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Chapter 6 Solutions
Elementary Geometry For College Students, 7e
- + Recall that a map, f: R2 R², is an isometry if |P-Q| = |ƒ(P) — ƒ (Q) for all pairs of points P and Q in R². Thus, f is a distance preserving map. Show that an isometry, f: R² → R² also preserves angles. In other words if two line segments meeting at a point determine an angle a, their image line segments meeting at the image of that point also determine the angle a.arrow_forwardUsing Harriott's formula for the area of a triangle on the unit sphere, S2, compute the Euler characteristic X(S2). Make sure to explain what the Euler characteristic is. (The point of the exercise is to show that this notion is well-defined.)arrow_forwardProve Harriot's Formula (Area of a Triangle on a Sphere).arrow_forward
- In rhombus ABCD, diagonals BD¯¯¯¯¯¯BD¯ and AC¯¯¯¯¯AC¯ intersect at point E. If BE = 4n – 3 and EC = 2n + 5, which expression can be used to represent AD?arrow_forwardProve that the image of a polygon in R², under an isometry, is congruent to the original polygonarrow_forward9 AB is parallel to plane m and perpendicular to plane r. CD lies in r. Which of the following must be true? arim br m 6 CD L m d AB || CD e AB and CD are skew.arrow_forward
- (6) Prove that the image of a polygon in R², under an isometry, is congruent to the original polygon.arrow_forwardsat Pie Joday) B rove: ABCB. Step 1 Statement D is the midpoint of AC ED FD ZEDAZFDC Reason Given 2 ADDC Select a Reason... A OBB hp B E F D Carrow_forward6) Find the area of the shaded region. Leave your answer in terms of π. A 2 B C A) 16.5л B) 30д 3.1988 C) 3л π D) 7.5π 9.+2uarrow_forward
- Task number: A1.1, A1.7 Topic: Celestial Navigation, Compass - Magnetic and Gyro Activ Determine compass error (magnetic and gyro) using azimuth choosing a suitable celestial body (Sun/ Stars/ Planets/ Moon). Apply variation to find the deviation of the magnetic compass. Minimum number of times that activity should be recorded: 6 (2 each phase) Sample calculation (Azimuth- Planets): On 06th May 2006 at 22h20m 10s UTC, a vessel in position 48°00'N 050°00'E observed Mars bearing 327° by compass. Find the compass error. If variation was 4.0° East, calculate the deviation. GHA Mars (06d 22h): Increment (20m 10s): 089° 55.7' 005° 02.5' v (0.9): (+) 00.3' GHA Mars: 094° 58.5' Longitude (E): (+) 050° 00.0' (plus- since longitude is easterly) LHA Mars: 144° 58.5' Declination (06d 22h): d (0.2): N 024° 18.6' (-) 00.1' Declination Mars: N 024° 18.5' P=144° 58.5' (If LHA<180°, P=LHA) A Tan Latitude/ Tan P A Tan 48° 00' Tan 144° 58.5' A = 1.584646985 N (A is named opposite to latitude, except when…arrow_forwardTask number: A1.1, A1.7 Topic: Celestial Navigation, Compass - Magnetic and Gyro Activ Determine compass error (magnetic and gyro) using azimuth choosing a suitable celestial body (Sun/ Stars/ Planets/ Moon). Apply variation to find the deviation of the magnetic compass. Minimum number of times that activity should be recorded: 6 (2 each phase) Sample calculation (Azimuth- Planets): On 06th May 2006 at 22h20m 10s UTC, a vessel in position 48°00'N 050°00'E observed Mars bearing 327° by compass. Find the compass error. If variation was 4.0° East, calculate the deviation. GHA Mars (06d 22h): Increment (20m 10s): 089° 55.7' 005° 02.5' v (0.9): (+) 00.3' GHA Mars: 094° 58.5' Longitude (E): (+) 050° 00.0' (plus- since longitude is easterly) LHA Mars: 144° 58.5' Declination (06d 22h): d (0.2): N 024° 18.6' (-) 00.1' Declination Mars: N 024° 18.5' P=144° 58.5' (If LHA<180°, P=LHA) A Tan Latitude/ Tan P A Tan 48° 00' Tan 144° 58.5' A = 1.584646985 N (A is named opposite to latitude, except when…arrow_forwardA: Tan Latitude / Tan P A = Tan 04° 30'/ Tan 77° 50.3' A= 0.016960 803 S CA named opposite to latitude, except when hour angle between 090° and 270°) B: Tan Declination | Sin P B Tan 052° 42.1'/ Sin 77° 50.3' B = 1.34 2905601 SCB is alway named same as declination) C = A + B = 1.35 9866404 S CC correction, A+/- B: if A and B have same name - add, If different name- subtract) = Tan Azimuth 1/Ccx cos Latitude) Tan Azimuth = 0.737640253 Azimuth = S 36.4° E CAzimuth takes combined name of C correction and Hour Angle - If LHA is between 0° and 180°, it is named "west", if LHA is between 180° and 360° it is named "east" True Azimuth= 143.6° Compass Azimuth = 145.0° Compass Error = 1.4° West Variation 4.0 East Deviation: 5.4 Westarrow_forward
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