Given Information : A hypothetical cache that uses the high order “s” bits of an address as the set index is given. For such a cache, the contiguous chunks of memory blocks are mapped to the same cache sets.

Question

Write the SQL code that permits to implement the tables: Student and Transcript. NB: Add the constraints on the attributes – keys and other.

Answer 1

Question

Chapter 6.4, Problem 6.11PP

A.

Program Plan Intro

Given Information:

A hypothetical cache that uses the high order “s” bits of an address as the set index is given. For such a cache, the contiguous chunks of memory blocks are mapped to the same cache sets.

B.

Program Plan Intro

Given Information:

The following code is given:

//traverse the array

for(i=0;i<4096;i++)

{

//add array elements

sum+=array[i];

}

The code runs on a system with cache of the form(S,E,B,m)= (512,1,32,32).

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Answer 2

Question

Chapter 6.4, Problem 6.11PP

A.

Program Plan Intro

Given Information:

A hypothetical cache that uses the high order “s” bits of an address as the set index is given. For such a cache, the contiguous chunks of memory blocks are mapped to the same cache sets.

B.

Program Plan Intro

Given Information:

The following code is given:

//traverse the array

for(i=0;i<4096;i++)

{

//add array elements

sum+=array[i];

}

The code runs on a system with cache of the form(S,E,B,m)= (512,1,32,32).

Expert Solution & Answer

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Answer 3

Question

Chapter 6.4, Problem 6.11PP

A.

Program Plan Intro

Given Information:

A hypothetical cache that uses the high order “s” bits of an address as the set index is given. For such a cache, the contiguous chunks of memory blocks are mapped to the same cache sets.

B.

Program Plan Intro

Given Information:

The following code is given:

//traverse the array

for(i=0;i<4096;i++)

{

//add array elements

sum+=array[i];

}

The code runs on a system with cache of the form(S,E,B,m)= (512,1,32,32).

Expert Solution & Answer

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Answer 4

Question

Chapter 6.4, Problem 6.11PP

A.

Program Plan Intro

Given Information:

A hypothetical cache that uses the high order “s” bits of an address as the set index is given. For such a cache, the contiguous chunks of memory blocks are mapped to the same cache sets.

B.

Program Plan Intro

Given Information:

The following code is given:

//traverse the array

for(i=0;i<4096;i++)

{

//add array elements

sum+=array[i];

}

The code runs on a system with cache of the form(S,E,B,m)= (512,1,32,32).

Expert Solution & Answer

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Answer 5

Chapter 6.4, Problem 6.11PP

A.

Program Plan Intro

Given Information:

A hypothetical cache that uses the high order “s” bits of an address as the set index is given. For such a cache, the contiguous chunks of memory blocks are mapped to the same cache sets.

B.

Program Plan Intro

Given Information:

The following code is given:

//traverse the array

for(i=0;i<4096;i++)

{

//add array elements

sum+=array[i];

}

The code runs on a system with cache of the form(S,E,B,m)= (512,1,32,32).

Answer 6

Chapter 6.4, Problem 6.11PP

A.

Program Plan Intro

Given Information:

A hypothetical cache that uses the high order “s” bits of an address as the set index is given. For such a cache, the contiguous chunks of memory blocks are mapped to the same cache sets.

Answer 7

Chapter 6.4, Problem 6.11PP

A.

Program Plan Intro

Given Information:

A hypothetical cache that uses the high order “s” bits of an address as the set index is given. For such a cache, the contiguous chunks of memory blocks are mapped to the same cache sets.

Answer 8

B.

Program Plan Intro

Given Information:

The following code is given:

//traverse the array

for(i=0;i<4096;i++)

{

//add array elements

sum+=array[i];

}

The code runs on a system with cache of the form(S,E,B,m)= (512,1,32,32).

Answer 9

B.

Program Plan Intro

Given Information:

The following code is given:

//traverse the array

for(i=0;i<4096;i++)

{

//add array elements

sum+=array[i];

}

The code runs on a system with cache of the form(S,E,B,m)= (512,1,32,32).

Answer 10

Expert Solution & Answer

Answer 11

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Answer 21

Ch. 6.1 - Prob. 6.1PP Ch. 6.1 - Prob. 6.2PP Ch. 6.1 - Prob. 6.3PP Ch. 6.1 - Prob. 6.4PP Ch. 6.1 - Prob. 6.5PP Ch. 6.1 - Prob. 6.6PP Ch. 6.2 - Prob. 6.7PP Ch. 6.2 - Prob. 6.8PP Ch. 6.4 - Prob. 6.9PP Ch. 6.4 - Prob. 6.10PP

Given Information : A hypothetical cache that uses the high order “s” bits of an address as the set index is given. For such a cache, the contiguous chunks of memory blocks are mapped to the same cache sets.

Solution Summary: The author describes a hypothetical cache that uses the high order "s" bits of an address as the set index.

Given Information:

A hypothetical cache that uses the high order “s” bits of an address as the set index is given. For such a cache, the contiguous chunks of memory blocks are mapped to the same cache sets.

Given Information:

The following code is given:

//traverse the array

for(i=0;i<4096;i++)

{

//add array elements

sum+=array[i];

}

The code runs on a system with cache of the form(S,E,B,m)= (512,1,32,32).

Chapter 6 Solutions

Given Information : A hypothetical cache that uses the high order “s” bits of an address as the set index is given. For such a cache, the contiguous chunks of memory blocks are mapped to the same cache sets.

Solution Summary: The author describes a hypothetical cache that uses the high order "s" bits of an address as the set index.

Given Information: A hypothetical cache that uses the high order “s” bits of an address as the set index is given. For such a cache, the contiguous chunks of memory blocks are mapped to the same cache sets.

Given Information: The following code is given: //traverse the array for(i=0;i<4096;i++) { //add array elements sum+=array[i]; } The code runs on a system with cache of the form(S,E,B,m)= (512,1,32,32).

Chapter 6 Solutions

Given Information:

A hypothetical cache that uses the high order “s” bits of an address as the set index is given. For such a cache, the contiguous chunks of memory blocks are mapped to the same cache sets.

Given Information:

The following code is given:

//traverse the array

for(i=0;i<4096;i++)

{

//add array elements

sum+=array[i];

}

The code runs on a system with cache of the form(S,E,B,m)= (512,1,32,32).