For the following exercises, use the fact that a falling body with friction equal to velocity squared obeys the equation d v / d t = g − v 2 . 419. Show that v ( t ) = g tanh ( g t ) satisfies this equation.
For the following exercises, use the fact that a falling body with friction equal to velocity squared obeys the equation d v / d t = g − v 2 . 419. Show that v ( t ) = g tanh ( g t ) satisfies this equation.
A 69-kg base runner begins his slide into second base when he is moving at a speed of 4.6 m/s. The coefficient of friction between his clothes and Earth is 0.70. He slides so that his speed is zero just as he reaches the base.
(a) How much mechanical energy is lost due to friction acting on the runner? J(b) How far does he slide? m
A particle starts to move at Q and travels in a straight line with velocity v cms-1, where v = 2t-t2 and t is the time in seconds after leaving Q. The particle comes to rest at A.
Calculate:
a. the value of t at A.
b. the acceleration, a cms-2
c. the distance, s cm, from Q to A.
d. the total distance covered from t=o to t=4.
An object is moving with velocity v(t) = 6t+ 6 in m/sec. Find the distance traveled by the object between time t = 0 and t = 5
seconds.
Select one:
Oa. 45 m
O b. 30 m
c. 105 m
d. 180 m
e. 36 m
University Calculus: Early Transcendentals (4th Edition)
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, subject and related others by exploring similar questions and additional content below.