Explanation The work done in lifting a body having a certain mass is the amount of gravitational potential energy that is there in the body which is being elevated to a specific height. The work done is equal to the force required to move the object upward multiplied with the vertical distance the object is moved. Thus, one can say that the work done is equal to the potential energy. Given: A mass of 4 − l b which is lifted to a height of 16 f t Formula Used: 1. The amount of work done in lifting a body to a height is given by the formula W o r k D o n e = m × g × h Where, m = mass of the object in kilograms g = acceleration due to gravity ( at the surface of the earth) h = height in meters 1. 1 P o u n d = 0.453592 k i l o g r a m s 2. 1 F o o t = 0.3048 m e t e r s Calculation: Given that mass, m = 4 l b And Height, h = 16 f t Mass in kilograms = 4 × 0.453592 = 1...

3rd Edition

ISBN: 9781464125263

Author: Jon Rogawski, Colin Adams

Publisher: W.H. Freeman & Co

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Question

Chapter 6.5, Problem 2E

To determine

The work done in raising a $4 - l b$ mass to a height of $16 f t$ above the ground.

Expert Solution & Answer

Chapter 6 Solutions

Calculus - Standalone book

Ch. 6.1 - Prob. 1PQ Ch. 6.1 - Prob. 2PQ Ch. 6.1 - Prob. 3PQ Ch. 6.1 - Prob. 4PQ Ch. 6.1 - Prob. 5PQ Ch. 6.1 - Prob. 6PQ Ch. 6.1 - Prob. 1E Ch. 6.1 - Prob. 2E Ch. 6.1 - Prob. 3E Ch. 6.1 - Prob. 4E

Ch. 6.1 - Prob. 5E Ch. 6.1 - Prob. 6E Ch. 6.1 - Prob. 7E Ch. 6.1 - Prob. 8E Ch. 6.1 - Prob. 9E Ch. 6.1 - Prob. 10E Ch. 6.1 - Prob. 11E Ch. 6.1 - Prob. 12E Ch. 6.1 - Prob. 13E Ch. 6.1 - Prob. 14E Ch. 6.1 - Prob. 15E Ch. 6.1 - Prob. 16E Ch. 6.1 - Prob. 17E Ch. 6.1 - Prob. 18E Ch. 6.1 - Prob. 19E Ch. 6.1 - Prob. 20E Ch. 6.1 - Prob. 21E Ch. 6.1 - Prob. 22E Ch. 6.1 - Prob. 23E Ch. 6.1 - Prob. 24E Ch. 6.1 - Prob. 25E Ch. 6.1 - Prob. 26E Ch. 6.1 - Prob. 27E Ch. 6.1 - Prob. 28E Ch. 6.1 - Prob. 29E Ch. 6.1 - Prob. 30E Ch. 6.1 - Prob. 31E Ch. 6.1 - Prob. 32E Ch. 6.1 - Prob. 33E Ch. 6.1 - Prob. 34E Ch. 6.1 - Prob. 35E Ch. 6.1 - Prob. 36E Ch. 6.1 - Prob. 37E Ch. 6.1 - Prob. 38E Ch. 6.1 - Prob. 39E Ch. 6.1 - Prob. 40E Ch. 6.1 - Prob. 41E Ch. 6.1 - Prob. 42E Ch. 6.1 - Prob. 43E Ch. 6.1 - Prob. 44E Ch. 6.1 - Prob. 45E Ch. 6.1 - Prob. 46E Ch. 6.1 - Prob. 47E Ch. 6.1 - Prob. 48E Ch. 6.1 - Prob. 49E Ch. 6.1 - Prob. 50E Ch. 6.1 - Prob. 51E Ch. 6.1 - Prob. 52E Ch. 6.1 - Prob. 53E Ch. 6.1 - Prob. 54E Ch. 6.1 - 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The work done in raising a 4 − l b mass to a height of 16 f t above the ground.

Solution Summary: The author explains that the amount of work done in lifting a 4 l b mass is equal to the gravitational potential energy that is there in the body.

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The work done in raising a $4 - l b$ mass to a height of $16 f t$ above the ground.

Chapter 6 Solutions

The work done in raising a 4 − l b mass to a height of 16 f t above the ground.

Solution Summary: The author explains that the amount of work done in lifting a 4 l b mass is equal to the gravitational potential energy that is there in the body.

Concept explainers

Videos

The work done in raising a 4−lb mass to a height of 16 ft above the ground.

Chapter 6 Solutions

The work done in raising a $4 - l b$ mass to a height of $16 f t$ above the ground.