Problems 31-40 refer to the partially completed table below of the 10 basic solutions to the e-system x 1 + x 2 + s 1 = 24 2 x 1 + x 2 + s 2 = 30 4 x 1 + x 2 + s 3 = 48 x 1 x 2 s 1 s 2 s 3 A 0 0 24 30 48 B 0 24 0 6 24 C 0 30 − 6 0 18 D 0 48 − 24 − 18 0 E 24 0 0 − 18 − 48 F 15 0 9 0 − 12 G 0 0 H 0 0 I 0 0 J 0 0 In the basic solution C , which variables are basic?
Problems 31-40 refer to the partially completed table below of the 10 basic solutions to the e-system x 1 + x 2 + s 1 = 24 2 x 1 + x 2 + s 2 = 30 4 x 1 + x 2 + s 3 = 48 x 1 x 2 s 1 s 2 s 3 A 0 0 24 30 48 B 0 24 0 6 24 C 0 30 − 6 0 18 D 0 48 − 24 − 18 0 E 24 0 0 − 18 − 48 F 15 0 9 0 − 12 G 0 0 H 0 0 I 0 0 J 0 0 In the basic solution C , which variables are basic?
Solution Summary: The author explains the basic variables of the e-system (C).
Problems 31-40 refer to the partially completed table below of the
10
basic solutions to the e-system
x
1
+
x
2
+
s
1
=
24
2
x
1
+
x
2
+
s
2
=
30
4
x
1
+
x
2
+
s
3
=
48
x
1
x
2
s
1
s
2
s
3
A
0
0
24
30
48
B
0
24
0
6
24
C
0
30
−
6
0
18
D
0
48
−
24
−
18
0
E
24
0
0
−
18
−
48
F
15
0
9
0
−
12
G
0
0
H
0
0
I
0
0
J
0
0
In the basic solution
C
, which variables are basic?
3. A basket contains 2 orange, 3 white, 4 yellow, 5 pink, and 6 purple flowers. If a flower
Chapter 6 Solutions
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