Explanation Consider the table of the six basic solutions to the e-system, 2 x 1 + 3 x 2 + s 1 = 24 4 x 1 + 3 x 2 + s 2 = 36

Finite Mathematics for Business, Economics, Life Sciences and Social Sciences Plus NEW MyLab Math with Pearson eText -- Access Card Package (13th Edition)

13th Edition

ISBN: 9780321947628

Author: Raymond A. Barnett, Michael R. Ziegler, Karl E. Byleen

Publisher: PEARSON

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Chapter 6.1, Problem 22E

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The variables in the basic solution (F), which are basic from the given table of the six basic solutions to the e-system, 2x1+3x2+s1 =244x1+3x2+s2 =36.

x1x2s1s2A002436B08012C012−120D1200−12E9060F6400

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Chapter 6.1, Problem 21E

Chapter 6.1, Problem 23E

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Chapter 6 Solutions

Finite Mathematics for Business, Economics, Life Sciences and Social Sciences Plus NEW MyLab Math with Pearson eText -- Access Card Package (13th Edition)

Ch. 6.1 - The following linear programming problem has only...Ch. 6.1 - Find an example of a standard maximization problem...Ch. 6.1 - Use the table method to solve the following linear...Ch. 6.1 - Refer to Example 1. Find the basic solution for...Ch. 6.1 - Construct the table of basic solutions and use it...Ch. 6.1 - Construct the table of basic solutions and use it...Ch. 6.1 - Refer to Table 5. For the basic solution...Ch. 6.1 - Prob. 1E Ch. 6.1 - Prob. 2E Ch. 6.1 - Prob. 3E

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The variables in the basic solution (F), which are basic from the given table of the six basic solutions to the e-system, 2 x 1 + 3 x 2 + s 1 = 24 4 x 1 + 3 x 2 + s 2 = 36 . x 1 x 2 s 1 s 2 A 0 0 24 36 B 0 8 0 12 C 0 12 − 12 0 D 12 0 0 − 12 E 9 0 6 0 F 6 4 0 0

Solution Summary: The author explains the basic variables in the table of the six basic solutions to the e-system.

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The variables in the basic solution (F), which are basic from the given table of the six basic solutions to the e-system, 2x1+3x2+s1 =244x1+3x2+s2 =36.

x1x2s1s2A002436B08012C012−120D1200−12E9060F6400

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Chapter 6 Solutions

The variables in the basic solution (F), which are basic from the given table of the six basic solutions to the e-system, 2 x 1 + 3 x 2 + s 1 = 24 4 x 1 + 3 x 2 + s 2 = 36 . x 1 x 2 s 1 s 2 A 0 0 24 36 B 0 8 0 12 C 0 12 − 12 0 D 12 0 0 − 12 E 9 0 6 0 F 6 4 0 0

Solution Summary: The author explains the basic variables in the table of the six basic solutions to the e-system.

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The variables in the basic solution (F), which are basic from the given table of the six basic solutions to the e-system, 2x1+3x2+s1 =244x1+3x2+s2 =36. x1x2s1s2A002436B08012C012−120D1200−12E9060F6400

Want to see the full answer?

Chapter 6 Solutions

The variables in the basic solution (F), which are basic from the given table of the six basic solutions to the e-system, 2x1+3x2+s1 =244x1+3x2+s2 =36.

x1x2s1s2A002436B08012C012−120D1200−12E9060F6400