Explanation Given information: The given statement is that 5J of work is done in stretching the spring 10cm beyond equilibrium. Concept Used: We use the formula for the work done given by W = 1 2 k x 2 where x is the displacement in metre beyond equilibrium. Calculation: As given5J of work is done in stretching the spring 10cm beyond equilibrium, thus W 1 = 1 2 k x 1 2 ⇒ 5 = 1 2 k ( 0.1 ) 2 ⇒ 10 = 0

3rd Edition

ISBN: 9781464125263

Author: Jon Rogawski, Colin Adams

Publisher: W.H. Freeman & Co

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Question

Chapter 6.5, Problem 7E

To determine

The work done in stretching the spring 15 cm beyond equilibrium.

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Chapter 6.5, Problem 6E

Chapter 6.5, Problem 8E

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Suppose a 1.6-oz golf ball is placed on a vertical spring with force constant k = 2 lb/in. The spring is compressed 6 in. and released. About how high does the ball go (measured from the spring’s rest position)?

Chapter 6 Solutions

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The work done in stretching the spring 15 cm beyond equilibrium.

Solution Summary: The author explains that 5J of work is done in stretching the spring 10cm beyond equilibrium.

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The work done in stretching the spring 15 cm beyond equilibrium.

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Chapter 6 Solutions