For the following exercises, solve using calculus, then check your answer with geometry.
57. Find the area between the perimeter of the unit circle and the triangle created from
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- The correct answer is D Could you explain and show the steps pleasearrow_forwardAre the two statements A and B equivalent? (A) p~q (B) ~pq ☐ Statement A and B are equivalent. ☐ Statement A and B are not equivalent as their values in three rows are not identical. ☐ Statement A and B are not equivalent as their values in one row is not identical. ☐ Statement A and B are not equivalent as their values in two row are not identical.arrow_forwardLet p, q and r to be True, False and True statements, respectively. What are the values of the statements below. A: B: [(p→q)^~q]→r (pvq) → ~r O O A: False B: False A: True B: True A: False B: True A: True B: Falsearrow_forward
- Let's assume p and q are true statements. What are the values of the statements below. A: (p→ q) →~p B: (p v~q) → ~(p^q) A: True B: False A: True B: True ☐ A: A: False B: False ☐ A: False B: Truearrow_forwardThree statements A, B and C are given below. Which choice is correct? (A) ~(p^~q) (B) ~p^q (c) pv~q ☐ All statements are inequivalent. ☐ Only statements A and B are equivalent. ☐ Only statements C and B are equivalent. ☐ Only statements A and C are equivalent.arrow_forward6: 000 Which truth table is correct for the given compound statement? (pvq)^p]→q A: B: P P 9 [(pvq)^p]→ 9 T T F T T T T F T T F F F T T F T F F F T F F T C: P 9 [(pvq)^p]→9 D: P 9 [pvq)^p]→9 T T T T T T TF T T F F F T F F T T F F F F F T B A D Previous Page Next Page Page 3 of 11arrow_forward
- st One Which truth table is correct for the given compound statement? (p→q)^~p A: P q (p→q)^~p B: P q (p→q)^~p T T F T T F T F F T F T F T T F T T F F F F F T C: D: P q (p→ q)^~p P 9 (p→q)^~p T T F T T T T F F T F F F T T F T T F F T F F T A U Oarrow_forward2) Find the general solution to the following differential equation. d²x dt² - dx 6 +25x = 64e¯* dtarrow_forward1) Solve the following initial value problem. y' + xy = x y(0) = −1arrow_forward
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