Task number: A1.1, A1.7 Topic: Celestial Navigation, Compass - Magnetic and Gyro Activ Determine compass error (magnetic and gyro) using azimuth choosing a suitable celestial body (Sun/ Stars/ Planets/ Moon). Apply variation to find the deviation of the magnetic compass. Minimum number of times that activity should be recorded: 6 (2 each phase) Sample calculation (Azimuth- Planets): On 06th May 2006 at 22h20m 10s UTC, a vessel in position 48°00'N 050°00'E observed Mars bearing 327° by compass. Find the compass error. If variation was 4.0° East, calculate the deviation. GHA Mars (06d 22h): Increment (20m 10s): 089° 55.7' 005° 02.5' v (0.9): (+) 00.3' GHA Mars: 094° 58.5' Longitude (E): (+) 050° 00.0' (plus- since longitude is easterly) LHA Mars: 144° 58.5' Declination (06d 22h): d (0.2): N 024° 18.6' (-) 00.1' Declination Mars: N 024° 18.5' P=144° 58.5' (If LHA<180°, P=LHA) A Tan Latitude/ Tan P A Tan 48° 00' Tan 144° 58.5' A = 1.584646985 N (A is named opposite to latitude, except when hour angle is between 090° and 270°) B Tan Declination/ Sin P B= Tan 024° 18.5' Sin 144° 58.5' B=0.787011353 N (B is always named same as declination) C A+B 2.371658338 N (C correction, A+/- B: If A and B have same name- add, If different name- subtract) Tan Azimuth = 1/ (C X Cos Latitude) Tan Azimuth = 0.6301399 Azimuth = N 32.2° W (Azimuth takes combined name of C correction and Hour Angle- If LHA is between 0° and 180°, it is named "west", if LHA is between 180° and 360°, it is named "east") True Azimuth= 327.8° Compass Azimuth=327.0° Compass Error = 0.8° East Variation = 4.0° East Deviation GlobalMET 3.2° West Deck Cadet Shipboard Activity Workbook - used in conjunction with the Deck Cadet SSTP Record Book 26 Activ Determine compass error using amplitude (Sun). Minimum number of times that activity should be performed: 3 (1 each phase) Sample calculation (Amplitude- Sun): On 07th May 2006 at Sunset, a vessel in position 10°00'N 010°00'W observed the Sun bearing 288° by compass. Find the compass error. LMT Sunset: LIT: (+) 00d 07d 18h 00h 13m 40m UTC Sunset: 07d 18h 53m (added- since longitude is westerly) Declination (07d 18h): N 016° 55.5' d (0.7): (+) 00.6' Declination Sun: N 016° 56.1' Sin Amplitude = Sin Declination/Cos Latitude = Sin 016°56.1'/ Cos 10°00' = 0.295780189 Amplitude=W17.2N (The prefix of amplitude is named easterly if body is rising, and westerly if body is setting. The suffix is named same as declination) True Bearing=287.2° Compass Bearing= 288.0° Compass Error = 0.8° West

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.6: Summarizing Categorical Data
Problem 32PPS
Question
Task number: A1.1, A1.7
Topic: Celestial Navigation, Compass - Magnetic and Gyro
Activ Determine compass error (magnetic and gyro) using azimuth choosing a suitable
celestial body (Sun/ Stars/ Planets/ Moon). Apply variation to find the deviation of the magnetic
compass.
Minimum number of times that activity should be recorded: 6 (2 each phase)
Sample calculation (Azimuth- Planets):
On 06th May 2006 at 22h20m 10s UTC, a vessel in position 48°00'N 050°00'E observed Mars bearing
327° by compass. Find the compass error. If variation was 4.0° East, calculate the deviation.
GHA Mars (06d 22h):
Increment (20m 10s):
089° 55.7'
005° 02.5'
v (0.9):
(+)
00.3'
GHA Mars:
094° 58.5'
Longitude (E):
(+) 050° 00.0' (plus- since longitude is easterly)
LHA Mars:
144° 58.5'
Declination (06d 22h):
d (0.2):
N 024° 18.6'
(-)
00.1'
Declination Mars:
N 024° 18.5'
P=144° 58.5' (If LHA<180°, P=LHA)
A Tan Latitude/ Tan P
A Tan 48° 00' Tan 144° 58.5'
A = 1.584646985 N (A is named opposite to latitude, except when hour angle is between 090° and
270°)
B Tan Declination/ Sin P
B= Tan 024° 18.5' Sin 144° 58.5'
B=0.787011353 N (B is always named same as declination)
C A+B 2.371658338 N (C correction, A+/- B: If A and B have same name- add, If different name-
subtract)
Tan Azimuth = 1/ (C X Cos Latitude)
Tan Azimuth = 0.6301399
Azimuth = N 32.2° W (Azimuth takes combined name of C correction and Hour Angle- If LHA is
between 0° and 180°, it is named "west", if LHA is between 180° and 360°, it is named "east")
True Azimuth= 327.8°
Compass Azimuth=327.0°
Compass Error = 0.8° East
Variation = 4.0° East
Deviation
GlobalMET
3.2° West
Deck Cadet Shipboard Activity Workbook - used in conjunction with the Deck Cadet SSTP Record Book
26
Transcribed Image Text:Task number: A1.1, A1.7 Topic: Celestial Navigation, Compass - Magnetic and Gyro Activ Determine compass error (magnetic and gyro) using azimuth choosing a suitable celestial body (Sun/ Stars/ Planets/ Moon). Apply variation to find the deviation of the magnetic compass. Minimum number of times that activity should be recorded: 6 (2 each phase) Sample calculation (Azimuth- Planets): On 06th May 2006 at 22h20m 10s UTC, a vessel in position 48°00'N 050°00'E observed Mars bearing 327° by compass. Find the compass error. If variation was 4.0° East, calculate the deviation. GHA Mars (06d 22h): Increment (20m 10s): 089° 55.7' 005° 02.5' v (0.9): (+) 00.3' GHA Mars: 094° 58.5' Longitude (E): (+) 050° 00.0' (plus- since longitude is easterly) LHA Mars: 144° 58.5' Declination (06d 22h): d (0.2): N 024° 18.6' (-) 00.1' Declination Mars: N 024° 18.5' P=144° 58.5' (If LHA<180°, P=LHA) A Tan Latitude/ Tan P A Tan 48° 00' Tan 144° 58.5' A = 1.584646985 N (A is named opposite to latitude, except when hour angle is between 090° and 270°) B Tan Declination/ Sin P B= Tan 024° 18.5' Sin 144° 58.5' B=0.787011353 N (B is always named same as declination) C A+B 2.371658338 N (C correction, A+/- B: If A and B have same name- add, If different name- subtract) Tan Azimuth = 1/ (C X Cos Latitude) Tan Azimuth = 0.6301399 Azimuth = N 32.2° W (Azimuth takes combined name of C correction and Hour Angle- If LHA is between 0° and 180°, it is named "west", if LHA is between 180° and 360°, it is named "east") True Azimuth= 327.8° Compass Azimuth=327.0° Compass Error = 0.8° East Variation = 4.0° East Deviation GlobalMET 3.2° West Deck Cadet Shipboard Activity Workbook - used in conjunction with the Deck Cadet SSTP Record Book 26
Activ
Determine compass error using amplitude (Sun).
Minimum number of times that activity should be performed: 3 (1 each phase)
Sample calculation (Amplitude- Sun):
On 07th May 2006 at Sunset, a vessel in position 10°00'N 010°00'W observed the Sun bearing 288°
by compass. Find the compass error.
LMT Sunset:
LIT:
(+) 00d
07d 18h
00h
13m
40m
UTC Sunset:
07d
18h
53m
(added- since longitude is westerly)
Declination (07d 18h):
N 016° 55.5'
d (0.7):
(+)
00.6'
Declination Sun:
N 016° 56.1'
Sin Amplitude = Sin Declination/Cos Latitude
= Sin 016°56.1'/ Cos 10°00'
= 0.295780189
Amplitude=W17.2N
(The prefix of amplitude is named easterly if body is rising,
and westerly if body is setting. The suffix is named same
as declination)
True Bearing=287.2°
Compass Bearing= 288.0°
Compass Error = 0.8° West
Transcribed Image Text:Activ Determine compass error using amplitude (Sun). Minimum number of times that activity should be performed: 3 (1 each phase) Sample calculation (Amplitude- Sun): On 07th May 2006 at Sunset, a vessel in position 10°00'N 010°00'W observed the Sun bearing 288° by compass. Find the compass error. LMT Sunset: LIT: (+) 00d 07d 18h 00h 13m 40m UTC Sunset: 07d 18h 53m (added- since longitude is westerly) Declination (07d 18h): N 016° 55.5' d (0.7): (+) 00.6' Declination Sun: N 016° 56.1' Sin Amplitude = Sin Declination/Cos Latitude = Sin 016°56.1'/ Cos 10°00' = 0.295780189 Amplitude=W17.2N (The prefix of amplitude is named easterly if body is rising, and westerly if body is setting. The suffix is named same as declination) True Bearing=287.2° Compass Bearing= 288.0° Compass Error = 0.8° West
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