a. Explanation Given: The force required for stretching 0.1 m from its equilibrium = 50 N. Definition used : “The work done by a variable force F moving an object along a line from x = a to x = b in the direction of the force is W = ∫ a b F ( x ) d x .” Law used : Hooke’s Law: “The force required to keep the spring in a compressed or stretched position x units from the equilibrium position is F ( x ) = k x , where the positive spring constant k measures the stiffness of the spring.” Calculation: Given that the force required for stretching 0.1 m from its equilibrium is 50 N. Hence, by Hooke’s Law, substitute F ( x ) = 50 N and x = 0.1 in F ( x ) = k x , 50 = 0.1 k k = 500 Hence, the positive spring constant k = 500 . Obtain the force required to stretch the following string x m from their equilibrium position by using Hooke’s Law b. To determine To find: The work required to stretch the following string 0.4 m from their equilibrium position.

Single Variable Calculus: Early Transcendentals, Books a la Carte, and MyLab Math with Pearson eText -- Title-Specific Access Card Package (3rd Edition)

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ISBN: 9780134996103

Author: William L. Briggs, Lyle Cochran, Bernard Gillett, Eric Schulz

Publisher: PEARSON

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Chapter 6.7, Problem 28E

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To find: The work required to stretch the following string 0.4 m from their equilibrium position.

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To find: The work required to stretch the following string 0.4 m from their equilibrium position.

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Chapter 6.7, Problem 27E

Chapter 6.7, Problem 29E

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The work required to stretch the following string 0.4 m from their equilibrium position.

Solution Summary: The author calculates the force required to stretch the following string 0.4 m from its equilibrium position by using Hooke's Law.

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To find: The work required to stretch the following string 0.4 m from their equilibrium position.

To find: The work required to stretch the following string 0.4 m from their equilibrium position.

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