Explanation Given: Mass of tank = 20 kg Tank contain water = 100 kg Water raised vertically at a constant speed of 100 m / min During that time, water leaks at a rate of 40 kg / min . Calculation: Let t be the time in minutes and y be the height of container. Water raised vertically at a constant speed of 100 m / min So, y = 100 t Mass of the water in container = 100 − 40 t 100 − 40 t = ( 100 − 0.4 y ) kg Force needed to lift the container and its content = 9.8 ( 20 + ( 100 − 0.4 y ) ) = 9.8 ( 120 − 0.4 y ) = 1176 − 3.92 y N Now, find the work required to lift the container. ∫ 0 100 ( 1176 − 3...

3rd Edition

ISBN: 9781464125263

Author: Jon Rogawski, Colin Adams

Publisher: W.H. Freeman & Co

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Chapter 6, Problem 54CRE

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Find the total work performed in raising the container.

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Chapter 6, Problem 53CRE

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Chapter 6 Solutions

Calculus - Standalone book

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Find the total work performed in raising the container.

Solution Summary: The author explains how the work required to lift the container is 98000 J.

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Chapter 6 Solutions