(a)
Interpretation:
The two
Concept introduction:
Nucleophile: Nucleophiles are electron rich compounds which donates electrons to electrophilic compounds which results in bond formation.
Nucleophilic nature depends on the negative charge present in the molecule, the solvent in which it present and the electronegativity of the atom.
Electrophile: Electrophiles are electron deficient compounds which accepts electrons from nucleophiles that results in bond formation.
Addition Reaction: It is defined as chemical reaction in which two given molecules combines and forms product. The types of addition reactions are electrophilic addition, nucleophilic addition, free radical additions and cycloadditions. Generally, compounds with carbon-hetero atom bonds favors addition reaction.
In addition reaction of alkenes when two substituents are placed on same side of
Acid Catalyzed Hydration Reaction: The reaction involves breaking of phi bonds between carbon-carbon multiple bonds and addition of alcohol to more substituted position of carbon in the molecule.
First step is the acid donates proton to the alkene which leads to the formation of more stable carbo cation.
Then, the water is added to the given alkene through acid catalyzed reaction where the water gets added to the carbo cation finally, the removal of one proton from oxonium ion (oxygen with one positive charge) using water results in the formation of product.
(b)
Interpretation:
The products formed in presence of
Concept introduction:
Addition Reaction: It is defined as chemical reaction in which two given molecules combines and forms product. The types of addition reactions are electrophilic addition, nucleophilic addition, free radical additions and cycloadditions. Generally, compounds with carbon-hetero atom bonds favors addition reaction.
In addition reaction of alkenes when two substituents are placed on same side of
Acid Catalyzed Hydration Reaction: The reaction involves breaking of phi bonds between carbon-carbon multiple bonds and addition of alcohol to more substituted position of carbon in the molecule.
First step is the acid donates proton to the alkene which leads to the formation of more stable carbo cation.
Then, the water is added to the given alkene through acid catalyzed reaction where the water gets added to the carbo cation finally, the removal of one proton from oxonium ion (oxygen with one positive charge) using water results in the formation of product.
Carbocation: it is carbon ion that bears a positive charge on it.
Carbocation stability order:
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Chapter 6 Solutions
Organic Chemistry; Modified MasteringChemistry with Pearson eText -- ValuePack Access Card; Study Guide and Student Solutions Manual for Organic Chemistry, Books a la Carte Edition (7th Edition)
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- Check the box under each structure in the table that is an enantiomer of the molecule shown below. If none of them are, check the none of the above box under the table. Molecule 1 Molecule 2 Molecule 3 ----||| Molecule 4 Molecule 5 Molecule 6 none of the above mm..arrow_forwardShow work. don't give Ai generated solutionarrow_forwardCheck the box under each structure in the table that is an enantiomer of the molecule shown below. If none of them are, check the none of the above box under the table. Molecule 1 Molecule 2 Molecule 3 ----||| Molecule 4 Molecule 5 Molecule 6 none of the above mm..arrow_forward
- Use the vapor-liquid equilibrium data at 1.0 atm. for methanol-water (Table 2-8 ) for the following: If the methanol vapor mole fraction is 0.600, what is the methanol liquid mole fraction? Is there an azeotrope in the methanol-water system at a pressure of 1.0 atmospheres? If water liquid mole fraction is 0.350, what is the water vapor mole fraction? What are the K values of methanol and of water at a methanol mole fraction in the liquid of 0.200? What is the relative volatility αM-W at a methanol mole fraction in the liquid of 0.200?arrow_forwardCheck the box under each structure in the table that is an enantiomer of the molecule shown below. If none of them are, check the none of the above box under the table. || |II***** Molecule 1 | Molecule 4 none of the above Molecule 2 Molecule 3 Х mm... C ---||| *** Molecule 5 Molecule 6arrow_forwardis SiBr4 Silicon (IV) tetra Bromine? is KClO2 potassium dihypochlorite ?arrow_forward
- "יוון HO" Br CI Check the box under each structure in the table that is an enantiomer of the molecule shown below. If none of them are, check the none of the above box under the table. Molecule 1 Molecule 2 Molecule 3 Br Br Br HO OH H CI OH ✓ Molecule 4 Molecule 5 Molecule 6 CI Br יייון H Br OH OH CI Br ☐ none of the above × Garrow_forwardUS2 Would this be Uranium (II) diSulfide?arrow_forwardnomenclature for PU(SO4)3arrow_forward
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