Chapter 6.3, Problem 20PP

To determine

To calculate: Electrical energy used by the refrigerator.

Answer to Problem 20PP

Electrical energy used by the refrigerator is $\underset{\_}{7\text{ kWh}}$ .

Explanation of Solution

Given:

Time = $\text{10}\text{.0 h}$

Power = $700\text{ W}$

Formula used:

Electrical energy is given by,

  $E=Pt$

where $P$ is power and $t$ is time.

Calculation:

Electrical energy is calculated as:

  $\begin{array}{l}E=Pt\\ =(700\text{ W})(10.0\text{ h})\\ =\left(\frac{700}{1000}\text{ kW}\right)(10.0\text{ h})\\ =(0.7\text{ kW})(10.0\text{ h})\\ =7\text{ kWh}\end{array}$

Conclusion:

Electrical energy used by the refrigerator is $\underset{\_}{7\text{ kWh}}$ .