Explanation The free body diagram is shown below Write the expression for moment at A using figure 1 ∑ M A = F × d ⊥ (I) Here, F is the force, d ⊥ is the perpendicular distance between A and point where force is acting, and M A is the moment at A At equilibrium the moment at A will be zero ∑ M A = F × d ⊥ = 0 (II) Write the complete expression for the total moment at A using figure 2 under equilibrium is ∑ M A = Q ( 15 in . ) − ( 35 in . ) C x = 0 (III) Here, Q is the force required to release the brace Rearrange equation (III) to obtain Q Q ( 15 in . ) − ( 35 in . ) C x = 0 Q = 7 3 C x (IV) The total force along y axis is ∑ F y = C y − 800 lb=0 C y = 800 lb Here, C y is the force at C along y direction Write the expression for the force acting on the spring F = k x = k ( l − l 0 ) (V) Here, k is the spring constant, l is the extension of the spring, and l 0 is the upstretched length of the spring. Consider the free body diagram of A B C as shown below Write the expression for moment at B using figure 2 ∑ M B = F × d ⊥ (IV) Here, F is the force, d ⊥ is the perpendicular distance between B and point where force is acting, and M B is the moment at B At equilibrium the moment at B will be zero ∑ M B = F × d ⊥ = 0 (V) Write the complete expression for the total moment at B using figure 2 under equilibrium is ∑ M B = F ( 2 in

Vector Mechanics for Engineers: Statics and Dynamics

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ISBN: 9781259977251

Author: BEER

Publisher: MCG

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Any functioning component, such as machine parts, structural members, pressure vessels, and so on, are all under the influence of more than one force. When anybody is under the influence of more than one force such as shear forces, bending moments, axial…

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Chapter 6.4, Problem 6.151P

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The force that required to release the brace.

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Chapter 6.4, Problem 6.150P

Chapter 6.4, Problem 6.152P

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