanethiol (CH3SH) is given. The nature of the sulfur atom in methanethiol, whether electrophilic or nucleophilic, is to be stated and explained.
Concept introduction:
Electrostatic potential maps are used to identify at a glance the electron rich or electron poor atoms in molecule. In them the electron rich regions are shown in red and electron poor region are shown in blue.
To state and explain:
From the electrostatic potential map of methanethiol, whether the sulfur atom in it is electrophilic or nucleophilic.
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Chapter 6 Solutions
OWLv2 with Student Solutions Manual eBook, 4 terms (24 months) Printed Access Card for McMurry's Organic Chemistry, 9th
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- Show work. don't give Ai generated solution. How many carbons and hydrogens are in the structure?arrow_forward13. (11pts total) Consider the arrows pointing at three different carbon-carbon bonds in the molecule depicted below. Bond B 2°C. +2°C. cleavage Bond A •CH3 + 26.← Cleavage 2°C. + Bond C +3°C• CH3 2C Cleavage E 2°C. 26. weakest bond Intact molecule Strongest 3°C 20. Gund Largest argest a. (2pts) Which bond between A-C is weakest? Which is strongest? Place answers in appropriate boxes. C Weakest bond A Produces Most Bond Strongest Bond Strongest Gund produces least stable radicals Weakest Stable radical b. (4pts) Consider the relative stability of all cleavage products that form when bonds A, B, AND C are homolytically cleaved/broken. Hint: cleavage products of bonds A, B, and C are all carbon radicals. i. Which ONE cleavage product is the most stable? A condensed or bond line representation is fine. 13°C. formed in bound C cleavage ii. Which ONE cleavage product is the least stable? A condensed or bond line representation is fine. • CH3 methyl radical Formed in Gund A Cleavage c.…arrow_forwardBr. COOH Br, FCH COOH E FeBr ASOCI B NH (CH,CO),OD Br₂ 2 C alcKOHarrow_forward
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