Explanation Given info: d a t a value=65 inches mean( μ ) = 63 .6 inches standard deviation( σ ) =2 .5 inches (a)We know that, Z = s tan d a r d score = d a t a value- mean s tan d a r d deviation Z = 65 − 63.6 2.5 = 0.56 Using Table 6.3 When Z − s c o r e is 0 .55 then percentile is 70 .88% when z-score is 0 .60 then percentile is 72 .57% Therfore, the approximate percentile for Z-score= 0 .56 is 71 .23% (c) Given data value = 60.5 i n c h e s Using Z-formula, Z = 60.5 − 63.6 2.5 = − 1.24 A n d by using table 6 .3, When Z-score is -1 .3 the percentile is 9 .68 When Z-score is − 1.2 then percentile is 11.51 ...

Using and Understanding Mathematics: A Quantitative Reasoning Approach (6th Edition)

6th Edition

ISBN: 9780321914620

Author: Jeffrey O. Bennett, William L. Briggs

Publisher: PEARSON

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Chapter 6.C, Problem 37E

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To find the standard score and approximate percentile.

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Chapter 6.C, Problem 36E

Chapter 6.C, Problem 38E

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Chapter 6 Solutions

Using and Understanding Mathematics: A Quantitative Reasoning Approach (6th Edition)

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