Chapter 6, Problem 6.98P

Interpretation Introduction

Interpretation:

Determine the heat of vaporization at the normal boiling point for Benzene and compare the results with table B.2 of Appendix B using given equations.

Concept Introduction:

From preceding problem, the heat of vaporization at the normal boiling point is calculated as:

  $\frac{d\ln P_r{}^{sat}}{d{T}_r}=\frac{\widehat{\Delta H^{lv}}}{T_r{}^2\Delta Z^{lv}}$

Where

  $\widehat{\Delta H^{lv}}=\frac{\Delta H^{lv}}{R{T}_C}$

Where $\Delta H^{lv}$ is the heat of vaporization at the normal boiling point.